Test Bank Answers Ch.27 Synthetic Polymers Klein - Organic Chemistry 4e | Test Bank by Klein by David R. Klein. DOCX document preview.

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Test Bank Answers Ch.27 Synthetic Polymers Klein

Organic Chemistry, 4e (Klein)

Chapter 27 Synthetic Polymers

1) Polymers are comprised of repeating units that are formed by joining ________.

A) tetramers

B) monomers

C) dimers

D) trimers

E) none of these

Diff: 1

Learning Objective: 27.1 Describe the general structure of a polymer, and compare synthetic polymers and biopolymers

2) Which one of the choices is (are) a biopolymer?

A) RNA

B) DNA

C) polysaccharides

D) proteins

E) all of these

Diff: 1

Learning Objective: 27.1 Describe the general structure of a polymer, and compare synthetic polymers and biopolymers

3) Which one of the choices is not a biopolymer?

A) amylopectin

B) DNA

C) glycogen

D) chitin

E) none of these

Diff: 1

Learning Objective: 27.1 Describe the general structure of a polymer, and compare synthetic polymers and biopolymers

4) Which one of the given monomers will produce polyisobutylene?

An illustration depicts four monomers. The first monomer labeled Roman numeral 1 has two carbon atoms double bonded to each other. From right to left, the C 1 is single bonded to a hydrogen atom, H, at the bottom and an ethyl group, C H 2 C H 3 at the top. The C 2 is single bonded to two hydrogen atoms. One at the top and the other at the bottom. The second monomer labeled Roman numeral 2 has two carbon atoms double bonded to each other. From right to left, the C 1 is single bonded to a methyl group, C H 3 at the top as well as at the bottom. The C 2 is single bonded to two hydrogen atoms. One at the top and the other at the bottom. The third monomer labeled Roman numeral 3 has two carbon atoms double bonded to each other. From right to left, the C 1 is single bonded to a hydrogen atom, H, at the bottom and methyl group C H 3 at the top. The C 2 is single bonded to a hydrogen atom, H, at the top, and methyl group C H 3 at the bottom. The fourth monomer labeled Roman numeral 4 has two carbon atoms double bonded to each other. From right to left, the C 1 is single bonded to a hydrogen atom, H, at the bottom and an ethyl group, C H 2 C H 3 at the top. The C 2 is single bonded to two hydrogen atoms. One at the top and the other at the bottom.

A) I

B) II

C) III

D) IV

E) none of these

Diff: 1

Learning Objective: 27.2 Assign a name to a polymer using IUPAC rules

5) Which one of the given monomers will produce poly(vinyl chloride)?

An illustration depicts four monomers. The first monomer labeled Roman numeral 1 has two carbon atoms double bonded to each other. From right to left, the C 1 is single bonded to a hydrogen atom, H, at the bottom and a chlorine atom, C l, at the top. The C 2 is single bonded to two hydrogen atoms. One at the top and the other at the bottom. The second monomer labeled Roman numeral 2 has two carbon atoms double bonded to each other. From right to left, the C 1 is single bonded to chloromethyl group, C H 2 C l at the top and a hydrogen atom, H, at the bottom. The C 2 is single bonded to two hydrogen atoms. One at the top and the other at the bottom. The third monomer labeled Roman numeral 3 has two carbon atoms double bonded to each other. From right to left, the C 1 is single bonded to a chlorine atom, C l, at the bottom and a methyl group C H 3 at the top. The C 2 is single bonded to two hydrogen atoms. One at the top and other at the bottom. The fourth monomer labeled Roman numeral 4 has two carbon atoms double bonded to each other. From right to left, the C 1 is single bonded to a hydrogen atom, H, at the bottom and a methyl group, C H 3, at the top. The C 2 is single bonded to chlorine atom, C l, at the bottom and hydrogen, H, at the top.

A) I

B) II

C) III

D) IV

E) none of these

Diff: 1

Learning Objective: 27.2 Assign a name to a polymer using IUPAC rules

6) Which one of the given monomers will produce polyisoprene?

An illustration depicts four monomers. The first monomer labeled Roman numeral 1 has a SMILES string of CC(=C)C(=C)C. The second monomer labeled Roman numeral 2 has a SMILES string of CC(=C)C=C. The third monomer labeled Roman numeral 3 has a SMILES string of CC=C(C)C. The fourth monomer labeled Roman numeral 4 has a SMILES string of CC(=C(C)C)C.

A) I

B) II

C) III

D) IV

E) none of these

Diff: 1

Learning Objective: 27.2 Assign a name to a polymer using IUPAC rules

7) Which one of the given monomers will produce polytetrafluoroethylene?

An illustration depicts four monomers. The first monomer labeled Roman numeral 1 has two carbon atoms double bonded to each other. From right to left, the C 1 is single bonded to two fluorine atoms. One at the top and the other at the bottom. The C 2 is single bonded to a fluorine atom, F, at the top and a hydrogen atom, H, at the bottom. The second monomer labeled Roman numeral 2 has two carbon atoms double bonded to each other. From right to left, the C 1 is single bonded to fluoromethyl group, C H 2 F at the top and a fluorine atom F at the bottom. The C 2 is single bonded to two fluorine atoms. One at the top and the other at the bottom. The third monomer labeled Roman numeral 3 has two carbon atoms double bonded to each other. From right to left, the C 1 is single bonded to two fluorine atoms. One at the top and the other at the bottom. The C 2 is single bonded to two fluorine atoms. One at the top and the other at the bottom. The fourth monomer labeled Roman numeral 4 has two carbon atoms double bonded to each other. From right to left, the C 1 is single bonded to a fluoromethyl group, C H 2 F at the top and a fluorine atom, F at the bottom. The C 2 is also single bonded to fluoromethyl group, C H 2 F at the top and a fluorine atom F at the bottom.

A) I

B) II

C) III

D) IV

E) none of these

Diff: 1

Learning Objective: 27.2 Assign a name to a polymer using IUPAC rules

8) Which one of the choices is the correct structure for polystyrene?

An illustration depicts four chemical structures. The first structure labeled Roman numeral 1 has two linearly arranged carbon atoms single bonded to each other. From right to left, the C 1 is single bonded to a phenyl group, P h, a hydrogen atom, H, and has an open bond. The C 2 is single bonded to a hydrogen atom, H, a methyl group, C H 3, and has an open bond. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. The open bonds at C 1 and C 2 extends outside the square bracket. The second structure labeled Roman numeral 2 has two linearly arranged carbon atoms single bonded to each other. From right to left, the C 1 is single bonded to a cyanide group, C N, a hydrogen atom, H, and has an open bond. The C 2 is single bonded to two hydrogen atoms and has an open bond. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. The open bonds at C 1 and C 2 extends outside the square bracket. The third structure labeled Roman numeral 3 has two linearly arranged carbon atoms single bonded to each other. From right to left, the C 1 is single bonded to a phenyl group, P h, a hydrogen atom, H, and has an open bond. The C 2 is single bonded to two hydrogen atoms and has an open bond. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. The open bonds at C 1 and C 2 extends outside the square bracket. The fourth structure labeled Roman numeral 4 has two linearly arranged carbon atoms single bonded to each other. From right to left, the C 1 is single bonded two methyl groups and has an open bond. The C 2 is single bonded to two hydrogen atoms and has an open bond. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. The open bonds at C 1 and C 2 extends outside the square bracket.

A) I

B) II

C) III

D) IV

E) none of these

Diff: 1

Learning Objective: 27.2 Assign a name to a polymer using IUPAC rules

9) Which one of the choices is the correct structure for poly(vinylidene fluoride)?

An illustration depicts four chemical structures. The first structure labeled Roman numeral 1 has two linearly arranged carbon atoms single bonded to each other. From right to left, the C 1 is single bonded to two fluorine atoms, F, and has an open bond. The C 2 is also single bonded to two fluorine atoms, F, and has an open bond. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. The open bond at C 1 and C 2 extends outside the square bracket. The second structure labeled Roman numeral 2 has two linearly arranged carbon atoms single bonded to each other. From right to left, the C 1 is single bonded to a fluorine atom, F, a hydrogen atom, H, and has an open bond. The C 2 is single bonded to two hydrogen atoms, H, and has an open bond. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. The open bond at C 1 and C 2 extends outside the square bracket. The third structure labeled Roman numeral 3 has two linearly arranged carbon atoms single bonded to each other. From right to left, the C 1 is single bonded to a fluorine atom, F, a hydrogen atom, H, and has an open bond. The C 2 is also single bonded to a fluorine atom, F, a hydrogen atom, H, and has an open bond. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. The open bond at C 1 and C 2 extends outside the square bracket.

A) I

B) II

C) III

D) IV

E) none of these

Diff: 1

Learning Objective: 27.2 Assign a name to a polymer using IUPAC rules

10) Which one of the choices is the correct structure for poly(vinyl acetate)?

An illustration depicts four chemical structures. The first structure labeled Roman numeral 1 has two linearly arranged carbon atoms single bonded to each other. From right to left, the C 1 is single bonded to an oxygen atom, O, a hydrogen atom, H, and has an open bond. The oxygen atom is further single bonded to a carbon atom, which is then double bonded to another oxygen atom and single bonded to a methyl group, C H 3. The C 2 is single bonded to two hydrogen atoms, and has an open bond. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. The open bond at C 1 and C 2 extends outside the square bracket. The second structure labeled Roman numeral 2 has two linearly arranged carbon atoms single bonded to each other. From right to left, the C 1 is single bonded to a carbon atom, which is further bonded to a methyl group and double bonded to an oxygen atom. C 1 is also single bonded to a hydrogen atom and has an open bond. The C 2 is single bonded to two hydrogen atoms, and has an open bond. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. The open bond at C 1 and C 2 extends outside the square bracket. The third structure labeled Roman numeral 3 has two linearly arranged carbon atoms single bonded to each other. From right to left, the C 1 is single bonded to a carbon atom, which is further bonded to a methyl group and double bonded to an oxygen atom. C 1 is also single bonded to a hydrogen atom and has an open bond. The C 2 is single bonded to a hydrogen atom, H, a methyl group, C H 3, and has an open bond. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. The open bond at C 1 and C 2 extends outside the square bracket. The fourth structure labeled Roman numeral 4 has two linearly arranged carbon atoms single bonded to each other. From right to left, the C 1 is single bonded to an oxygen atom, O, hydrogen atom, H, and has an open bond. The oxygen atom is further single bonded to a carbon atom which is then double bonded to another oxygen atom and single bonded to a methyl group, C H 3. The C 2 is single bonded to a hydrogen atom, H, a methyl group, C H 3, and has an open bond. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. The open bond at C 1 and C 2 extends outside the square bracket.

A) I

B) II

C) III

D) IV

E) none of these

Diff: 1

Learning Objective: 27.2 Assign a name to a polymer using IUPAC rules

11) Which one of the choices is the correct structure for poly(methyl α-cyanoacrylate?

An illustration depicts four chemical structures. The first structure labeled Roman numeral 1 has two linearly arranged carbon atoms single bonded to each other. From right to left, the C 1 is single bonded to an oxygen atom, O, a hydrogen atom, H, and has an open bond. The oxygen atom is further single bonded to a carbon atom which is then double bonded to another oxygen atom and single bonded to a methyl group, C H 3. The C 2 is single bonded to a hydrogen atom, H, a cyanide group, C N, and has an open bond. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. The open bond at C 1 and C 2 extends outside the square bracket. The second structure labeled Roman numeral 2 has two linearly arranged carbon atoms single bonded to each other. From right to left, the C 1 is single bonded to another carbon atom which is further double bonded to an oxygen atom, O, and single bonded to methoxy group, H 3 C O. C 1 is also further single bonded to a cyanide group, C N and has an open bond. The C 2 is single bonded to two hydrogen atoms, and has an open bond. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. The open bond at C 1 and C 2 extends outside the square bracket. The third structure labeled Roman numeral 3 has two linearly arranged carbon atoms single bonded to each other. From right to left, the C 1 is single bonded to a carbon atom, which is further bonded to a methyl group and double bonded to an oxygen atom. C 1 is also single bonded to a hydrogen atom and has an open bond. The C 2 is single bonded to a hydrogen atom, H, a cyanide group, C N, and has an open bond. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. The open bond at C 1 and C 2 extends outside the square bracket. The fourth structure labeled Roman numeral 4 has two linearly arranged carbon atoms single bonded to each other. From right to left, the C 1 is single bonded to an oxygen atom, O, a cyanide group, C N, and has an open bond. The oxygen atom is further single bonded to a carbon atom which is then double bonded to another oxygen atom and single bonded to a methyl group, C H 3. The C 2 is single bonded to two hydrogen atoms, H, and has an open bond. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. The open bond at C 1 and C 2 extends outside the square bracket.

A) I

B) II

C) III

D) IV

E) none of these

Diff: 1

Learning Objective: 27.2 Assign a name to a polymer using IUPAC rules

12) Identify the polymer used in nonstick frying pans.

A) polytetrafluoroethylene

B) polystyrene

C) polypropylene

D) polyethylene

E) poly(vinyl chloride)

Diff: 1

Learning Objective: 27.2 Assign a name to a polymer using IUPAC rules

13) Identify the polymer used in plumbing.

A) polytetrafluoroethylene

B) polystyrene

C) polypropylene

D) polyethylene

E) poly(vinyl chloride)

Diff: 1

Learning Objective: 27.2 Assign a name to a polymer using IUPAC rules

14) Identify the polymer used in disposable cups.

A) polytetrafluoroethylene

B) polystyrene

C) polypropylene

D) polyethylene

E) poly(vinyl chloride)

Diff: 1

Learning Objective: 27.2 Assign a name to a polymer using IUPAC rules

15) A homopolymer is a polymer constructed from ________.

A) a single type of monomer

B) two different types of monomers

C) many different types of monomers

D) a dimer

E) a trimer

Diff: 1

Learning Objective: 27.3 Compare and contrast homopolymers and copolymers, alternating and random copolymers, and block and graft copolymers

16) A copolymer is a polymer constructed from ________.

A) a single type of monomer

B) two or more different types of monomers

C) monosaccharides

D) a dimer

E) a trimer

Diff: 1

Learning Objective: 27.3 Compare and contrast homopolymers and copolymers, alternating and random copolymers, and block and graft copolymers

17) Which one of the choices is classified as a homopolymer?

A) saran

B) viton

C) poly(vinyl bromide)

D) SAN

E) ABS

Diff: 1

Learning Objective: 27.3 Compare and contrast homopolymers and copolymers, alternating and random copolymers, and block and graft copolymers

18) Which one of the choices is classified as a copolymer?

A) saran

B) polyacrylonitrile

C) poly(vinyl bromide)

D) polystyrene

E) polyethylene

Diff: 2

Learning Objective: 27.3 Compare and contrast homopolymers and copolymers, alternating and random copolymers, and block and graft copolymers

19) Polymers constructed from a single type of monomer are called ________, whereas those constructed from two or more different types of monomers are called ________.

A) copolymers; homopolymers

B) homopolymers; copolymers

C) block polymers; homopolymers

D) homopolymers; block polymers

E) copolymers; block polymers

Diff: 1

Learning Objective: 27.3 Compare and contrast homopolymers and copolymers, alternating and random copolymers, and block and graft copolymers

20) Identify the polymer used in food packaging.

A) SAN

B) ABS

C) butyl rubber

D) viton

E) saran

Diff: 1

Learning Objective: 27.3 Compare and contrast homopolymers and copolymers, alternating and random copolymers, and block and graft copolymers

21) The given polymer is classified as a(n) ________.

An illustration depicts a sequence of repeat units A and B in a polymer. From left to right the sequence reads, A, B, A, B, A, B, A, B.

A) homopolymer

B) block copolymer

C) graft copolymer

D) alternating copolymer

E) random copolymer

Diff: 1

Learning Objective: 27.3 Compare and contrast homopolymers and copolymers, alternating and random copolymers, and block and graft copolymers

22) The given polymer is classified as a(n) ________.

An illustration depicts a sequence of repeat units A and B in a polymer. From left to right the sequence reads, A, A, A, B, A, B, B, B.

A) homopolymer

B) block copolymer

C) graft copolymer

D) alternating copolymer

E) random copolymer

Diff: 1

Learning Objective: 27.3 Compare and contrast homopolymers and copolymers, alternating and random copolymers, and block and graft copolymers

23) The given polymer is classified as a(n) ________.

An illustration depicts a sequence of repeat units A and B in a polymer. From left to right the sequence reads, A, A, A, A, B, B, B, B.

A) homopolymer

B) block copolymer

C) graft copolymer

D) alternating copolymer

E) random copolymer

Diff: 1

Learning Objective: 27.3 Compare and contrast homopolymers and copolymers, alternating and random copolymers, and block and graft copolymers

24) The given polymer is classified as a(n) ________.

An illustration depicts a sequence of repeat units A and B in a polymer. The polymer has a main chain and a branched chain. From left to right, the horizontal main chain components read, A, A, A, A, A, A, A, A. Below the third component from left, a vertical branched chain is present and it reads, B, B, B. Below the third component from right, another vertical branched chain is present and it reads, B, B, B.

A) homopolymer

B) block copolymer

C) graft copolymer

D) alternating copolymer

E) random copolymer

Diff: 1

Learning Objective: 27.3 Compare and contrast homopolymers and copolymers, alternating and random copolymers, and block and graft copolymers

25) Which of the choices is a region of a block copolymer constructed from isobutylene and vinyl fluoride?

An illustration depicts a chemical structure labeled Roman numeral 1 with a linear carbon chain of 12 carbon atoms. From right to left, the C 1 is bonded to a fluorine atom, F, a hydrogen atom, H, and has an open bond. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to two methyl groups, C H 3. The C 4 is bonded to two hydrogen atoms, H. The C 5 is bonded to a fluorine atom, F, and a hydrogen atom, H. The C 6 is bonded to two hydrogen atoms, H. The C 7 is bonded to two methyl groups, C H 3. The C 8 is bonded to two hydrogen atoms, H. The C 9 is bonded to a fluorine atom, F, and a hydrogen atom, H. The C 10 is bonded to two hydrogen atoms, H. The C 11 is bonded to two methyl groups, C H 3. The C 12 is bonded to two hydrogen atoms, H, and has an open bond.

An illustration depicts a chemical structure labeled Roman numeral 2 with a linear carbon chain of 12 carbon atoms. From right to left, the C 1 is bonded to a fluorine atom, F, a hydrogen atom, H, and has an open bond. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to a fluorine atom, F, and a hydrogen atom, H. The C 4 is bonded to two hydrogen atoms, H. The C 5 is bonded to a fluorine atom, F, and a hydrogen atom, H. The C 6 is bonded to two hydrogen atoms, H. The C 7 is bonded to two methyl groups, C H 3. The C 8 is bonded to two hydrogen atoms, H. The C 9 is bonded to two methyl groups, C H 3. The C 10 is bonded to two hydrogen atoms, H. The C 11 is bonded to two methyl groups, C H 3. The C 12 is bonded to two hydrogen atoms, H, and has an open bond.

An illustration depicts a chemical structure labeled Roman numeral 3 with a linear carbon chain of 12 carbon atoms. From right to left, the C 1 is bonded to a fluorine atom, F, a hydrogen atom, H, and has an open bond. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to two methyl groups, C H 3. The C 4 is bonded to two hydrogen atoms, H. The C 5 is bonded to a fluorine atom, F, and a hydrogen atom, H. The C 6 is bonded to two hydrogen atoms, H. The C 7 is bonded to a fluorine atom, F, and a hydrogen atom, H. The C 8 is bonded to two hydrogen atoms, H. The C 9 is bonded to two methyl groups, C H 3. The C 10 is bonded to two hydrogen atoms, H. The C 11 is bonded to two methyl groups, C H 3. The C 12 is bonded to two hydrogen atoms, H, and has an open bond.

An illustration depicts a chemical structure labeled Roman numeral 4 with a linear carbon chain of 12 carbon atoms. From right to left, the C 1 is bonded to a fluorine atom, F, a hydrogen atom, H, and has an open bond. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to two methyl groups, C H 3. The C 4 is bonded to two hydrogen atoms, H. The C 5 is bonded to two hydrogen atoms, H. The C 6 is bonded to a fluorine atom, F, and a hydrogen atom, H. The C 7 is bonded to two methyl groups, C H 3. The C 8 is bonded to two hydrogen atoms, H. The C 9 is bonded to two hydrogen atoms, H. The C 10 is bonded to a fluorine atom, F, and a hydrogen atom, H. The C 11 is bonded to two methyl groups, C H 3. The C 12 is bonded to two hydrogen atoms, H, and has an open bond.

A) I

B) II

C) III

D) IV

E) none of these

Diff: 1

Learning Objective: 27.3 Compare and contrast homopolymers and copolymers, alternating and random copolymers, and block and graft copolymers

26) Which of the choices is a region of an alternate copolymer constructed from isobutylene and vinyl fluoride?

An illustration depicts a chemical structure labeled Roman numeral 1 with a linear carbon chain of 12 carbon atoms. From right to left, the C 1 is bonded to a fluorine atom, F, a hydrogen atom, H, and has an open bond. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to two methyl groups, C H 3. The C 4 is bonded to two hydrogen atoms, H. The C 5 is bonded to a fluorine atom, F, and a hydrogen atom, H. The C 6 is bonded to two hydrogen atoms, H. The C 7 is bonded to two methyl groups, C H 3. The C 8 is bonded to two hydrogen atoms, H. The C 9 is bonded to a fluorine atom, F, and a hydrogen atom, H. The C 10 is bonded to two hydrogen atoms, H. The C 11 is bonded to two methyl groups, C H 3. The C 12 is bonded to two hydrogen atoms, H, and has an open bond.

An illustration depicts a chemical structure labeled Roman numeral 2 with a linear carbon chain of 12 carbon atoms. From right to left, the C 1 is bonded to a fluorine atom, F, a hydrogen atom, H, and has an open bond. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to a fluorine atom, F, and a hydrogen atom, H. The C 4 is bonded to two hydrogen atoms, H. The C 5 is bonded to a fluorine atom, F, and a hydrogen atom, H. The C 6 is bonded to two hydrogen atoms, H. The C 7 is bonded to two methyl groups, C H 3. The C 8 is bonded to two hydrogen atoms, H. The C 9 is bonded to two methyl groups, C H 3. The C 10 is bonded to two hydrogen atoms, H. The C 11 is bonded to two methyl groups, C H 3. The C 12 is bonded to two hydrogen atoms, H, and has an open bond.

An illustration depicts a chemical structure labeled Roman numeral 3 with a linear carbon chain of 12 carbon atoms. From right to left, the C 1 is bonded to a fluorine atom, F, a hydrogen atom, H, and has an open bond. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to two methyl groups, C H 3. The C 4 is bonded to two hydrogen atoms, H. The C 5 is bonded to a fluorine atom, F, and a hydrogen atom, H. The C 6 is bonded to two hydrogen atoms, H. The C 7 is bonded to a fluorine atom, F, and a hydrogen atom, H. The C 8 is bonded to two hydrogen atoms, H. The C 9 is bonded to two methyl groups, C H 3. The C 10 is bonded to two hydrogen atoms, H. The C 11 is bonded to two methyl groups, C H 3. The C 12 is bonded to two hydrogen atoms, H, and has an open bond.

An illustration depicts a chemical structure labeled Roman numeral 4 with a linear carbon chain of 12 carbon atoms. From right to left, the C 1 is bonded to a fluorine atom, F, a hydrogen atom, H, and has an open bond. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to two methyl groups, C H 3. The C 4 is bonded to two hydrogen atoms, H. The C 5 is bonded to two hydrogen atoms, H. The C 6 is bonded to a fluorine atom, F, and a hydrogen atom, H. The C 7 is bonded to two methyl groups, C H 3. The C 8 is bonded to two hydrogen atoms, H. The C 9 is bonded to two hydrogen atoms, H. The C 10 is bonded to a fluorine atom, F, and a hydrogen atom, H. The C 11 is bonded to two methyl groups, C H 3. The C 12 is bonded to two hydrogen atoms, H, and has an open bond.

A) I

B) II

C) III

D) IV

E) none of these

Diff: 1

Learning Objective: 27.3 Compare and contrast homopolymers and copolymers, alternating and random copolymers, and block and graft copolymers

27) Which of the choices is a region of a random copolymer constructed from isobutylene and vinyl fluoride?

An illustration depicts a chemical structure labeled Roman numeral 1 with a linear carbon chain of 12 carbon atoms. From right to left, the C 1 is bonded to a fluorine atom, F, a hydrogen atom, H, and has an open bond. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to two methyl groups, C H 3. The C 4 is bonded to two hydrogen atoms, H. The C 5 is bonded to a fluorine atom, F, and a hydrogen atom, H. The C 6 is bonded to two hydrogen atoms, H. The C 7 is bonded to two methyl groups, C H 3. The C 8 is bonded to two hydrogen atoms, H. The C 9 is bonded to a fluorine atom, F, and a hydrogen atom, H. The C 10 is bonded to two hydrogen atoms, H. The C 11 is bonded to two methyl groups, C H 3. The C 12 is bonded to two hydrogen atoms, H, and has an open bond.

An illustration depicts a chemical structure labeled Roman numeral 2 with a linear carbon chain of 12 carbon atoms. From right to left, the C 1 is bonded to a fluorine atom, F, a hydrogen atom, H, and has an open bond. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to a fluorine atom, F, and a hydrogen atom, H. The C 4 is bonded to two hydrogen atoms, H. The C 5 is bonded to a fluorine atom, F, and a hydrogen atom, H. The C 6 is bonded to two hydrogen atoms, H. The C 7 is bonded to two methyl groups, C H 3. The C 8 is bonded to two hydrogen atoms, H. The C 9 is bonded to two methyl groups, C H 3. The C 10 is bonded to two hydrogen atoms, H. The C 11 is bonded to two methyl groups, C H 3. The C 12 is bonded to two hydrogen atoms, H, and has an open bond.

An illustration depicts a chemical structure labeled Roman numeral 3 with a linear carbon chain of 12 carbon atoms. From right to left, the C 1 is bonded to a fluorine atom, F, a hydrogen atom, H, and has an open bond. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to two methyl groups, C H 3. The C 4 is bonded to two hydrogen atoms, H. The C 5 is bonded to a fluorine atom, F, and a hydrogen atom, H. The C 6 is bonded to two hydrogen atoms, H. The C 7 is bonded to a fluorine atom, F, and a hydrogen atom, H. The C 8 is bonded to two hydrogen atoms, H. The C 9 is bonded to two methyl groups, C H 3. The C 10 is bonded to two hydrogen atoms, H. The C 11 is bonded to two methyl groups, C H 3. The C 12 is bonded to two hydrogen atoms, H, and has an open bond.

An illustration depicts a chemical structure labeled Roman numeral 4 with a linear carbon chain of 12 carbon atoms. From right to left, the C 1 is bonded to a fluorine atom, F, a hydrogen atom, H, and has an open bond. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to two methyl groups, C H 3. The C 4 is bonded to two hydrogen atoms, H. The C 5 is bonded to two hydrogen atoms, H. The C 6 is bonded to a fluorine atom, F, and a hydrogen atom, H. The C 7 is bonded to two methyl groups, C H 3. The C 8 is bonded to two hydrogen atoms, H. The C 9 is bonded to two hydrogen atoms, H. The C 10 is bonded to a fluorine atom, F, and a hydrogen atom, H. The C 11 is bonded to two methyl groups, C H 3. The C 12 is bonded to two hydrogen atoms, H, and has an open bond.

A) I

B) II

C) III

D) IV

E) none of these

Diff: 2

Learning Objective: 27.3 Compare and contrast homopolymers and copolymers, alternating and random copolymers, and block and graft copolymers

28) Which choice shows the structure of a region of an alternating copolymer constructed from propylene and acrylonitrile?

An illustration depicts five structures. The first structure labeled Roman numeral 1 has a carbon chain of 12 carbon atoms. From right to left, the C 1 atom is bonded to a cyanide group, C N, a hydrogen atom, H, and has an open bond. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to a methyl group, C H 3 and a hydrogen atom, H. The C 4 is bonded to two hydrogen atoms, H. The C 5 is bonded to a cyanide group, C N and a hydrogen atom, H. The C 6 is bonded to two hydrogen atoms, H. The C 7 is bonded to a methyl group, C H 3 and a hydrogen atom, H. The C 8 is bonded to two hydrogen atoms, H. The C 9 is bonded to a cyanide group, C N and a hydrogen atom, H. The C 10 is bonded to two hydrogen atoms, H. The C 11 is bonded to a methyl group, C H 3 and a hydrogen atom, H. The C 12 is bonded to two hydrogen atoms, H and has an open bond. The second structure labeled Roman numeral 2 has a carbon chain of 12 carbon atoms. From right to left, the C 1 atom is bonded to a cyanide group, C N, a hydrogen atom, H, and has an open bond. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to a cyanide group, C N and a hydrogen atom, H. The C 4 is bonded to two hydrogen atoms, H. The C 5 is bonded to a cyanide group, C N and a hydrogen atom, H. The C 6 is bonded to two hydrogen atoms, H. The C 7 is bonded to a methyl group, C H 3 and a hydrogen atom, H. The C 8 is bonded to two hydrogen atoms, H. The C 9 is bonded to a methyl group, C H 3 and a hydrogen atom, H. The C 10 is bonded to two hydrogen atoms, H. The C 11 is bonded to a methyl group, C H 3 and a hydrogen atom, H. The C 12 is bonded to two hydrogen atoms, H and has an open bond. The third structure labeled Roman numeral 3 has a carbon chain of 12 carbon atoms. From right to left, the C 1 atom is bonded to a methyl group, C H 3, a hydrogen atom, H, and has an open bond. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to a methyl group, C H 3 and a hydrogen atom, H. The C 4 is bonded to two hydrogen atoms, H. The C 5 is bonded to a cyanide group, C N and a hydrogen atom, H. The C 6 is bonded to two hydrogen atoms, H. The C 7 is bonded to a cyanide group, C N and a hydrogen atom, H. The C 8 is bonded to two hydrogen atoms, H. The C 9 is bonded to a methyl group, C H 3 and a hydrogen atom, H. The C 10 is bonded to two hydrogen atoms, H. The C 11 is bonded to a methyl group, C H 3 and a hydrogen atom, H. The C 12 is bonded to two hydrogen atoms, H and has an open bond. The fourth structure labeled Roman numeral 4 has a carbon chain of 12 carbon atoms. From right to left, the C 1 atom is bonded to two hydrogen atoms, H and has an open bond. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to a methyl group, C H 3 and a hydrogen atom, H. The C 4 is bonded to two hydrogen atoms, H. The C 5 is bonded to two hydrogen atoms, H. The C 6 is bonded to two hydrogen atoms, H. The C 7 is bonded to a methyl group, C H 3 and a hydrogen atom, H. The C 8 is bonded to two hydrogen atoms, H. The C 9 is bonded to two hydrogen atoms, H. The C 10 is bonded to two hydrogen atoms, H. The C 11 is bonded to a methyl group, C H 3 and a hydrogen atom, H. The C 12 is bonded to two hydrogen atoms, H and has an open bond. The fifth structure labeled Roman numeral 5 has a carbon chain of 12 carbon atoms. From right to left, the C 1 atom is bonded to a cyanide group, C N, a hydrogen atom, H and has an open bond. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to two hydrogen atoms, H. The C 4 is bonded to two hydrogen atoms, H. The C 5 is bonded to a cyanide group, C N and a hydrogen atom, H. The C 6 is bonded to two hydrogen atoms, H. The C 7 is bonded to two hydrogen atoms, H. The C 8 is bonded to two hydrogen atoms, H. The C 9 is bonded to a cyanide group, C N and a hydrogen atom, H. The C 10 is bonded to two hydrogen atoms, H. The C 11 is bonded to two hydrogen atoms, H. The C 12 is bonded to two hydrogen atoms, H and has an open bond.

A) I

B) II

C) III

D) IV

E) V

Diff: 2

Learning Objective: 27.3 Compare and contrast homopolymers and copolymers, alternating and random copolymers, and block and graft copolymers

29) Which choice shows the structure of a region of a random copolymer constructed from ethylene and styrene?

An illustration depicts five structures. The first structure labeled Roman numeral 1 has a carbon chain of 12 carbon atoms. From right to left, the C 1 atom is bonded to a phenyl group, P h, a hydrogen atom, H, and has an open bond. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to a phenyl group, P h and a hydrogen atom, H. The C 4 is bonded to two hydrogen atoms, H. The C 5 is bonded to two hydrogen atoms, H. The C 6 is bonded to two hydrogen atoms, H. The C 7 is bonded to a phenyl group, P h and a hydrogen atom, H. The C 8 is bonded to two hydrogen atoms, H. The C 9 is bonded to two hydrogen atoms, H. The C 10 is bonded to two hydrogen atoms, H. The C 11 is bonded to two hydrogen atoms, H. The C 12 is bonded to two hydrogen atoms, H and has an open bond. The second structure labeled Roman numeral 2 has a carbon chain of 12 carbon atoms. From right to left, the C 1 atom is bonded to a phenyl group, P h, a hydrogen atom, H, and has an open bond. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to a phenyl group, P h and a hydrogen atom, H. The C 4 is bonded to two hydrogen atoms, H. The C 5 is bonded to a phenyl group, P h and a hydrogen atom, H. The C 6 is bonded to two hydrogen atoms, H. The C 7 is bonded to a phenyl group, P h and a hydrogen atom, H. The C 8 is bonded to two hydrogen atoms, H. The C 9 is bonded to a phenyl group, P h and a hydrogen atom, H. The C 10 is bonded to two hydrogen atoms, H. The C 11 is bonded to a phenyl group, P h and a hydrogen atom, H. The C 12 is bonded to two hydrogen atoms, H and has an open bond. The third structure labeled Roman numeral 3 has a carbon chain of 12 carbon atoms. From right to left, the C 1 atom is bonded to a phenyl group, P h, a hydrogen atom, H, and has an open bond. The C 2 is bonded to a phenyl group, P h and a hydrogen atom, H. The C 3 is bonded to a phenyl group, P h and a hydrogen atom, H. The C 4 is bonded to a phenyl group, P h and a hydrogen atom, H. The C 5 is bonded to a phenyl group, P h and a hydrogen atom, H. The C 6 is bonded to a phenyl group, P h and a hydrogen atom, H. The C 7 is bonded to a phenyl group, P h and a hydrogen atom, H. The C 8 is bonded to two hydrogen atoms, H. The C 9 is bonded to two hydrogen atoms, H. The C 10 is bonded to two hydrogen atoms, H. The C 11 is bonded to two hydrogen atoms, H. The C 12 is bonded to two hydrogen atoms, H and has an open bond. The fourth structure labeled Roman numeral 4 has a carbon chain of 12 carbon atoms. From right to left, the C 1 atom is bonded to two hydrogen atoms, H and has an open bond. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to two hydrogen atoms, H. The C 4 is bonded to two hydrogen atoms, H. The C 5 is bonded to two hydrogen atoms, H. The C 6 is bonded to two hydrogen atoms, H. The C 7 is bonded to a phenyl group, P h and a hydrogen atom, H. The C 8 is bonded to a phenyl group, P h and a hydrogen atom, H. The C 9 is bonded to a phenyl group, P h and a hydrogen atom, H. The C 10 is bonded to a phenyl group, P h and a hydrogen atom, H. The C 11 is bonded to a phenyl group, P h and a hydrogen atom, H. The C 12 is bonded to a phenyl group, P h, a hydrogen atom, H and has an open bond. The fifth structure labeled Roman numeral 5 has a carbon chain of 12 carbon atoms. From right to left, the C 1 atom is bonded to two hydrogen atoms, H and has an open bond. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to two hydrogen atoms, H. The C 4 is bonded to two hydrogen atoms, H. The C 5 is bonded to two hydrogen atoms, H. The C 6 is bonded to two hydrogen atoms, H. The C 7 is bonded to two hydrogen atoms, H. The C 8 is bonded to two hydrogen atoms, H. The C 9 is bonded to two hydrogen atoms, H. The C 10 is bonded to two hydrogen atoms, H. The C 11 is bonded to two hydrogen atoms, H. The C 12 is bonded to two hydrogen atoms, H and has an open bond.

A) I

B) II

C) III

D) IV

E) V

Diff: 2

Learning Objective: 27.3 Compare and contrast homopolymers and copolymers, alternating and random copolymers, and block and graft copolymers

30) PET, used to make soft-drink bottles, is classified as a(n) ________.

A) homopolymer

B) block copolymer

C) graft copolymer

D) alternating copolymer

E) random copolymer

Diff: 1

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

31) Polyesters are classified as ________.

A) homopolymers

B) block copolymers

C) graft copolymers

D) alternating copolymers

E) random copolymers

Diff: 1

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

32) Which of the given monomers is required to make the polymer below?

An illustration depicts the chemical structure of a polymer. A linear carbon chain of eight carbon atoms is present. From right to left, the C 1 is bonded to two methyl groups, C H 3. Another single bond from C 1 is present with a wavy line on it. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to two methyl groups, C H 3. The C 4 is bonded to two hydrogen atoms, H. The C 5 is bonded to two methyl groups, C H 3. The C 6 is bonded to two hydrogen atoms, H. The C 7 is bonded to two methyl groups, C H 3. The C 8 is bonded to two hydrogen atoms, H. Another single bond from C 8 is present with a wavy line on it.

A) propene

B) isobutylene

C) isoprene

D) styrene

E) none of these

Diff: 2

Learning Objective: 27.3 Compare and contrast homopolymers and copolymers, alternating and random copolymers, and block and graft copolymers

33) Which of the given monomer pairs is required to make the polymer shown?

An illustration depicts a chemical structure of a polymer. A linear carbon chain of four carbon atoms is present. From right to left, the C 1 is bonded to a cyanide group, C N, and a hydrogen atom, H. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to two methyl groups, C H 3. The C 4 is bonded to two hydrogen atoms, H. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. A single bond connecting the carbon atoms, C 1 and C 4 extends outside the square bracket.

A) propene and acrylonitrile

B) isoprene and acrylonitrile

C) ethylene and acrylonitrile

D) isobutylene and acrylonitrile

E) none of these

Diff: 2

Learning Objective: 27.3 Compare and contrast homopolymers and copolymers, alternating and random copolymers, and block and graft copolymers

34) Which of the given monomer pairs is required to make the polymer below?

An illustration depicts a chemical structure of a polymer. A linear carbon chain of four carbon atoms is present. From right to left, the C 1 is bonded to a C H group, which is further double bonded to a C H 2 group. The C 1 is also bonded to a methyl group C H 3. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to two methyl groups, C H 3. The C 4 is bonded to two hydrogen atoms, H. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. Another single bond connecting the carbon atoms, C 1 and C 4 extends outside the square bracket.

A) propene and isobutylene

B) isoprene and propene

C) ethylene and butene

D) isobutylene and isoprene

E) none of these

Diff: 2

Learning Objective: 27.3 Compare and contrast homopolymers and copolymers, alternating and random copolymers, and block and graft copolymers

35) Which of the given monomer pairs is required to make the polymer below?

An illustration depicts a chemical structure of a polymer. A linear carbon chain of four carbon atoms is present. From right to left, the C 1 is bonded to a cyanide group, C N, and a hydrogen atom, H. The C 2 is bonded to two hydrogen atoms, H. The C 3 is bonded to a phenyl group, P h, and a hydrogen atom. The C 4 is bonded to two hydrogen atoms, H. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. A single bond connecting the carbon atoms, C 1 and C 4 extends outside the square bracket.

A) styrene and acrylonitrile

B) styrene and propylnitrile

C) phenylpropene and acrylonitrile

D) phenylpropene and propylnitrile

E) none of these

Diff: 2

Learning Objective: 27.3 Compare and contrast homopolymers and copolymers, alternating and random copolymers, and block and graft copolymers

36) Which of the choices is used as an initiator in radical polymerization?

A) BF3, H2O

B) CH3CH2CH2CH2Li

C) ROOR

D) NaOH

E) H2O

Diff: 2

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

37) Which of the choices is used as an initiator in cationic polymerization?

A) BF3, H2O

B) CH3CH2CH2CH2Li

C) ROOR

D) NaOH

E) none of these

Diff: 2

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

38) Which of the choices is used as an initiator in anionic polymerization?

A) BF3, H2O

B) CH3CH2CH2CH2Li

C) ROOR

D) H2SO4

E) none of these

Diff: 2

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

39) Which of the given monomers would be most reactive towards cationic polymerization?

An illustration depicts five monomers. The first compound labeled as Roman numeral one has a carbon atom double bonded to a methylene compound and single bonded to a methoxy group, O C H 3. The second compound labeled as Roman numeral two has a carbon atom double bonded to a methylene compound and single bonded to a cyanide group, C N. The third compound labeled as Roman numeral three has a SMILES string of C=CC=O. The fourth compound labeled as Roman numeral fourth has a carbon atom double bonded to a methylene compound and single bonded to a trifluoromethyl, C F 3. The fifth compound labeled as Roman numeral five has a carbon atom double bonded to a methylene compound and single bonded to a nitrogen dioxide, N O 2.

A) I

B) II

C) III

D) IV

E) V

Diff: 2

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

40) Which of the given monomers would be most reactive towards anionic polymerization?

An illustration depicts five monomers. The first compound labeled as Roman numeral one has a carbon atom double bonded to a methylene compound and single bonded to a methoxy group, O C H 3. The second compound labeled as Roman numeral two has a carbon atom double bonded to a methylene compound and single bonded to a cyanide group, C N. The third compound labeled as Roman numeral three has a SMILES string of CC=C. The fourth compound labeled as Roman numeral four has a SMILES string of C=CN. The fifth compound labeled as Roman numeral five has a SMILES string of CC(=O)OC=C.

A) I

B) II

C) III

D) IV

E) V

Diff: 2

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

41) Arrange the given monomers in decreasing order of reactivity towards cationic polymerization.

An illustration depicts three monomers. The first monomer labeled Roman numeral 1 has a SMILES string of C=CC=O. The second monomer labeled Roman numeral 2 has a SMILES string of C=CN. The third monomer labeled Roman numeral 3 has a SMILES string of CC(=O)OC=C.

A) I > III > II

B) II > I > III

C) III > II > I

D) II > III > I

E) III > I > II

Diff: 2

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

42) Arrange the given monomers in decreasing order of reactivity towards anionic polymerization.

An illustration depicts three monomers. The first compound labeled as Roman numeral one has a carbon atom double bonded to a methylene compound and single bonded to a methoxy group, O C H 3. The second compound labeled as Roman numeral two has a carbon atom double bonded to a methylene compound and single bonded to a trifluoromethyl group, C F 3. The third compound labeled as Roman numeral three has a SMILES string of CC=C.

A) I > III > II

B) II > III > I

C) III > II > I

D) II > I > III

E) III > I > II

Diff: 2

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

43) Arrange the given monomers in decreasing order of reactivity towards anionic polymerization.

An illustration depicts three monomers. The first compound labeled as Roman numeral one has a SMILES string of C=CN. The second compound labeled as Roman numeral two has a SMILES string of CC(=O)C=C. The third compound labeled as Roman numeral three has a SMILES string of CC(=O)OC=C.

A) I > III > II

B) II > I > III

C) III > II > I

D) II > III > I

E) III > I > II

Diff: 2

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

44) Which of the given monomer(s) would undergo cationic polymerization? Select all that apply.

A) vinylidene fluoride

B) acrylonitrile

C) isobutylene

D) vinyl acetate

E) all of these

Diff: 2

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

45) Which of the given monomer(s) would undergo anionic polymerization? Select all that apply.

A) vinyl acetate

B) acrylonitrile

C) isobutylene

D) vinylidene chloride

E) all of these

Diff: 2

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

46) Which of the given monomer(s) would undergo both radical and cationic polymerization?

A) methyl methacrylate

B) acrylonitrile

C) isobutylene

D) vinylidene chloride

E) all of these

Diff: 2

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

47) Which of the given polymers would be best prepared using cationic polymerization?

An illustration depicts four chemical structures of polymers. The first structure labeled Roman numeral 1 has two linearly arranged carbon atoms single bonded to each other. From right to left, the C 1 is single bonded to an oxygen atom, O, a hydrogen atom, H, and has an open bond. The oxygen atom is further single bonded to a carbon atom which is then double bonded to another oxygen atom and single bonded to a methyl group, C H 3. The C 2 is single bonded to two hydrogen atoms, and has an open bond. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. The open bond at C 1 and C 2 extends outside the square bracket. The second structure labeled Roman numeral 2 has two linearly arranged carbon atoms single bonded to each other. From right to left, the C 1 is single bonded to Nitrogen dioxide, N O 2, hydrogen atom, H, and has an open bond. The C 2 is single bonded to two hydrogen atoms, and has an open bond. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. The open bond at C 1 and C 2 extends outside the square bracket. The third structure labeled Roman numeral 3 has two linearly arranged carbon atoms single bonded to each other. From right to left, the C 1 is single bonded to a carbon atom, which is further bonded to a methyl group and double bonded to an oxygen atom. C 1 is also single bonded to a hydrogen atom and has an open bond. The C 2 is single bonded to a hydrogen atom, H, a methyl group, C H 3, and has an open bond. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. The open bond at C 1 and C 2 extends outside the square bracket. The fourth structure labeled Roman numeral 4 has two linearly arranged carbon atoms single bonded to each other. From right to left, the C 1 is single bonded to two fluorine atoms and has an open bond. The C 2 is single bonded to two hydrogen atoms, H and has an open bond. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. The open bond at C 1 and C 2 extends outside the square bracket.

A) I

B) II

C) III

D) IV

E) none of these

Diff: 2

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

48) Which of the given polymers would be best prepared using anionic polymerization?

An illustration depicts four chemical structures of polymers. The first structure labeled Roman numeral 1 has two linearly arranged carbon atoms single bonded to each other. From right to left, the C 1 is single bonded to an oxygen atom, O, a hydrogen atom, H, and has an open bond. The oxygen atom is further single bonded to a carbon atom which is then double bonded to another oxygen atom and single bonded to a methyl group, C H 3. The C 2 is single bonded to two hydrogen atoms, and has an open bond. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. The open bond at C 1 and C 2 extends outside the square bracket. The second structure labeled Roman numeral 2 has two linearly arranged carbon atoms single bonded to each other. From right to left, the C 1 is single bonded to two hydrogen atoms and has an open bond. The C 2 is single bonded to two hydrogen atoms, and has an open bond. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. The open bond at C 1 and C 2 extends outside the square bracket. The third structure labeled Roman numeral 3 has two linearly arranged carbon atoms single bonded to each other. From right to left, the C 1 is single bonded to a carbon atom, which is further bonded to a methyl group and double bonded to an oxygen atom. C 1 is also single bonded to a hydrogen atom and has an open bond. The C 2 is single bonded to a hydrogen atom, H, a methyl group, C H 3, and has an open bond. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. The open bond at C 1 and C 2 extends outside the square bracket. The fourth structure labeled Roman numeral 4 has two linearly arranged carbon atoms single bonded to each other. From right to left, the C 1 is single bonded to a methyl group, C H 3, a hydrogen atom, and has an open bond. The C 2 is single bonded to two hydrogen atoms, H and has an open bond. The structure is enclosed within a square bracket. An alphabet n is at the base of the square bracket. The open bond at C 1 and C 2 extends outside the square bracket. An illustration depicts four chemical structures of polymers.

A) I

B) II

C) III

D) IV

E) none of these

Diff: 2

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

49) ________ polymerization usually forms living polymers if the process is not terminated by an electrophile.

A) Anionic

B) Cationic

C) Radical

D) Condensation

E) Elimination

Diff: 1

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

50) Identify the type of addition that is used to form Superglue.

A) anionic

B) cationic

C) radical

D) condensation

E) elimination

Diff: 1

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

51) Which of the choices is (are) condensation polymer(s)?

A) nylon 6,6

B) polyisobutylene

C) poly(vinyl chloride)

D) polycarbonate

E) A and D

Diff: 2

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

52) Which of the given monomers would produce the condensation polymer shown?

An illustration depicts a condensation polymer. The polymer has two six membered benzene rings. The C 1 of the first ring is bonded to a carbon atom, which is further double bonded to an oxygen atom. This carbon atom is also connected to a single bond which has a wavy line on it. The C 4 of the first ring is bonded to a carbon atom which is further double bonded to an oxygen atom. This carbon atom is also bonded to O C H 2 C H 2 C H 2 O group, which is further bonded to another carbon atom. This carbon atom is double bonded to an oxygen atom and single bonded to C 1 of the second benzene ring. The C 4 of the second ring is bonded to a carbon atom which is further double bonded to an oxygen atom. This carbon atom is also bonded to O C H 2 C H 2 C H 2 O group which is further single bonded to another element and is indicated using a wavy line.

An illustration depicts four monomers. The first compound labeled as Roman numeral one is an ethylene glycol, H O C H 2 C H 2 O H. The second compound labeled as Roman numeral two is a propanediol, H O C H 2 C H 2 C H 2 O H. The third compound labeled as Roman numeral three has a SMILES string of c1cc(ccc1C(=O)O)C(=O)O. The fourth compound labeled as Roman numeral four has a SMILES string of c1cc(ccc1C=O)C=O.

A) I and II

B) I and III

C) II and III

D) II and IV

E) I and IV

Diff: 3

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

53) What is the structure of a region of the polymer that is produced when the given monomers react?

An illustration depicts a reaction between two monomers. The first monomer has two six membered benzene rings in which C 4 of the first benzene ring is single bonded to C 1 of the second benzene ring. The C 1 of the first benzene ring is single bonded to a carbon atom which is then double bonded to an oxygen atom and single bonded to a methoxy group, O C H 3. The C 4 of the second benzene ring is single bonded to a carbon atom which is then double bonded to an oxygen atom and single bonded to a methoxy group, O C H 3. The second monomer has a formula that reads, H O C H 2 C H 2 C H 2 C H 2 O H.

Five chemical structures depicting the different regions of a polymer are as follows: The first structure has four six membered benzene rings. The C 1 of the first ring is bonded to a carbon atom which is further double bonded to an oxygen atom. This carbon atom is also connected to a single bond which has a wavy line on it. The C 4 of the first ring is bonded to C 1 of the second benzene ring. The C 4 of the second benzene ring is bonded to a carbon atom which is further double bonded to an oxygen atom. This carbon atom is also bonded to O C H 2 C H 2 C H 2 O group which is further bonded to another carbon atom. This carbon atom is double bonded to an oxygen atom and single bonded to C 1 of the third benzene ring. The C 4 of the third benzene ring is bonded to C 1 of the fourth benzene ring. The C 4 of the fourth benzene ring is bonded to a carbon atom which is further double bonded to an oxygen atom. This carbon atom is also bonded to O C H 2 C H 2 C H 2 O group which is further single bonded to another element and is indicated using a wavy line. The second structure has four six membered benzene rings. The C 1 of the first ring is bonded to a carbon atom which is further double bonded to an oxygen atom. This carbon atom is also connected to a single bond which has a wavy line on it. The C 4 of the first ring is bonded to C 1 of the second benzene ring. The C 4 of the second benzene ring is bonded to a carbon atom which is further double bonded to an oxygen atom. This carbon atom is also bonded to C H 2 C H 2 C H 2 C H 2 group which is further bonded to another carbon atom. This carbon atom is double bonded to an oxygen atom and single bonded to C 1 of the third benzene ring. The C 4 of the third benzene ring is bonded to C 1 of the fourth benzene ring. The C 4 of the fourth benzene ring is bonded to a carbon atom which is further double bonded to an oxygen atom. This carbon atom is also bonded to C H 2 C H 2 C H 2 group which further has a wavy line near it. The third structure has four six membered benzene rings. The C 1 of the first ring is bonded to a methylene compound, C H 2, which is further connected to another element using a single bond and is represented using a wavy line. The C 4 of the first ring is bonded to C 1 of the second benzene ring. The C 4 of the second benzene ring is bonded to a methylene compound, C H 2, which is further bonded to O C H 2 C H 2 C H 2 C H 2 O group which is further bonded to another methylene compound, C H 2. This methylene compound is bonded to C 1 of the third benzene ring. The C 4 of the third benzene ring is bonded to C 1 of the fourth benzene ring. The C 4 of the fourth benzene ring is bonded to a methylene compound, C H 2. The methylene compound is bonded to O C H 2 C H 2 C H 2 C H 2 O group which is further single bonded to another element and is indicated using a wavy line. The fourth structure has four six membered benzene rings. The C 1 of the first ring is bonded to a carbon atom which is further double bonded to an oxygen atom. This carbon atom is also connected to a single bond which has a wavy line on it. The C 4 of the first ring is bonded to C 1 of the second benzene ring. The C 4 of the second benzene ring is bonded to a carbon atom which is further double bonded to an oxygen atom. This carbon atom is also bonded to O C H 2 C H 2 C H 2 C H 2 O group which is further bonded to another carbon atom. This carbon atom is double bonded to an oxygen atom and single bonded to C 1 of the third benzene ring. The C 4 of the third benzene ring is bonded to C 1 of the fourth benzene ring. The C 4 of the fourth benzene ring is bonded to a carbon atom which is further double bonded to an oxygen atom. This carbon atom is also bonded to O C H 2 C H 2 C H 2 C H 2 O group which is further single bonded to another element.

The fifth structure has four six membered benzene rings. The C 1 of the first ring is bonded to a carbon atom which is further single bonded to an O H group. This carbon atom is also connected to a single bond which has a wavy line on it. The C 4 of the first ring is bonded to C 1 of the second benzene ring. The C 4 of the second benzene ring is bonded to a carbon atom which is further single bonded to an O H group. This carbon atom is also bonded to O C H 2 C H 2 C H 2 C H 2 O group which is further bonded to another carbon atom. This carbon atom is single bonded to an O H group and single bonded to C 1 of the third benzene ring. The C 4 of the third benzene ring is bonded to C 1 of the fourth benzene ring. The C 4 of the fourth benzene ring is bonded to a carbon atom which is further single bonded to an O H group. This carbon atom is also bonded to O C H 2 C H 2 C H 2 C H 2 O group which is further single bonded to another element and is indicated using a wavy line.

A) I

B) II

C) III

D) IV

E) V

Diff: 3

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

54) Which of the given monomers would produce the condensation polymer shown?

An illustration depicts a condensation polymer. The polymer has a 21 carbon chain. From right to left C 1, C 6, C 11, C 16, and C 21 each is double bonded to an oxygen atom. C 2, C 7, C 12, and C 17 each is replaced by an N H group. C 1 and C 21 each is also bonded to a wavy bond.

An illustration depicts four monomers. The first compound labeled as Roman numeral one has a SMILES string of C1CCN=C(C1)O. The second compound labeled as Roman numeral two has a SMILES string of C1CCC(=O)NCC1. The third compound labeled as Roman numeral three has a SMILES string of C1CC(=NC1)O. The fourth compound labeled as Roman numeral four has a linear carbon chain of five carbon atoms. From right to left, the C 1 atom is double bonded to an oxygen atom and single bonded to an amino group, N H 2. The C 5 atom is double bonded to an oxygen atom and single bonded to a methyl group.

A) I

B) II

C) III

D) IV

E) C and D

Diff: 3

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

55) Which of the given monomers would produce the condensation polymer shown?

An illustration depicts a condensation polymer. The polymer has a 25 carbon chain. From right to left, the C 1, C 7, C 13, C 19, and C 25 each is double bonded to an oxygen atom. C 2, C 8, C 14, and C 20 each is replaced by an oxygen atom. C 1 and C 22 is also bonded to a wavy bond.

An illustration depicts four monomers. The first compound labeled as Roman numeral one has a SMILES string of C1CCOC(=O)C1. The second compound labeled as Roman numeral two has a SMILES string of C1CCC(=O)OCC1. The third compound labeled as Roman numeral three has a SMILES string of C1CC(=O)OC1. The fourth compound labeled as Roman numeral four has a SMILES string of CC(=O)CCCC(=O)O.

A) I

B) II

C) III

D) IV

E) C and D

Diff: 3

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

56) Nomex is a synthetic polymer with the structure shown. What is the structure(s) of the monomer(s) that would produce Nomex?

An illustration depicts the chemical structure of a synthetic polymer named Nomex. The Nomex has four six membered benzene rings. The C 5 of the first benzene ring is bonded to N H which is further single bonded to another element. A wavy line is present on this single bond. The C 3 of the first benzene ring is bonded to N H which is further bonded to a carbon atom. This carbon atom is double bonded to an oxygen atom and single bonded to C 6 of the second benzene ring. The C 2 of the second benzene ring is bonded to a carbon atom. This carbon atom is double bonded to an oxygen atom and single bonded to N H. The N H is further single bonded to C 5 of the third benzene ring. The C 3 of the third benzene ring is bonded to N H which is further bonded to a carbon atom. This carbon atom is double bonded to an oxygen atom and single bonded to C 6 of the fourth benzene ring. The C 2 of the fourth benzene ring is bonded to a carbon atom. This carbon atom is double bonded to an oxygen atom and single bonded to another element. The terminal carbon atoms are also bonded to a wavy bond.

An illustration depicts four monomers. The first compound labeled as Roman numeral one has a SMILES string of c1cc(cc(c1)N)N. The second compound labeled as Roman numeral two has a SMILES string of c1cc(cc(c1)C(=O)O)C(=O)O. The third compound labeled as Roman numeral has a molecular formula, N H 2 N H 2. The fourth compound labeled as Roman numeral four has a SMILES string of CC(=O)c1cccc(c1)C(=O)C.

A) I and II

B) I and III

C) II and III

D) II and IV

E) I and IV

Diff: 2

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

57) What is the structure of the monomer(s) that would produce the condensation polymer shown?

An illustration depicts a condensation polymer. The polymer has three six membered benzene rings. The C 5 of the first benzene ring is bonded to an oxygen atom, O, which is further bonded to a carbon atom. This carbon atom is double bonded to an oxygen atom. A wavy line is present on this single bond. The C 3 of the first benzene ring is bonded to an oxygen atom which is further bonded to a carbon atom. This carbon atom is double bonded to an oxygen atom and single bonded to another oxygen atom. This oxygen atom is bonded to C 5 of the second benzene ring. The C 3 of the second benzene ring is bonded to an oxygen atom which is further bonded to a carbon atom. This carbon atom is double bonded to an oxygen atom and single bonded to another oxygen atom. This oxygen atom is bonded to C 5 of the third benzene ring. The C 3 of the third benzene ring is bonded to an oxygen atom which is single bonded to a carbon atom. This carbon atom is double bonded to an oxygen atom.

An illustration depicts four compounds. The first compound labeled as Roman numeral one has a SMILES string of c1cc(cc(c1)Cl)Cl. The second compound labeled as Roman numeral two has a SMILES string of c1cc(cc(c1)O)O. The third compound labeled as Roman numeral three has a SMILES string of CC(=O)C. The fourth compound labeled as Roman numeral four has a SMILES string of C(=O)(Cl)Cl.

A) I and II

B) I and III

C) II and III

D) II and IV

E) I and IV

Diff: 2

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

58) What is the structure of the monomer(s) that would produce the condensation polymer shown?

An illustration depicts a condensation polymer. The polymer has an 18 carbon chain, in which C 1, C 7, and C 13 each is double bonded to an oxygen atom. C 2, C 6, C 8, C 12, and C 14 each is replaced by an oxygen atom. C 4, C 10, and C 16 each is bonded to a methyl group. The terminal carbon atoms are also bonded to a wavy bond.

An illustration depicts four compounds. The first compound labeled as Roman numeral one has a SMILES string of CC(=O)C. The second compound labeled as Roman numeral two has a SMILES string of C(=O)(Cl)Cl. The third compound labeled as Roman numeral three has a SMILES string of CC(C=O)C=O. The fourth compound labeled as Roman numeral four has a SMILES string of CC(CO)CO.

A) I and II

B) I and III

C) II and III

D) II and IV

E) I and IV

Diff: 2

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

59) Provide the structure of a region of the polymer that is produced when phosgene is treated with 3,3-dimethyl-1,5-pentanediol.

Five chemical structures depicting the different regions of a polymer are as follows: The first structure labeled as Roman numeral 1 has a 24 carbon chain, in which C 1, C 9, and C 13 each is bonded to a hydroxyl group. C 2, C 8, C 10, C 16, C 18, C 24 each is replaced by an oxygen atom. C 5, C 13, and C 21 each is bonded to two methyl groups. C 1 and C 24 are also bonded to a wavy bond. The second structure labeled as Roman numeral 2 has a 24 carbon chain, in which C 1, C 9, and C 13 each is double bonded to an oxygen atom. C 2, C 8, C 10, C 16, C 18, C 24 each is replaced by an oxygen atom. C 5, C 13, and C 21 each is bonded to two methyl groups. C 1 and C 24 are also bonded to a wavy bond. The third structure labeled as Roman numeral 3 has 24 carbon chain, in which C 1, C 9, and C 17 each is double bonded to an oxygen atom. C 1 and C 24 are also bonded to a wavy bond. The fourth structure labeled as Roman numeral 4 has a 24 carbon chain, in which C 1, C 9, and C 17 each is double bonded to an oxygen atom. C 2, C 8, C 10, C 16, C 18, C 24 each is replaced by an oxygen atom. C 5, C 13, and C 21 each is bonded to two methyl groups. C 1 and C 24 are also bonded to a wavy bond. The fifth structure labeled as Roman numeral 5 has a 24 carbon chain, in which C 1, C 9, and C 17 each is double bonded to an oxygen atom. C 5, C 13, and C 21 each is bonded to two methyl groups. C 1 and C 24 are also bonded to a wavy bond.

A) I

B) II

C) III

D) IV

E) V

Diff: 2

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

60) Provide the structure of a region of the polymer that is produced when the given monomers are treated in the presence of dilute NaOH.

An illustration depicts the reaction of two compounds. The first compound has a formula that reads, C l C double bond O, O, left parenthesis, C H 2, right parenthesis, 6, O, C, double bond O, C, l. The second compound has a formula that reads, H 2 N, left parenthesis, C H 2, right parenthesis, 4, N H 2.

Five chemical structures depicting the different regions of a polymer are as follows: The first structure has a 34 carbon chain, in which C 1, C 10, C 17, C 26, and C 33 each is double bonded to an oxygen atom. C 2, C 9, C 18, C 25, and C 34 each is replaced by an oxygen atom. C 11, C 16, C 27, and C 32 each is replaced by an N H group. The terminal carbon atoms are bonded to a wavy bond. The second structure has a 34 carbon chain, in which C 1, C 10, C 17, C 26, and C 33 each is double bonded to an oxygen atom. C 11, C 16, C 27, and C 32 each is replaced by an N H group. The terminal carbon atoms are bonded to a wavy bond. The third structure has a linear chain of a 34 carbon chain, in which C 1, C 10, C 17, C 26, and C 33 each is double bonded to an oxygen atom. C 2, C 9, C 18, C 25, and C 34 each is replaced by an oxygen atom. The terminal carbon atoms are bonded to a wavy bond. The fourth structure has a 34 carbon chain, in which C 1, C 10, C 17, C 26, and C 33 each is single bonded to a hydroxyl group. C 2, C 9, C 18, C 25, and C 34 each is replaced by an oxygen atom. C 11, C 16, C 27, and C 32 each is replaced by an N H group. The terminal carbon atoms are bonded to a wavy bond. The fifth structure has a 34 carbon chain, in which C 1, C 10, C 17, C 26, and C 33 each is double bonded to an oxygen atom. C 2, C 9, C 18, C 25, and C 34 each is replaced by an oxygen atom. C 16, C 27, and C 32 each is replaced by an N H group. The terminal carbon atoms are bonded to a wavy bond.

A) I

B) II

C) III

D) IV

E) V

Diff: 2

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

61) What monomers form PET?

A) terephthalic acid and ethylene glycol

B) phosgene and ethylene glycol

C) terephthalic acid and propylene glycol

D) urethane and carbamate

E) terephthalic acid and carbamate

Diff: 2

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

62) What monomers form Nylon 6,6?

A) adipic acid and ethylene glycol

B) phosgene and 1,6-hexandiamine

C) terephthalic acid and 1,6-hexandiamine

D) adipic acid and 1,6-hexandiamine

E) terephthalic acid and carbamate

Diff: 2

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

63) What monomers form Lexan?

A) adipic acid and Bisphenol-A

B) phosgene and 1,6-hexandiamine

C) terephthalic acid and 1,6-hexandiamine

D) adipic acid and 1,6-hexandiamine

E) phosgene and Bisphenol-A

Diff: 2

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

64) Identify the type of compound used to make safety goggles.

A) polyester

B) polyamide

C) polyether

D) polyalcohol

E) polycarbonate

Diff: 2

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

65) What is not an example of a small molecule that is released in a condensation reaction?

A) water

B) carbon dioxide

C) nitrogen gas

D) benzene

Diff: 2

Learning Objective: 27.4 Discuss the reaction types that can be used in the synthesis of addition and condensation polymers

66) Which of the choices are examples of chain growth polymerization?

A) radical polymerization

B) cationic polymerization

C) anionic polymerization

D) condensation polymerization

E) A, B and C

Diff: 1

Learning Objective: 27.5 Compare the processes involved in the formation of chain-growth and step-growth polymers

67) Which of the choices are examples of step growth polymerization?

A) radical polymerization

B) cationic polymerization

C) anionic polymerization

D) condensation polymerization

E) none of these

Diff: 1

Learning Objective: 27.5 Compare the processes involved in the formation of chain-growth and step-growth polymers

68) Which of the given polymerization processes best describes the formation of polycarbonates?

A) step growth addition

B) chain growth addition

C) step growth condensation

D) chain growth condensation

E) none of these

Diff: 2

Learning Objective: 27.5 Compare the processes involved in the formation of chain-growth and step-growth polymers

69) Which of the given polymerization processes best describes the formation of polyurethanes?

A) step growth addition

B) chain growth addition

C) step growth condensation

D) chain growth condensation

E) none of these

Diff: 2

Learning Objective: 27.5 Compare the processes involved in the formation of chain-growth and step-growth polymers

70) Which of the given polymerization processes best describes the formation of polyisobutylene?

A) step growth addition

B) chain growth addition

C) step growth condensation

D) chain growth condensation

E) none of these

Diff: 2

Learning Objective: 27.5 Compare the processes involved in the formation of chain-growth and step-growth polymers

71) What are the monomers in a polyurethane?

A) isocyanate and alcohol

B) diisocyanate and diol

C) ester and amine

D) carboxylic acid and amine

E) amide and alcohol

Diff: 2

Learning Objective: 27.5 Compare the processes involved in the formation of chain-growth and step-growth polymers

72) ________ polymers are formed under conditions in which the individual monomers react with each other to form oligomers, which are then joined to form polymers.

A) Step growth

B) Chain growth

C) Branched

D) Graft

E) none of these

Diff: 2

Learning Objective: 27.5 Compare the processes involved in the formation of chain-growth and step-growth polymers

73) What is the classification of the polymer shown?

An illustration depicts a polymer. The polymer has three six membered benzene rings. The C 1 of the first benzene ring is bonded to N H which is further bonded to another carbon atom. This carbon atom is double bonded to an oxygen atom and single bonded to another element. A wavy line is present on this single bond. The C 4 of the first benzene ring is bonded to N H which is further bonded to a carbon atom. This carbon atom is double bonded to an oxygen atom and single bonded to another oxygen atom. The single bonded oxygen atom is further bonded to a linear chain of three carbon atoms. From left to right, the C 2 is bonded to a methyl group and C 3 is bonded to an oxygen atom. This oxygen atom is further bonded to a carbon atom which is then double bonded to an oxygen atom and single bonded to N H. The N H is then single bonded to C 1 of the second benzene ring. The C 4 of the second benzene ring is bonded to N H which is further bonded to a carbon atom. This carbon atom is double bonded to an oxygen atom and single bonded to another oxygen atom. The single bonded oxygen atom is further bonded to a linear chain of three carbon atoms. From left to right, the C 2 is bonded to a methyl group and C 3 is bonded to an oxygen atom. This oxygen atom is further bonded to a carbon atom which is then double bonded to an oxygen atom and single bonded to N H. The N H is then single bonded to C 1 of the third benzene ring. The C 4 of the third benzene ring is bonded to N H which is further bonded to a carbon atom. This carbon atom is double bonded to an oxygen atom and single bonded to another element. A wavy line is present on this single bond.

A) polyester

B) polyamide

C) polyurethane

D) polycarbonate

E) none of these

Diff: 2

Learning Objective: 27.5 Compare the processes involved in the formation of chain-growth and step-growth polymers

74) What monomer(s) would produce the polymer shown?

An illustration depicts a polymer. The polymer has three six membered benzene rings. The C 1 of the first benzene ring is bonded to N H which is further bonded to another carbon atom. This carbon atom is double bonded to an oxygen atom and single bonded to another element. A wavy line is present on this single bond. The C 4 of the first benzene ring is bonded to N H which is further bonded to a carbon atom. This carbon atom is double bonded to an oxygen atom and single bonded to another oxygen atom. The single bonded oxygen atom is further bonded to a linear chain of three carbon atoms. From left to right, the C 2 is bonded to a methyl group and C 3 is bonded to an oxygen atom. This oxygen atom is further bonded to a carbon atom which is then double bonded to an oxygen atom and single bonded to N H. The N H is then single bonded to C 1 of the second benzene ring. The C 4 of the second benzene ring is bonded to N H which is further bonded to a carbon atom. This carbon atom is double bonded to an oxygen atom and single bonded to another oxygen atom. The single bonded oxygen atom is further bonded to a linear chain of three carbon atoms. From left to right, the C 2 is bonded to a methyl group and C 3 is bonded to an oxygen atom. This oxygen atom is further bonded to a carbon atom which is then double bonded to an oxygen atom and single bonded to N H. The N H is then single bonded to C 1 of the third benzene ring. The C 4 of the third benzene ring is bonded to N H which is further bonded to a carbon atom. This carbon atom is double bonded to an oxygen atom and single bonded to another element. A wavy line is present on this single bond.

An illustration depicts four monomers. The first monomer labeled as Roman numeral one has a SMILES string of c1cc(ccc1N=C=O)N=C=O. The second monomer labeled as Roman numeral two has a SMILES string of CC(CO)CO. The third monomer labeled as Roman numeral three has a benzene ring in which C 1 and C 4 atoms each are bonded to a nitrogen atom. This nitrogen atom is double bonded to a carbon atom. The carbon atom is bonded to a methyl group. The fourth monomer labeled as Roman numeral four has a SMILES string of CCC(C)CC.

A) I and II

B) I and III

C) II and III

D) II and IV

E) I and IV

Diff: 2

Learning Objective: 27.5 Compare the processes involved in the formation of chain-growth and step-growth polymers

75) Provide the structure of a region of the polymer that is produced when isocyanate, shown below, is treated with 1,4-butanediol.

An illustration depicts the reaction of two compounds. The first compound has a formula that reads, O double bond C double bond N left parenthesis, C H 2, right parenthesis, 4, N double bond C double bond O. The second compound reads, 1, 4 hyphen butanediol.

Five chemical structures depicting the different regions of a polymer are as follows: The first structure has a 31 carbon chain, in which C 1, C 10, C 15, C 24, and C 29 each is replaced by an N H group. C 2, C 9, C 16, C 23, C 30 each is double bonded to an oxygen atom. The terminal carbon atoms are bonded to a wavy bond. The second structure has a 31 carbon chain, in which C 2, C 9, C 16, C 23, and C 30 each is double bonded to an oxygen atom. C 3, C 8, C 17, C 22, and C 31 each is replaced by an oxygen atom. The terminal carbon atoms are bonded to a wavy bond. The third structure has a 31 carbon chain, in which C 1, C 10, C 15, C 24, and C 29 each is replaced by an N H group. C 2, C 9, C 16, C 23, and C 30 each is double bonded to an oxygen atom. C 3, C 8, C 17, C 22, and C 31 each is replaced by an oxygen atom. The terminal carbon atoms are bonded to a wavy bond. The fourth structure has a 31 carbon chain, in which C 1, C 15, and C 29 each is replaced by an N H group. C 2, C 9, C 16, C 23, and C 30 each is double bonded to an oxygen atom. C 3, C 8, C 17, C 22, and C 31 each is replaced by an oxygen atom. The terminal carbon atoms are bonded to a wavy bond. The fifth structure has a 31 carbon chain, in which C 1, C 10, C 15, C 24, and C 29 each is replaced by an N H group. C 2, C 16, and C 30 each is single bonded to a methyl group. C 3, C 8, C 17, C 22, and C 31 each is replaced by an oxygen atom. C 9, C 23, each is double to an oxygen atom. The terminal carbon atoms are bonded to a wavy bond.

A) I

B) II

C) III

D) IV

E) V

Diff: 2

Learning Objective: 27.5 Compare the processes involved in the formation of chain-growth and step-growth polymers

76) What is the polymer that is used in bullet-proof vests?

A) Nylon 6

B) Teflon

C) Kevlar

D) Lexan

E) Nylon 6,6

Diff: 1

Learning Objective: 27.5 Compare the processes involved in the formation of chain-growth and step-growth polymers

77) What polymer is used in bicycle helmets?

A) Nylon 6

B) Teflon

C) Kevlar

D) Lexan

E) Nylon 6,6

Diff: 1

Learning Objective: 27.5 Compare the processes involved in the formation of chain-growth and step-growth polymers

78) What polymer is used in rope?

A) Nylon 6

B) Teflon

C) Kevlar

D) Lexan

E) Nylon 6,6

Diff: 1

Learning Objective: 27.8 Discuss the limitations on recycling polymers, and the potential benefits of biodegradable polymers

79) Which of the given statements is(are) true about linear polymers?

A) they are highly branched

B) they may be slightly branched

C) they can have no branching

D) A and B

E) B and C

Diff: 1

Learning Objective: 27.6 Compare branched, linear, and cross-linked polymers, isotactic, syndiotactic, and atactic polymers, and compare crystalline and amorphous polymers

80) Which of the choices best describes the polymer shown?

An illustration depicts a polymer. The structure has an 11 carbon chain, in which C 1, C 3, C 5, C 7, C 9, and C 11 each is wedge boded to a methyl group. The C 1 and C 11 are also bonded to a wavy bond.

A) atactic

B) isotactic

C) syndiotactic

D) antidiotactic

E) none of these

Diff: 1

Learning Objective: 27.6 Compare branched, linear, and cross-linked polymers, isotactic, syndiotactic, and atactic polymers, and compare crystalline and amorphous polymers

81) Which of the choices best describes the polymer shown?

An illustration depicts a polymer. The structure has an 11 carbon chain, in which C 1, C 5, and C 9 each is wedge boded to a methyl group. C 3, C 7, and C 11 each is dash boded to a methyl group. C 1 and C 11 are also bonded to a wavy bond.

A) atactic

B) isotactic

C) syndiotactic

D) antidiotactic

E) none of these

Diff: 1

Learning Objective: 27.6 Compare branched, linear, and cross-linked polymers, isotactic, syndiotactic, and atactic polymers, and compare crystalline and amorphous polymers

82) Which of the choices best describes the polymer shown?

An illustration depicts a polymer. The structure has an 11 carbon chain, in which C 1, C 5, and C 11 each is wedge boded to a methyl group. C 3, C 7, and C 9 each is dash boded to a methyl group. C 1 and C 11 are also bonded to a wavy bond.

A) atactic

B) isotactic

C) syndiotactic

D) antidiotactic

E) none of these

Diff: 1

Learning Objective: 27.6 Compare branched, linear, and cross-linked polymers, isotactic, syndiotactic, and atactic polymers, and compare crystalline and amorphous polymers

83) An isotactic polymer has a ________ configuration.

A) random

B) alternating

C) same

D) block

E) graft

Diff: 1

Learning Objective: 27.6 Compare branched, linear, and cross-linked polymers, isotactic, syndiotactic, and atactic polymers, and compare crystalline and amorphous polymers

84) An atactic polymer has a ________ configuration.

A) random

B) alternating

C) same

D) block

E) graft

Diff: 1

Learning Objective: 27.6 Compare branched, linear, and cross-linked polymers, isotactic, syndiotactic, and atactic polymers, and compare crystalline and amorphous polymers

85) A syndiotactic polymer has a ________ configuration.

A) random

B) alternating

C) same

D) block

E) graft

Diff: 1

Learning Objective: 27.6 Compare branched, linear, and cross-linked polymers, isotactic, syndiotactic, and atactic polymers, and compare crystalline and amorphous polymers

86) Draw a possible segment of atactic polyacrylonitrile.

An illustration depicts five compounds. The first compound labeled as Roman numeral one has a 12 carbon chain, in which C 1, C 3, C 5, C 7, C 9, and C 11 each is wedge bonded to a cyanide group. C 1 is also bonded to a wavy bond. The second compound labeled as Roman numeral two has a 12 carbon chain, in which C 1, C 5, and C 9 each is wedge bonded to a cyanide group. C 3, C 7, and C 11 each is dash bonded to a cyanide group. C 1 is also bonded to a wavy bond. The third compound labeled as Roman numeral three has a 12 carbon chain, in which C 1, C 5, and C 11 each is wedge bonded to a cyanide group. C 3, C 7, and C 9 each is dash bonded to a cyanide group. C 1 is also bonded to a wavy bond. The fourth compound labeled as Roman numeral four has a 12 carbon chain, in which C 1, C 3, C 5, C 7, C 9, and C 11 each is dash bonded to a cyanide group. C 1 is also bonded to a wavy bond. The fifth compound labeled as Roman numeral five has a 12 carbon chain, in which C 1, C 5, and C 9 each is dash bonded to a cyanide group. C 3, C 7, and C 11 each is wedge bonded to a cyanide group. C 1 is also bonded to a wavy bond.

A) I

B) II

C) III

D) IV

E) V

Diff: 2

Learning Objective: 27.6 Compare branched, linear, and cross-linked polymers, isotactic, syndiotactic, and atactic polymers, and compare crystalline and amorphous polymers

87) Draw a possible segment of isotactic polyacrylonitrile.

An illustration depicts five compounds. The first compound labeled as Roman numeral one has a 12 carbon chain, in which C 1, C 3, C 5, C 7, C 9, and C 11 each is wedge bonded to a cyanide group. C 1 is also bonded to a wavy bond. The second compound labeled as Roman numeral two has a 12 carbon chain, in which C 1, C 5, and C 9 each is wedge bonded to a cyanide group. C 3, C 7, and C 11 each is dash bonded to a cyanide group. C 1 is also bonded to a wavy bond. The third compound labeled as Roman numeral three has a 12 carbon chain, in which C 1, C 5, and C 11 each is wedge bonded to a cyanide group. C 3, C 7, and C 9 each is dash bonded to a cyanide group. C 1 is also bonded to a wavy bond. The fourth compound labeled as Roman numeral four has a 12 carbon chain, in which C 1, C 7, and C 9 each is dash bonded to a cyanide group. C 3, C 5, and C 11 each is wedge bonded to a cyanide group. C 1 is also bonded to a wavy bond. The fifth compound labeled as Roman numeral five has a 12 carbon chain, in which C 1, C 5, and C 9 each is dash bonded to a cyanide group. C 3, C 7, and C 11 each is wedge bonded to a cyanide group. C 1 is also bonded to a wavy bond.

A) I

B) II

C) III

D) IV

E) V

Diff: 2

Learning Objective: 27.6 Compare branched, linear, and cross-linked polymers, isotactic, syndiotactic, and atactic polymers, and compare crystalline and amorphous polymers

88) Draw a possible segment of syndiotactic polyacrylonitrile.

An illustration depicts five compounds. The first compound labeled as Roman numeral one has a 12 carbon chain, in which C 1, C 3, C 5, C 7, C 9, and C 11 each is wedge bonded to a cyanide group. C 1 is also bonded to a wavy bond. The second compound labeled as Roman numeral two has a 12 carbon chain, in which C 1, C 3, C 5, and C 9 each is wedge bonded to a cyanide group. C 7, and C 11 each is dash bonded to a cyanide group. C 1 is also bonded to a wavy bond. The third compound labeled as Roman numeral three has a 12 carbon chain, in which C 1, C 5, and C 11 each is wedge bonded to a cyanide group. C 3, C 7, and C 9 each is dash bonded to a cyanide group. C 1 is also bonded to a wavy bond. The fourth compound labeled as Roman numeral four has a 12 carbon chain, in which C 1, C 7, and C 9 each is dash bonded to a cyanide group. C 3, C 5, and C 11 each is wedge bonded to a cyanide group. C 1 is also bonded to a wavy bond. The fifth compound labeled as Roman numeral five has a 12 carbon chain, in which C 1, C 5, and C 9 each is dash bonded to a cyanide group. C 3, C 7, and C 11 each is wedge bonded to a cyanide group. C 1 is also bonded to a wavy bond.

A) I

B) II

C) III

D) IV

E) V

Diff: 2

Learning Objective: 27.6 Compare branched, linear, and cross-linked polymers, isotactic, syndiotactic, and atactic polymers, and compare crystalline and amorphous polymers

89) Draw a possible segment of syndiotactic poly(vinyl fluoride).

An illustration depicts five compounds. The first compound labeled as Roman numeral one has a 12 carbon chain, in which C 1, C 3, C 5, C 7, C 9, and C 11 each is wedge bonded to a fluorine atom. C 1 is also bonded to a wavy bond. The second compound labeled as Roman numeral two has a 12 carbon chain, in which C 1, C 3, C 5, and C 9 each is wedge bonded to a fluorine atom. C 7, and C 11 each is dash bonded to a fluorine atom. C 1 is also bonded to a wavy bond. The third compound labeled as Roman numeral three has a 12 carbon chain, in which C 1, C 5, and C 11 each is wedge bonded to a fluorine atom. C 3, C 7, and C 9 each is dash bonded to a fluorine atom. C 1 is also bonded to a wavy bond. The fourth compound labeled as Roman numeral four has a 12 carbon chain, in which C 1, C 5, and C 9 each is dash bonded to a fluorine atom. C 3, C 7, and C 11 each is wedge bonded to a fluorine atom. C 1 is also bonded to a wavy bond. The fifth compound labeled as Roman numeral five has a 12 carbon chain, in which C 1, C 3, C 5, C 7, C 9, and C 11 each is dash bonded to a fluorine atom. C 1 is also bonded to a wavy bond.

A) I

B) II

C) III

D) IV

E) V

Diff: 2

Learning Objective: 27.6 Compare branched, linear, and cross-linked polymers, isotactic, syndiotactic, and atactic polymers, and compare crystalline and amorphous polymers

90) Draw a possible segment of isotactic poly(vinyl acetate).

An illustration depicts five compounds. The first compound labeled as Roman numeral one has a 12 carbon chain, in which C 1, C 5, and C 9 each is wedge bonded to an acetoxy group. C 3, C 7, C 11 each is dash bonded to an acetoxy group. C 1 is also bonded to a wavy bond. The second compound labeled as Roman numeral two has a 12 carbon chain, in which C 1, C 3, C 5, C 7, C 9, and C 11 each is wedge bonded to an acetoxy group. C 1 is also bonded to a wavy bond. The third compound labeled as Roman numeral three has a 12 carbon chain, in which C 1, C 5, and C 11 each is wedge bonded to an acetoxy group. C 3, C 7, and C 9 each is dash bonded to an acetoxy group. C 1 is also bonded to a wavy bond. The fourth compound labeled as Roman numeral four has a 12 carbon chain, in which C 1, C 5, and C 9 each is dash bonded to an acetoxy group. C 3, C 7, and C 11 each is wedge bonded to an acetoxy group. C 1 is also bonded to a wavy bond. The fifth compound labeled as Roman numeral five has a 12 carbon chain, in which C 1, C 5, and C 9, each is wedge bonded to an acetoxy group. C 3, C 7, and C 11 is dash bonded to an acetoxy group. C 1 is also bonded to a wavy bond.

A) I

B) II

C) III

D) IV

E) V

Diff: 2

Learning Objective: 27.6 Compare branched, linear, and cross-linked polymers, isotactic, syndiotactic, and atactic polymers, and compare crystalline and amorphous polymers

91) Polymerization of ethylene in the presence of a Ziegler-Natta catalyst results in ________.

A) LDPE

B) MDPE

C) HDPE

D) B and C

E) none of these

Diff: 2

Learning Objective: 27.6 Compare branched, linear, and cross-linked polymers, isotactic, syndiotactic, and atactic polymers, and compare crystalline and amorphous polymers

92) Free radical polymerization of ethylene results in ________.

A) LDPE

B) MDPE

C) HDPE

D) B and C

E) none of these

Diff: 2

Learning Objective: 27.8 Discuss the limitations on recycling polymers, and the potential benefits of biodegradable polymers

93) Which of the given types of polyethylene is used to make trash bags?

A) HDPE

B) LDPE

C) MDPE

D) A and C

E) none of these

Diff: 2

Learning Objective: 27.6 Compare branched, linear, and cross-linked polymers, isotactic, syndiotactic, and atactic polymers, and compare crystalline and amorphous polymers

94) Which of the given types of polyethylene is used to make Tupperware?

A) HDPE

B) LDPE

C) MDPE

D) A and C

E) none of these

Diff: 2

Learning Objective: 27.6 Compare branched, linear, and cross-linked polymers, isotactic, syndiotactic, and atactic polymers, and compare crystalline and amorphous polymers

95) Vulcanization of rubber results in ________ between the neighboring chains of the polymer.

A) hydrogen bonding

B) salt bridges

C) phosphide bridges

D) disulfide bridges

E) none of these

Diff: 2

Learning Objective: 27.6 Compare branched, linear, and cross-linked polymers, isotactic, syndiotactic, and atactic polymers, and compare crystalline and amorphous polymers

96) Which of the given elements is used during the vulcanization of rubber?

A) silicon

B) aluminum

C) sulfur

D) phosphorous

E) silver

Diff: 2

Learning Objective: 27.6 Compare branched, linear, and cross-linked polymers, isotactic, syndiotactic, and atactic polymers, and compare crystalline and amorphous polymers

97) Neoprene, which is used in gaskets, electrical insulation, and other products, has the structure shown. What is the structure of the monomer?

An illustration depicts a monomer structure. The structure has a 12 carbon chain, in which C 2, C 6, and C 10 is double bonded to C 3, C 7, and C 11 respectively. C 2, C 6, and C 10 each is also single bonded to a chlorine atom. The terminal carbon atoms are bonded to a wavy bond.

An illustration depicts five products. The first product labeled as Roman numeral one has a SMILES string of C=C(C(=C)Cl)Cl. The second product labeled as Roman numeral two has a SMILES string of CCC(=C)Cl. The third product labeled as Roman numeral three has a SMILES string of CC(C=C)Cl. The fourth product labeled as Roman numeral four has a SMILES string of C=CC(=C)Cl. The fifth compound labeled as Roman numeral five has a SMILES string of CC(C(C)Cl)Cl.

A) I

B) II

C) III

D) IV

E) V

Diff: 2

Learning Objective: 27.6 Compare branched, linear, and cross-linked polymers, isotactic, syndiotactic, and atactic polymers, and compare crystalline and amorphous polymers

98) SBR (styrene-butadiene rubber) is used in the manufacturing of automobile tires. What is the structure of a region of this polymer?

An illustration depicts five chemical structure. The first structure labeled as Roman numeral 1 has a linear carbon chain of 18 carbon atoms. From right to left, C 1 atom is bonded to a methyl group and a wavy line is present on the bonded line. The C 6, C 12, C 18 atoms are bonded to a six membered benzene ring. The C 18 atom is also bonded to a methyl group and a wavy line is present on the bonded line. The second structure labeled as Roman numeral 2 has a linear carbon chain of 18 carbon atoms. From right to left, C 1 atom is bonded to a methyl group and a wavy line is present on the bonded line. The C 2 and C 3 atoms are double bonded. The C 6 atom is bonded to a six membered cyclohexane ring. The C 8 and C 9 atoms are double bonded. The C 12 atom is bonded to a six membered benzene ring. The C 14 and C 15 atoms are double bonded. The C 18 atom is bonded to a methyl group and a wavy line is present on the bonded line. The C 18 atom is also bonded to a six membered cyclohexane ring. The third structure labeled as Roman numeral 3 has a linear carbon chain of 18 carbon atoms. From right to left, C 1 atom is bonded to a methyl group and a wavy line is present on the bonded line. The C 2 and C 3 atoms are double bonded. The C 6 atom is bonded to a six membered benzene ring. The C 8 and C 9 atoms are double bonded. The C 12 atom is bonded to a six membered benzene ring. The C 14 and C 15 atoms are double bonded. The C 18 atom is bonded to a methyl group and a wavy line is present on the bonded line. The C 18 atom is also bonded to a six membered benzene ring. The fourth structure labeled as Roman numeral 4 has a linear carbon chain of 18 carbon atoms. From right to left, atom is bonded to a methyl group and a wavy line is present on the bonded line. The C 2 and C 3 atoms are double bonded. The C 6 atom is bonded to a six membered cyclohexane ring. The C 8 and C 9 atoms are double bonded. The C 12 atom is bonded to a six membered benzene ring. The C 14 and C 15 atoms are double bonded. The C 18 atom is bonded to a methyl group and a wavy line is present on the bonded line. The C 18 atom is also bonded to a six membered cyclohexane ring. The fifth structure labeled as Roman numeral 5 has a linear carbon chain of 18 carbon atoms. From right to left, C 1 atom is bonded to a methyl group and a wavy line is present on the bonded line. The C 2 and C 3 atoms are double bonded. The C 4 and C 5 atoms are double bonded. The C 6 atom is bonded to a six membered benzene ring. The C 8 and C 9 atoms are double bonded. The C 10 and C 11 atoms are double bonded. The C 12 atom is bonded to a six membered benzene ring. The C 14 and C 15 atoms are double bonded. The C 16 and C 17 atoms are double bonded. The C 18 atom is bonded to a methyl group and a wavy line is present on the bonded line. The C 18 atom is also bonded to a six membered benzene ring.

A) I

B) II

C) III

D) IV

E) V

Diff: 2

Learning Objective: 27.6 Compare branched, linear, and cross-linked polymers, isotactic, syndiotactic, and atactic polymers, and compare crystalline and amorphous polymers

99) Which of the choices best describes crystallites?

A) crossed linked chains with disulfide bridges

B) linearly arranged chains held together by van der Waals forces

C) crossed linked chains held together by van der Waals forces

D) linearly arranged chains with disulfide bridges

E) hydrogen bonding between chains

Diff: 2

Learning Objective: 27.6 Compare branched, linear, and cross-linked polymers, isotactic, syndiotactic, and atactic polymers, and compare crystalline and amorphous polymers

100) ________ regions in polymers make the polymer hard and durable.

A) Amorphous

B) Cross linked

C) Crystalline

D) A and B

E) B and C

Diff: 2

Learning Objective: 27.6 Compare branched, linear, and cross-linked polymers, isotactic, syndiotactic, and atactic polymers, and compare crystalline and amorphous polymers

101) ________ regions in polymers make the polymer flexible.

A) Amorphous

B) Cross linked

C) Crystalline

D) B and C

E) none of these

Diff: 2

Learning Objective: 27.6 Compare branched, linear, and cross-linked polymers, isotactic, syndiotactic, and atactic polymers, and compare crystalline and amorphous polymers

102) The glass transition temperature (Tg), is the temperature at which the ________ regions of the polymers become ________.

A) crystalline; amorphous

B) amorphous; hard

C) crystalline; hard

D) amorphous; soft

E) none of these

Diff: 2

Learning Objective: 27.6 Compare branched, linear, and cross-linked polymers, isotactic, syndiotactic, and atactic polymers, and compare crystalline and amorphous polymers

103) The melt transition temperature (Tm), is the temperature at which the ________ regions of the polymers become ________.

A) crystalline; amorphous

B) amorphous; hard

C) crystalline; hard

D) non-crystalline; soft

E) none of these

Diff: 2

Learning Objective: 27.6 Compare branched, linear, and cross-linked polymers, isotactic, syndiotactic, and atactic polymers, and compare crystalline and amorphous polymers

104) Which of the given polymers are hard at room temperature and soft at high temperature?

A) fibers

B) elastomers

C) plasticizers

D) thermoplastics

E) thermosetting resins

Diff: 1

Learning Objective: 27.7 Describe thermoplastic polymers, elastomers, fibers, and thermosetting resins

105) Which of the given polymers is(are) classified as thermoplastics?

A) PVC

B) PET

C) LDPE

D) HDPE

E) all of these

Diff: 2

Learning Objective: 27.7 Describe thermoplastic polymers, elastomers, fibers, and thermosetting resins

106) Addition of ________ to thermoplastics increases flexibility of the polymer.

A) PVC

B) plasticizers

C) resins

D) LDPE

E) elastomers

Diff: 2

Learning Objective: 27.7 Describe thermoplastic polymers, elastomers, fibers, and thermosetting resins

107) Which one of the choices is the best classification of an amorphous polymer that is flexible?

A) fibers

B) elastomers

C) plasticizers

D) thermoplastics

E) thermosetting resins

Diff: 2

Learning Objective: 27.7 Describe thermoplastic polymers, elastomers, fibers, and thermosetting resins

108) Which of the given polymers is(are) classified as elastomers?

A) spandex

B) natural rubber

C) HDPE

D) A and B

E) all of these

Diff: 2

Learning Objective: 27.7 Describe thermoplastic polymers, elastomers, fibers, and thermosetting resins

109) Which of the choices best describe elastomers?

A) polymers that are hard at room temperature

B) polymers that return to original shape after being stretched

C) small molecules that are added to polymers to increase flexibility

D) polymers that can form fibers

E) none of these

Diff: 2

Learning Objective: 27.7 Describe thermoplastic polymers, elastomers, fibers, and thermosetting resins

110) Which of the choices is the best classification of crystalline polymers with high tensile strength?

A) fibers

B) elastomers

C) plasticizers

D) thermoplastics

E) thermosetting resins

Diff: 2

Learning Objective: 27.7 Describe thermoplastic polymers, elastomers, fibers, and thermosetting resins

111) Which of the choices is the best classification of chewing gum?

A) fibers

B) elastomers

C) plasticizers

D) thermoplastics

E) thermosetting resins

Diff: 1

Learning Objective: 27.7 Describe thermoplastic polymers, elastomers, fibers, and thermosetting resins

112) Which of the choices is the best classification of Nylon?

A) fibers

B) elastomers

C) plasticizers

D) thermoplastics

E) thermosetting resins

Diff: 1

Learning Objective: 27.7 Describe thermoplastic polymers, elastomers, fibers, and thermosetting resins

113) Which of the choices is the best classification of the polymer Bakelite?

A) fibers

B) elastomers

C) plasticizers

D) thermoplastics

E) thermosetting resins

Diff: 2

Learning Objective: 27.7 Describe thermoplastic polymers, elastomers, fibers, and thermosetting resins

114) The strength of the thermosetting polymers like Bakelite is due to ________.

A) cross linking

B) elastomers

C) plasticizers

D) thermoplastics

E) thermosetting resins

Diff: 2

Learning Objective: 27.7 Describe thermoplastic polymers, elastomers, fibers, and thermosetting resins

115) Which of the given monomer(s) are used to prepare the polymer Bakelite?

A) phenol and acetaldehyde

B) phenol and formaldehyde

C) phenol and methanol

D) thermoplastics

E) none of these

Diff: 2

Learning Objective: 27.7 Describe thermoplastic polymers, elastomers, fibers, and thermosetting resins

116) Which of the given functional groups are common in biodegradable polymers?

A) esters

B) amides

C) anhydrides

D) A and B

E) A and C

Diff: 2

Learning Objective: 27.8 Discuss the limitations on recycling polymers, and the potential benefits of biodegradable polymers

117) Which of the given processes is(are) used in the recycling of soft drink bottles made of PET?

A) esterification

B) acid hydrolysis

C) melting

D) B and C

E) none of these

Diff: 2

Learning Objective: 27.8 Discuss the limitations on recycling polymers, and the potential benefits of biodegradable polymers

118) Which of the given descriptions is(are) consistent with biodegradable polymers?

A) polymers that can be broken down by enzymes produced by microorganisms

B) polymers with ester moieties

C) polymers with amide moieties

D) polymers known as polyhydroxyalkanoates

E) all of these

Diff: 2

Learning Objective: 27.8 Discuss the limitations on recycling polymers, and the potential benefits of biodegradable polymers

119) Which choice best defines biogradable polymers?

A) Polymers made of natural substances.

B) Polymers that can be broken down by enzymes produced by soil microorganisms.

C) Polymers that can be recycled using standard means.

D) Polymers that contain only organic materials.

E) Polymers that are not harmful to the environment even if they persist in the environment for an extended time.

Diff: 2

Learning Objective: 27.8 Discuss the limitations on recycling polymers, and the potential benefits of biodegradable polymers

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Document Type:
DOCX
Chapter Number:
27
Created Date:
Aug 21, 2025
Chapter Name:
Chapter 27 Synthetic Polymers
Author:
David R. Klein

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