Verified Test Bank Ch8 Estimation Of The Mean And Proportion

Introductory Statistics, 10e (Mann)

Chapter 8 Estimation of the Mean and Proportion

8.1 Estimation, Point Estimate, and Interval Estimate

1) Estimation is a procedure by which we assign a numerical value or numerical values to the:

A) population parameter based on the information collected from a sample

B) sample statistic based on the information collected from a sample

C) population parameter based on the information collected from a population

D) sample statistic based on the information collected from a population

Diff: 1

LO: 8.1.0 Demonstrate an understanding of estimation.

Section: 8.1 Estimation, Point Estimate, and Interval Estimate

Question Title: Chapter 08, Testbank Question 001

2) The values assigned to a population parameter based on the value(s) of a sample statistic are called:

A) the probabilities

B) the probability distribution

C) a sampling distribution

D) estimate(s)

Diff: 1

LO: 8.1.0 Demonstrate an understanding of estimation.

Section: 8.1 Estimation, Point Estimate, and Interval Estimate

Question Title: Chapter 08, Testbank Question 002

3) The sample statistic used to estimate a population parameter is called a(n):

A) random variable

B) qualitative variable

C) estimator

D) parameter

Diff: 1

LO: 8.1.0 Demonstrate an understanding of estimation.

Section: 8.1 Estimation, Point Estimate, and Interval Estimate

Question Title: Chapter 08, Testbank Question 003

4) The (single) value of a sample statistic that we assign to the population parameter is called a:

A) single estimate

B) unique estimate

C) point estimate

D) singular estimate

Diff: 1

LO: 8.1.0 Demonstrate an understanding of estimation.

Section: 8.1 Estimation, Point Estimate, and Interval Estimate

Question Title: Chapter 08, Testbank Question 004

5) The confidence level of an interval estimate is denoted by:

A) α

B) (1 - α) × 100%

C) β

D) (1 - β) × 100%

Diff: 1

LO: 8.1.0 Demonstrate an understanding of estimation.

Section: 8.1 Estimation, Point Estimate, and Interval Estimate

Question Title: Chapter 08, Testbank Question 005

6) For most distributions, we can use the normal distribution to make a confidence interval for a population mean provided that the population standard deviation σ is known and the sample size is:

A) greater than or equal to 10

B) less than 25

C) greater than or equal to 30

D) equal to 20

Diff: 1

LO: 8.1.0 Demonstrate an understanding of estimation.

Section: 8.1 Estimation, Point Estimate, and Interval Estimate

Question Title: Chapter 08, Testbank Question 006

7) Which of the following is not part of the procedure for estimating the value of a population parameter?

A) Selecting a sample

B) Collecting the required information from the members of the sample

C) Calculating the value of the sample statistic

D) Calculating the exact value of the corresponding population parameter

Diff: 1

LO: 8.1.0 Demonstrate an understanding of estimation.

Section: 8.1 Estimation, Point Estimate, and Interval Estimate

Question Title: Chapter 08, Testbank Question 007

8) You are estimating the mean waiting time in line at a particular fast-food restaurant to place an order. You ask 30 customers, at varying times of the day, how long they waited in line before placing their order. You then take the average of these values and use this average to estimate the mean waiting time for all customers. The average of the 30 values is an example of a(n):

A) Chebyshev estimate

B) point estimate

C) interval estimate

D) confidence estimate

Diff: 1

LO: 8.1.0 Demonstrate an understanding of estimation.

Section: 8.1 Estimation, Point Estimate, and Interval Estimate

Question Title: Chapter 08, Testbank Question 008

8.2 Estimation of a Population Mean: σ Known

1) The margin of error for the population mean, assuming σ is known, is:

A) E = zσ

B) E = zt

C) E = σ

D) E = z

Diff: 2

LO: 8.2.0 Construct a confidence interval for the population mean when the population standard deviation is known.

Section: 8.2 Estimation of a Population Mean: σ Known

Question Title: Chapter 08, Testbank Question 009

2) The z value for a 90% confidence interval for the population mean with σ known is:

A) 2.05

B) 1.645

C) 2.17

D) 1.60

Diff: 1

LO: 8.2.0 Construct a confidence interval for the population mean when the population standard deviation is known.

Section: 8.2 Estimation of a Population Mean: σ Known

Question Title: Chapter 08, Testbank Question 010

3) The z value for a 85% confidence interval for the population mean with σ known is:

A) 1.96

B) 2.33

C) 1.44

D) 2.58

Diff: 1

LO: 8.2.0 Construct a confidence interval for the population mean when the population standard deviation is known.

Section: 8.2 Estimation of a Population Mean: σ Known

Question Title: Chapter 08, Testbank Question 011

4) The width of a confidence interval depends on the size of the:

A) population mean

B) margin of error

C) sample mean

D) none of these

Diff: 2

LO: 8.2.0 Construct a confidence interval for the population mean when the population standard deviation is known.

Section: 8.2 Estimation of a Population Mean: σ Known

Question Title: Chapter 08, Testbank Question 012

5) You can decrease the width of a confidence interval by:

A) decreasing the confidence level or decreasing the sample size

B) increasing the confidence level or decreasing the sample size

C) decreasing the confidence level or increasing the sample size

D) increasing the confidence level or increasing the sample size

Diff: 2

LO: 8.2.0 Construct a confidence interval for the population mean when the population standard deviation is known.

Section: 8.2 Estimation of a Population Mean: σ Known

Question Title: Chapter 08, Testbank Question 013

6) To decrease the width of a confidence interval, we should always prefer to:

A) lower the confidence level

B) increase the confidence level

C) increase the sample size

D) decrease the sample size

Diff: 2

LO: 8.2.0 Construct a confidence interval for the population mean when the population standard deviation is known.

Section: 8.2 Estimation of a Population Mean: σ Known

Question Title: Chapter 08, Testbank Question 014

7) A sample of size 106 from a population having standard deviation produced a mean of 43. The 99% confidence interval for the population mean (rounded to two decimal places) is:

A) 40.74 to 45.26

B) 40.96 to 45.04

C) 41.29 to 44.71

D) 41.49 to 44.51

Diff: 2

LO: 8.2.0 Construct a confidence interval for the population mean when the population standard deviation is known.

Section: 8.2 Estimation of a Population Mean: σ Known

Question Title: Chapter 08, Testbank Question 015

8) A sample of size 61 from a population having standard deviation produced a mean of 265.00. The 95% confidence interval for the population mean (rounded to two decimal places) is:

A) 253.71 to 276.29

B) 251.58 to 278.42

C) 250.13 to 279.87

D) 255.04 to 274.96

Diff: 2

LO: 8.2.0 Construct a confidence interval for the population mean when the population standard deviation is known.

Section: 8.2 Estimation of a Population Mean: σ Known

Question Title: Chapter 08, Testbank Question 016

9) A random sample of 93 customers, who visited a department store, spent an average of $76 at this store. Suppose the standard deviation of expenditures at this store is The 98% confidence interval for the population mean (rounded to two decimal places) is:

A) 71.17 to 80.83

B) 70.65 to 81.35

C) 71.94 to 80.06

D) 72.41 to 79.59

Diff: 2

LO: 8.2.0 Construct a confidence interval for the population mean when the population standard deviation is known.

Section: 8.2 Estimation of a Population Mean: σ Known

Question Title: Chapter 08, Testbank Question 017

10) The mean IQ score of a sample of 61 students selected from a high school is 87. Suppose the standard deviation of IQ's at this school is σ = 8.4. The 99% confidence interval for the population mean (rounded to two decimal places) is:

A) 95.47 to 100.53

B) 95.71 to 100.29

C) 96.08 to 99.92

D) 96.30 to 99.70

Diff: 2

LO: 8.2.0 Construct a confidence interval for the population mean when the population standard deviation is known.

Section: 8.2 Estimation of a Population Mean: σ Known

Question Title: Chapter 08, Testbank Question 018

11) The mean federal income tax paid last year by a random sample of 37 persons selected from a city was $4278. Suppose the standard deviation of tax paid in this city is The 95% confidence interval for the population mean (rounded to two decimal places) is:

A) 4040.52 to 4515.48

B) 3995.69 to 4560.31

C) 3965.40 to 4590.60

D) 4068.51 to 4487.49

Diff: 2

LO: 8.2.0 Construct a confidence interval for the population mean when the population standard deviation is known.

Section: 8.2 Estimation of a Population Mean: σ Known

Question Title: Chapter 08, Testbank Question 019

12) A researcher wants to make a 99% confidence interval for a population mean. She wants the margin of error to be within 4.8 of the population mean. The population standard deviation is 18.20. The sample size that will yield a margin of error within 4.8 of the population mean is:

Diff: 2

LO: 8.2.0 Construct a confidence interval for the population mean when the population standard deviation is known.

Section: 8.2 Estimation of a Population Mean: σ Known

Question Title: Chapter 08, Testbank Question 020

13) A researcher wants to make a 95% confidence interval for a population mean. She wants the margin of error to be within 2.3 of the population mean. The population standard deviation is 9.55. The sample size that will yield a margin of error within 2.3 of the population mean is:

Diff: 2

LO: 8.2.0 Construct a confidence interval for the population mean when the population standard deviation is known.

Section: 8.2 Estimation of a Population Mean: σ Known

Question Title: Chapter 08, Testbank Question 021

14) A researcher wants to estimate the mean age of all Business Week readers at a 99% confidence level. She wants the margin of error to be within 2.7 years of the population mean. The standard deviation of ages of all Business Week readers is 8.22 years. The sample size that will yield a margin of error within 2.7 of the population mean is:

Diff: 2

LO: 8.2.0 Construct a confidence interval for the population mean when the population standard deviation is known.

Section: 8.2 Estimation of a Population Mean: σ Known

Question Title: Chapter 08, Testbank Question 022

15) A company wants to estimate the mean net weight of all 32-ounce packages of its Yummy Taste cookies at a 95% confidence level. The margin of error is to be within 0.019 ounces of the population mean. The population standard deviation is 0.100 ounces. The sample size that will yield a margin of error within 0.019 ounces of the population mean is:

Diff: 2

LO: 8.2.0 Construct a confidence interval for the population mean when the population standard deviation is known.

Section: 8.2 Estimation of a Population Mean: σ Known

Question Title: Chapter 08, Testbank Question 023

16) A scientist is estimating the mean lifetime of a newly-discovered insect. From a sample of 95 insects, she finds a sample mean of 41.8 days. Suppose that the population standard deviation of all lifetimes is 2.425 days. What are the boundaries for a 90% confidence interval for the mean lifetime of the insect, rounded to two decimal places?

A) 41.39 to 42.21

B) 41.31 to 42.29

C) 41.22 to 42.38

D) 41.16 to 42.44

Diff: 2

LO: 8.2.0 Construct a confidence interval for the population mean when the population standard deviation is known.

Section: 8.2 Estimation of a Population Mean: σ Known

Question Title: Chapter 08, Testbank Question 024

17) The Eks Survey Company employs 2000 people to conduct telephone surveys. Because many people don't like to answer such surveys, many "hang-ups" (whereby the person hangs up without completing the survey) occur. The owner of Eks wants to determine the mean number of "hang-ups" per employee on a particular day, using 95% confidence. He samples 36 employees, and finds that the mean number of "hang-ups" on that day was 39.5. Suppose that the standard deviation of the number of "hang-ups" for all employees is 20.6. What is the value of the margin of error? (Round to four decimal places.)

Diff: 2

LO: 8.2.0 Construct a confidence interval for the population mean when the population standard deviation is known.

Section: 8.2 Estimation of a Population Mean: σ Known

Question Title: Chapter 08, Testbank Question 025

18) We are using the mean of a sample as a point estimate for the mean of a normal distribution with a standard deviation of 5. The margin of error, with 95% confidence, for this estimate is 0.834. What is the sample size?

Diff: 2

LO: 8.2.0 Construct a confidence interval for the population mean when the population standard deviation is known.

Section: 8.2 Estimation of a Population Mean: σ Known

Question Title: Chapter 08, Testbank Question 026

19) An advisor to the mayor of a large city wants to estimate, within 2.950 minutes, the mean travel time to work for all employees who work within the city limits. He knows that the standard deviation of all travel times is 13.15 minutes. He also wants to achieve a 95% confidence interval. He will poll a random sample of city employees. How many employees should he poll?

Diff: 2

LO: 8.2.0 Construct a confidence interval for the population mean when the population standard deviation is known.

Section: 8.2 Estimation of a Population Mean: σ Known

Question Title: Chapter 08, Testbank Question 027

20) Determine the sample size n that is required for estimating the population mean. The population standard deviation σ and the desired margin of error are specified.

A) 19,871

B) 19,872

C) 19,870

D) 19,873

Diff: 2

LO: 8.2.0 Construct a confidence interval for the population mean when the population standard deviation is known.

Section: 8.2 Estimation of a Population Mean: σ Known

Question Title: Chapter 08, Testbank Question 028

21) The correct formula for the limits of a confidence interval is:

A) ( - z, + z)

B) (z - margin of error, z + margin of error)

C) ( - margin of error, + margin of error)

D) ( × margin of error, × margin of error)

Diff: 1

LO: 8.2.0 Construct a confidence interval for the population mean when the population standard deviation is known.

Section: 8.2 Estimation of a Population Mean: σ Known

Question Title: Chapter 08, Testbank Question 029

22) True or False. The statement: "The 91% confidence interval for the mean is can be interpreted to mean that the probability that the mean lies in the range is 91%.

Diff: 1

LO: 8.2.0 Construct a confidence interval for the population mean when the population standard deviation is known.

Section: 8.2 Estimation of a Population Mean: σ Known

Question Title: Chapter 08, Testbank Question 030

8.3 Estimation of a Population Mean: σ Not Known

1) We use the t distribution to make a confidence interval for the population mean if the population from which the sample is drawn is (approximately) normally distributed, the population standard deviation is unknown, and the sample size is at least:

A) 30

B) 100

C) 50

D) 2

Diff: 1

LO: 8.3.0 Construct a confidence interval for the population mean when the population standard deviation is unknown.

Section: 8.3 Estimation of a Population Mean: σ Not Known

Question Title: Chapter 08, Testbank Question 031

2) When making a confidence interval for the population mean using the t distribution, the degrees of freedom for the t distribution are:

A) n

B) n - 2

C) n + 1

D) n - 1

Diff: 1

LO: 8.3.0 Construct a confidence interval for the population mean when the population standard deviation is unknown.

Section: 8.3 Estimation of a Population Mean: σ Not Known

Question Title: Chapter 08, Testbank Question 032

3) The value of t for 15 degrees of freedom and a 98% confidence interval is:

A) 2.861

B) 2.602

C) -2.602

D) 1.328

Diff: 1

LO: 8.3.0 Construct a confidence interval for the population mean when the population standard deviation is unknown.

Section: 8.3 Estimation of a Population Mean: σ Not Known

Question Title: Chapter 08, Testbank Question 033

4) The value of t for 19 degrees of freedom and a 90% confidence interval is:

A) 1.729

B) -1.729

C) 2.539

D) -2.539

Diff: 1

LO: 8.3.0 Construct a confidence interval for the population mean when the population standard deviation is unknown.

Section: 8.3 Estimation of a Population Mean: σ Not Known

Question Title: Chapter 08, Testbank Question 034

5) A sample of 20 elements produced a mean of 91.4 and a standard deviation of 13.80. Assuming that the population has a normal distribution, the 90% confidence interval for the population mean is:

A) 86.06 to 96.74

B) 86.05 to 96.75

C) 86.08 to 96.72

D) 84.94 to 97.86

Diff: 2

LO: 8.3.0 Construct a confidence interval for the population mean when the population standard deviation is unknown.

Section: 8.3 Estimation of a Population Mean: σ Not Known

Question Title: Chapter 08, Testbank Question 035

6) A sample of 25 elements produced a mean of 127.6 and a standard deviation of 17.23. Assuming that the population has a normal distribution, the 90% confidence interval for the population mean, rounded to two decimal places, is:

A) 121.70 to 133.50

B) 121.00 to 134.20

C) 121.02 to 134.18

D) 119.65 to 135.55

Diff: 2

LO: 8.3.0 Construct a confidence interval for the population mean when the population standard deviation is unknown.

Section: 8.3 Estimation of a Population Mean: σ Not Known

Question Title: Chapter 08, Testbank Question 036

7) A random sample of 23 tourists who visited Hawaii this summer spent an average of $1470.00 on this trip with a standard deviation of $286.00. Assuming that the money spent by all tourists who visit Hawaii has an approximate normal distribution, the 95% confidence interval for the average amount of money spent by all tourists who visit Hawaii, rounded to two decimal places, is:

A) 1346.32 to 1593.68

B) 1336.98 to 1603.02

C) 1337.68 to 1602.32

D) 1309.61 to 1630.39

Diff: 2

LO: 8.3.0 Construct a confidence interval for the population mean when the population standard deviation is unknown.

Section: 8.3 Estimation of a Population Mean: σ Not Known

Question Title: Chapter 08, Testbank Question 037

8) A random sample of 12 life insurance policy holders showed that the mean value of their life insurance policies is $210,000 with a standard deviation of $51,600. Assuming that the values of life insurance policies for all such policy holders are approximately normally distributed, the 99% confidence interval for the mean value of all life insurance policies, rounded to two decimal places, is:

A) 163,734.15 to 256,265.85

B) 162,795.73 to 257,204.27

C) 164,493.83 to 255,506.17

D) 169,513.66 to 250,486.34

Diff: 2

LO: 8.3.0 Construct a confidence interval for the population mean when the population standard deviation is unknown.

Section: 8.3 Estimation of a Population Mean: σ Not Known

Question Title: Chapter 08, Testbank Question 038

9) A random sample of 8 houses selected from a city showed that the mean size of these houses is 1987.0 square feet with a standard deviation of 242.00 square feet. Assuming that the sizes of all houses in this city have an approximate normal distribution, the 90% confidence interval for the mean size of all houses in this city, rounded to two decimal places, is:

A) 1824.86 to 2149.14

B) 1820.76 to 2153.24

C) 1827.86 to 2146.14

D) 1865.93 to 2108.07

Diff: 2

LO: 8.3.0 Construct a confidence interval for the population mean when the population standard deviation is unknown.

Section: 8.3 Estimation of a Population Mean: σ Not Known

Question Title: Chapter 08, Testbank Question 039

10) Which of the following is not an acceptable condition for using the t distribution to make a confidence interval for μ?

A) The population from which the sample is drawn is right-skewed and n ≥ 30

B) The population from which the sample is drawn is approximately normal

C) The population standard deviation is unknown

D) The population standard deviation is known

Diff: 1

LO: 8.3.0 Construct a confidence interval for the population mean when the population standard deviation is unknown.

Section: 8.3 Estimation of a Population Mean: σ Not Known

Question Title: Chapter 08, Testbank Question 040

11) Each employee of a large company is encouraged to contribute, through payroll deduction, to an international charity. Annual contributions per employee follow (approximately) a normal distribution. You take a random sample of 25 employees and find that the sample mean annual contribution per employee is $503 with a standard deviation of $18.60. What are the boundaries for a 99% confidence interval for the population mean, rounded to two decimal places?

A) $492.60 to $513.40

B) $493.40 to $512.60

C) $492.63 to $513.37

D) $493.73 to $512.27

Diff: 2

LO: 8.3.0 Construct a confidence interval for the population mean when the population standard deviation is unknown.

Section: 8.3 Estimation of a Population Mean: σ Not Known

Question Title: Chapter 08, Testbank Question 041

12) An employee of the College Board analyzed the mathematics section of the SAT for 91 students and finds and She reports that a 97% confidence interval for the mean number of correct answers is Does the interval cover the true mean?

Which of the following alternatives is the best answer for the above question?

A) Yes, (29.952, 36.048) covers the true mean.

B) No, (29.952, 36.048) does not cover the true mean.

C) We will never know whether (29.952, 36.048) covers the true mean.

D) The true mean will never be in (29.952, 36.048).

Diff: 2

LO: 8.3.0 Construct a confidence interval for the population mean when the population standard deviation is unknown.

Section: 8.3 Estimation of a Population Mean: σ Not Known

Question Title: Chapter 08, Testbank Question 042

8.4 Estimation of a Population Proportion: Large Samples

1) A random sample of 513 produced a sample proportion of 0.74. The 95% confidence interval for the population proportion, rounded to four decimal places, is:

A) $0.7020 to $0.7780

B) $0.6949 to $0.7851

C) $0.6900 to $0.7900

D) $0.7081 to $0.7719

Diff: 2

LO: 8.4.0 Construct a confidence interval for the population proportion from a large sample.

Section: 8.4 Estimation of a Population Proportion: Large Samples

Question Title: Chapter 08, Testbank Question 043

2) A random sample of 171 produced a sample proportion of 0.44. The 98% confidence interval for the population proportion, rounded to four decimal places, is:

A) $0.3516 to $0.5284

B) $0.3656 to $0.5144

C) $0.3421 to $0.5379

D) $0.3776 to $0.5024

Diff: 2

LO: 8.4.0 Construct a confidence interval for the population proportion from a large sample.

Section: 8.4 Estimation of a Population Proportion: Large Samples

Question Title: Chapter 08, Testbank Question 044

3) A random sample of 1017 adults showed that 33% of them are smokers. Based on this sample, the 90% confidence interval for the proportion of all adults who are smokers, rounded to four decimal places, is:

A) $0.3057 to $0.3543

B) $0.3011 to $0.3589

C) $0.2956 to $0.3644

D) $0.2920 to $0.3680

Diff: 2

LO: 8.4.0 Construct a confidence interval for the population proportion from a large sample.

Section: 8.4 Estimation of a Population Proportion: Large Samples

Question Title: Chapter 08, Testbank Question 045

4) In a random sample of 676 items produced by a machine, the quality control staff found 6.0% to be defective. Based on this sample, the 95% confidence interval for the proportion of defective items in all items produced by this machine, rounded to four decimal places, is:

A) $0.0421 to $0.0779

B) $0.0387 to $0.0813

C) $0.0364 to $0.0836

D) $0.0449 to $0.0751

Diff: 2

LO: 8.4.0 Construct a confidence interval for the population proportion from a large sample.

Section: 8.4 Estimation of a Population Proportion: Large Samples

Question Title: Chapter 08, Testbank Question 046

5) A random sample of 968 families selected from a large city showed that 15.3% of them make $100,000 or more per year. Based on this sample, the 99% confidence interval for the proportion of all families living in this city who make $100,000 or more per year, rounded to four decimal places, is:

A) $0.1231 to $0.1829

B) $0.1260 to $0.1800

C) $0.1303 to $0.1757

D) $0.1339 to $0.1721

Diff: 2

LO: 8.4.0 Construct a confidence interval for the population proportion from a large sample.

Section: 8.4 Estimation of a Population Proportion: Large Samples

Question Title: Chapter 08, Testbank Question 047

6) A random sample of 781 persons showed that 14.2% do not have any health insurance. Based on this sample, the 95% confidence interval for the proportion of all persons who do not have any health insurance, rounded to four decimal places, is:

A) $0.1175 to $0.1665

B) $0.1214 to $0.1626

C) $0.1129 to $0.1711

D) $0.1098 to $0.1742

Diff: 2

LO: 8.4.0 Construct a confidence interval for the population proportion from a large sample.

Section: 8.4 Estimation of a Population Proportion: Large Samples

Question Title: Chapter 08, Testbank Question 048

7) A researcher wants to make a 99% confidence interval for a population proportion. The most conservative estimate of the sample size that would limit the margin of error to be within 0.047 of the population proportion is:

Diff: 2

LO: 8.4.0 Construct a confidence interval for the population proportion from a large sample.

Section: 8.4 Estimation of a Population Proportion: Large Samples

Question Title: Chapter 08, Testbank Question 049

8) A company wants to estimate, at a 95% confidence level, the proportion of all families who own its product. A preliminary sample showed that 32.5% of the families in this sample own this company's product. The sample size that would limit the margin of error to be within 0.031 of the population proportion is:

Diff: 2

LO: 8.4.0 Construct a confidence interval for the population proportion from a large sample.

Section: 8.4 Estimation of a Population Proportion: Large Samples

Question Title: Chapter 08, Testbank Question 050

9) A company wants to estimate, at a 95% confidence level, the proportion of all families who own its product. The most conservative estimate of the sample size that would limit the margin of error to be within 0.036 of the population proportion is:

Diff: 2

LO: 8.4.0 Construct a confidence interval for the population proportion from a large sample.

Section: 8.4 Estimation of a Population Proportion: Large Samples

Question Title: Chapter 08, Testbank Question 051

10) The Labor Bureau wants to estimate, at a 90% confidence level, the proportion of all households that receive welfare. The most conservative estimate of the sample size that would limit the margin of error to be within 0.024 of the population proportion is:

Diff: 2

LO: 8.4.0 Construct a confidence interval for the population proportion from a large sample.

Section: 8.4 Estimation of a Population Proportion: Large Samples

Question Title: Chapter 08, Testbank Question 052

11) The Labor Bureau wants to estimate, at a 90% confidence level, the proportion of all households that receive welfare. A preliminary sample showed that 19.0% of households in this sample receive welfare. The sample size that would limit the margin of error to be within 0.040 of the population proportion is:

Diff: 2

LO: 8.4.0 Construct a confidence interval for the population proportion from a large sample.

Section: 8.4 Estimation of a Population Proportion: Large Samples

Question Title: Chapter 08, Testbank Question 053

12) In a 1997 poll of 249 male, married, upper-level managers conducted by Joy Schneer and Frieda Reitman for Fortune magazine, 30% of the men stated that their wives worked either full-time or part-time (Fortune, March 17, 1997). What are the boundaries for a 99% confidence interval for p, the proportion of all male, married, upper-level managers whose wives work?

A) 0.2251 to 0.3749

B) 0.2323 to 0.3677

C) 0.2431 to 0.3569

D) 0.2521 to 0.3479

Diff: 2

LO: 8.4.0 Construct a confidence interval for the population proportion from a large sample.

Section: 8.4 Estimation of a Population Proportion: Large Samples

Question Title: Chapter 08, Testbank Question 054

13) Out of a sample of 681 gasoline purchases at a self-service gas station, 585 were made with a credit or debit card. Obtain the predeterminated margin of error. (Round your answer to three decimal places.)

Diff: 2

LO: 8.4.0 Construct a confidence interval for the population proportion from a large sample.

Section: 8.4 Estimation of a Population Proportion: Large Samples

Question Title: Chapter 08, Testbank Question 055

14) In a random sample of 63 items produced by a machine, the quality control staff found 9 of them to be defective. Calculate the point estimate of the population proportion of defective items. Round to 4 decimal places.

Diff: 2

LO: 8.4.0 Construct a confidence interval for the population proportion from a large sample.

Section: 8.4 Estimation of a Population Proportion: Large Samples

Question Title: Chapter 08, Testbank Question 056

15) A random sample of 703 persons showed that 581 do not have health insurance. Calculate the point estimate of the population proportion of persons who do not have health insurance. Round to 4 decimal places.

Diff: 2

LO: 8.4.0 Construct a confidence interval for the population proportion from a large sample.

Section: 8.4 Estimation of a Population Proportion: Large Samples

Question Title: Chapter 08, Testbank Question 057

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