Ch11 Verified Test Bank Bivariate Correlation And Regression - Statistics for Criminology 1e | Test Bank Cooper by Jonathon A. Cooper. DOCX document preview.

Ch11 Verified Test Bank Bivariate Correlation And Regression

Chapter 11: Bivariate Correlation and Regression

  1. To learn about the accuracy of a relationship between two variables (continuous), as well as its strength and direction, the most appropriate statistical test to run is
    1. ANOVA.
    2. Regression.
    3. Chi square.
    4. Correlation.
  2. To predict a certain outcome having detailed knowledge about the independent variable, which is impacting the dependent variable, the most appropriate statistical test to run is
    1. ANOVA.
    2. Regression.
    3. Chi square.
    4. Correlation.
  3. Many formulas utilized in statistics are complex. However, one basic formula used in regression is a classic algebraic equation: y = a + bx. Explain the variables within this formula.
  4. Assume you have computed b = 6. Interpret your result in words.
  5. To warm up, let us start with a problem that has a “perfect” regression line. Assume that the state prison wants to encourage prisoners to get involved in education. Thus, the prison administration offers that for every hour spent on education, inmates receive 5 additional minutes in the prison yard.
    1. Compute beta and interpret your finding.
    2. Compute the constant (y intercept or a) and interpret your finding.

 

x

y

 

0

0

 

1

5

 

2

10

 

3

15

 

4

20

 

5

25

 

6

30

 

7

35

 

8

40

 

9

45

 

10

50

Totals

Means

    1. Assume that John (inmate) has studied 17 hours in the previous week; how many minutes of additional yard time did he earn? Use the classic algebraic equation (y = a + bx) to calculate the amount of minutes earned and interpret your result.
    2. Next, you want to predict the total time an inmate is allowed to spend in the yard (weekly allowance + additional time earned). The weekly allowance regarding yard time is (without additional time earned) 630 minutes (10.5 hours).

 

x

y

 

0

630

 

1

635

 

2

640

 

3

645

 

4

650

 

5

655

 

6

660

 

7

665

 

8

670

 

9

675

 

10

680

Totals

 

 

Means

 

 

      1. Compute beta.
      2. Compute the constant (a or y-intercept).
      3. How many minutes (total) is John allowed to spend in the prison yard if he has studied for 21 hours? Use the classic algebraic equation (y = a + bx).
  1. Academic literature found evidence that there is a relationship between temperature and the frequency of the occurrence of violent crimes. Utilizing data derived from the local police department (number of violent crimes/month/100 inhabitants) and meteorological data (average temperature/month), you want to determine the relationship between temperature (IV) and the frequency of violent crime (DV). Find the distribution of both variables in the table below.
    1. Use a spreadsheet program to create a scatterplot or draw it by hand. Describe what you see.
    2. Compute beta (b) and interpret your result.
    3. Compute the constant (a) and interpret your result.
    4. Assume you want to predict the frequency of violent crimes in a month with an average temperature of 90.5 degrees Fahrenheit. Compute y.

Case/month

temperature

No. of violent crimes/100 inhabitants

1

41.5

5

2

44

5

3

47

7

4

51

8

5

56.5

7

6

75

8

7

82.5

10

8

84.1

9

9

71.4

6

10

59.2

7

11

45.6

2

12

39.4

4

Totals

 

 

Means

 

 


  1. Using the example from problem 2:
    1. State your null and your alternative hypotheses.
    2. Determine the strength and direction of the relationship by computing Pearson’s r. Interpret your results.
    3. Compute r2 and interpret your result.
  2. You are interested in the relationship between the visual consumption of crime shows (average per day in hours) and levels of fear of crime (on a scale of 0–30). You have asked a random sample of 14 individuals (random digit dialing) how many hours they watch TV crime shows (per week) and about their level of fear of crime on a scale from 1 to 30. You select an alpha level of 0.05. Because you are uncertain about the direction of the relationship, you choose to utilize two-tailed t values.
    1. State your null and alternative hypotheses.
    2. Utilizing the data from the table presented below:
      1. Compute beta (b). Interpret your result.
      2. Compute the constant (a) and interpret your result.
      3. Determine the strength and direction of the relationship by computing Pearson’s r. Interpret your result.
      4. Compute r2 and interpret your result.
      5. Compute the prediction error you could possibly have knowing nothing about the distribution of the independent variable (hours of crime shows watched).
      6. Compute the unexplained variance.
      7. Compute the explained variance.
    3. Make a decision rule to determine significance.
    4. Make a decision and interpret your results.
    5. Compute the standard error of estimate.

Case

1

2

3

4

5

6

7

8

9

10

11

12

13

14

  1. It is debated whether IQ scores influence criminal behavior (either directly or indirectly). It is argued that the majority of criminals have an IQ that lies 8 points below (92) the average IQ (100). You draw a random sample of 15 individuals of age 18+, assess the IQ of participants, and ask them about their criminal history (number of offenses committed, not including minor traffic violations). You select an alpha of 0.05. The results of your assessment are to be found in the table presented below.
    1. State your null and alternative hypotheses.
    2. State your decision rule to determine statistical significance.
    3. Utilizing the data from the table presented below:
      1. Compute beta (b).
      2. Compute the constant (a).
      3. Determine the strength and direction of the relationship by computing Pearson’s r.
      4. Compute r2.
      5. Compute the prediction error you could possibly have if you know nothing about the distribution of the independent variable (IQ score).
      6. Compute the unexplained variance.
      7. Compute the explained variance.
    4. Make a decision.
    5. Compute the standard error of estimate.
    6. INTERPRET ALL YOUR RESULTS.

Case

IQ (x)

No. of offenses (y)

1

90

4

2

110

1

3

89

4

4

95

3

5

92

5

6

91

4

7

102

0

8

99

2

9

76

3

10

99

1

11

92

6

12

98

1

13

111

1

14

100

2

15

93

6

 

x

y

 

0

0

 

1

5

 

2

10

 

3

15

 

4

20

 

5

25

 

6

30

 

7

35

 

8

40

 

9

45

 

10

50

Totals

55

275

Means

5

25

 

x

y

 

0

630

 

1

635

 

2

640

 

3

645

 

4

650

 

5

655

 

6

660

 

7

665

 

8

670

 

9

675

 

10

680

Totals

55

7205

Means

5

655

Case/month

temperature

No. of violent crimes/100 inhabitants

1

41.5

5

2

44

5

3

47

7

4

51

8

5

56.5

7

6

75

8

7

82.5

10

8

84.1

9

9

71.4

6

10

59.2

7

11

45.6

2

12

39.4

4

Totals

697.2

78

Means

58.1

6.5

Case/month

x

y

x2

y2

xy

1

41.5

5

1,722.25

25

207.5

2

44

5

1936

25

220

3

47

7

2209

49

329

4

51

8

2601

64

408

5

56.5

7

3,192.25

49

395.5

6

75

8

5625

64

600

7

82.5

10

6,806.25

100

825

8

84.1

9

7,072.81

81

756.9

9

71.4

6

5,097.96

36

428.4

10

59.2

7

3,504.64

49

414.4

11

45.6

2

2,079.36

4

91.2

12

39.4

4

1,552.36

16

157.6

Totals

697.2

78

43,398.88

562

4,833.5

Case

x

y

x2

y2

xy

1

0

12

0

144

0

2

3

11

9

121

33

3

2

11

4

121

22

4

9

18

81

324

162

5

4

19

16

361

76

6

5

20

25

400

100

7

7

11

49

121

77

8

9

16

81

256

144

9

8

18

64

324

144

10

9

25

81

625

225

11

11

24

121

576

264

12

1

9

1

81

9

13

3

11

9

121

33

14

2

11

4

121

22

Totals

73

216

545

3,696

1,311

 

x

y

 

Hours of crime shows

Fear of crime

 

0

12

 

3

11

 

2

11

 

9

18

 

4

19

 

5

20

 

7

11

 

9

16

 

8

18

 

9

25

 

11

24

 

1

9

 

3

11

 

2

11

Totals

73

216

Means

5.214286

15.42857

Case

x

y

1

0

12

–3.4286

11.7553

2

3

11

–4.4286

19.6125

3

2

11

–4.4286

19.6125

4

9

18

2.5714

6.612098

5

4

19

3.5714

12.7549

6

5

20

4.5714

20.8977

7

7

11

–4.4286

19.6125

8

9

16

0.5714

0.326498

9

8

18

2.5714

6.612098

10

9

25

9.5714

91.6117

11

11

24

8.5714

73.4689

12

1

9

–6.4286

41.3269

13

3

11

–4.4286

19.6125

14

2

11

–4.4286

19.6125

Totals

73

216

–0.0004

363.4286

case

x

y

y′

y – y′

(y – y′)2

1

0

12

9.5677

2.4323

5.916083

2

3

11

12.9394

1.9394

3.761272

3

2

11

11.8155

0.8155

0.66504

4

9

18

19.6828

1.6828

2.831816

5

4

19

14.0633

4.9367

24.37101

6

5

20

15.1872

4.8128

23.16304

7

7

11

17.435

6.435

41.40923

8

9

16

19.6828

3.6828

13.56302

9

8

18

18.5589

0.5589

0.312369

10

9

25

19.6828

5.3172

28.27262

11

11

24

21.9306

2.0694

4.282416

12

1

9

10.6916

1.6916

2.861511

13

3

11

12.9394

1.9394

3.761272

14

2

11

11.8155

0.8155

0.66504

Totals

73

216

 

 

155.8357

Case

x

y

x2

y2

xy

1

90

4

8,100

16

360

2

110

1

12,100

1

110

3

89

4

7,921

16

356

4

95

3

9,025

9

285

5

92

5

8,464

25

460

6

91

4

8,281

16

364

7

102

0

10,404

0

0

8

99

2

9,801

4

198

9

76

3

5,776

9

228

10

99

1

9,801

1

99

11

92

6

8,464

36

552

12

98

1

9,604

1

98

13

111

1

12,321

1

111

14

100

2

10,000

4

200

15

93

6

8,649

36

558

Totals

1,437

43

138,711

175

3,979

 

Case

IQ (x)

No. of offenses (y)

 

1

90

4

 

2

110

1

 

3

89

4

 

4

95

3

 

5

92

5

 

6

91

4

 

7

102

0

 

8

99

2

 

9

76

3

 

10

99

1

 

11

92

6

 

12

98

1

 

13

111

1

 

14

100

2

 

15

93

6

Totals

 

1,437

43

Means

 

95.8

2.866667

Standard deviations

 

8.6453951

1.9223

Case

IQ (x)

No. of offenses (y)

1

90

4

1.1333

1.284369

2

110

1

–1.8667

3.484569

3

89

4

1.1333

1.284369

4

95

3

0.1333

0.017769

5

92

5

2.1333

4.550969

6

91

4

1.1333

1.284369

7

102

0

–2.8667

8.217969

8

99

2

–0.8667

0.751169

9

76

3

0.1333

0.017769

10

99

1

–1.8667

3.484569

11

92

6

3.1333

9.817569

12

98

1

–1.8667

3.484569

13

111

1

–1.8667

3.484569

14

100

2

–0.8667

0.751169

15

93

6

3.1333

9.817569

Totals

1,437

43

–0.0005

51.73333

Case

IQ (x)

No. of offenses (y)

y′

yy′

(yy′)2

1

90

4

3.643

0.357

0.127449

2

110

1

0.959

0.041

0.001681

3

89

4

3.7772

0.2228

0.04964

4

95

3

2.972

0.028

0.000784

5

92

5

3.3746

1.6254

2.641925

6

91

4

3.5088

0.4912

0.241277

7

102

0

2.0326

–2.0326

4.131463

8

99

2

2.4352

–0.4352

0.189399

9

76

3

5.5218

–2.5218

6.359475

10

99

1

2.4352

–1.4352

2.059799

11

92

6

3.3746

2.6254

6.892725

12

98

1

2.5694

–1.5694

2.463016

13

111

1

0.8248

0.1752

0.030695

14

100

2

2.301

-0.301

0.090601

15

93

6

3.2404

2.7596

7.615392

Totals

1,437

43

 

 

32.89532

Document Information

Document Type:
DOCX
Chapter Number:
11
Created Date:
Aug 21, 2025
Chapter Name:
Chapter 11 Bivariate Correlation And Regression
Author:
Jonathon A. Cooper

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