Test Bank + Answers Ch13 Kinetics: Mechanisms And Rates Of - Chemistry Canada 4e | Complete Test Bank by John A. Olmsted. DOCX document preview.

Test Bank + Answers Ch13 Kinetics: Mechanisms And Rates Of

CHAPTER 13

KINETICS: MECHANISMS AND RATES OF REACTIONS

CHAPTER STUDY OBJECTIVES

1. Explain the concepts of a mechanism and a rate-determining step in a chemical reaction.

SKILLS TO MASTER: Visualizing elementary reactions

KEY CONCEPTS: A reaction mechanism is the exact molecular pathway that starting materials follow on their way to becoming products. The overall reaction is the sum of the elementary steps in the mechanism. The rate-determining step is the slowest step in the reaction mechanism. The overall reaction cannot go faster than the rate-determining step.

2. Determine the rate of a reaction based on the rate of change of concentration of a reactant or a product.

SKILLS TO MASTER: Calculating reaction rates from concentration versus time data; calculating relative rates of reaction

KEY CONCEPTS: The reaction rate can be expressed using the rate of change of concentration of any of the reagents.

3. Determine the rate law, given the mechanism and knowledge of the relative rates of steps of a reaction.

SKILLS TO MASTER: Predicting the rate law from the reaction mechanism

KEY CONCEPTS: A reaction rate depends on the concentrations of the reactants as expressed by the rate law for that reaction. The order of a reactant often differs from its stoichiometric coefficient.

4. Determine rate laws from concentration versus time data.

SKILLS TO MASTER: Determining the rate law from isolation experiments; determining the rate law from the method of initial rates

KEY CONCEPTS: Rate laws must be determined from experimental data. The half-life of a first-order reaction is a constant. The half-life of a second-order reaction depends on the initial concentration.

5. Show that the mechanism and rate law are closely related.

SKILLS TO MASTER: Determining the rate law when the first step is rate determining; determining the rate law when a later step is rate determining; using the equilibrium (equality of rates) assumption

KEY CONCEPTS: The mechanism must be the sum of the elementary reactions, and must explain the experimentally observed rate law.

6. Explain and quantify the effects of temperature on a reaction rate.

SKILLS TO MASTER: Drawing and labelling an activation energy diagram for an elementary reaction; using the Arrhenius equation to calculate a rate constant as a function of temperature; using the Arrhenius equation to calculate an activation energy

KEY CONCEPTS: The activation energy is the minimum energy that must be supplied before a reaction can take place.

7. Explain the mechanisms by which catalysts function.

SKILLS TO MASTER: Recognizing the difference between a catalyst and an intermediate; describing the mechanism of heterogeneous catalysis; explaining the mechanism of catalysis by an enzyme

KEY CONCEPTS: A catalyst functions by providing a mechanism for which the rate-determining step has a lower activation energy.

Multiple Choice QUESTIONS

1. Which of the following are bimolecular processes?

I.

II. NO 🡪 ONNO

III. H2C = CHCH3 + H2SO4 🡪CH3CH(OSO2(OH))CH3

IV.

V. H2 🡪 2 H•

a) I and V

b) I, IV and V

c) II only

d) II and III

e) II, III and V

Difficulty: Easy

Learning Objective: Explain the concepts of a mechanism and a rate determining step in a chemical reaction.

Section Reference: 13.1 What Is a Reaction Mechanism?

2. Which of the following is an elementary reaction?

a) OH- + H3O+ 🡪 H2O

b) 4NO2 + O2 🡪 2N2O5

c) CO + 2H2 + CH4 🡪 C2H6 + H2O

d) N2 + 3H2 🡪 NH3

e) 2NO + 2H2 🡪 N2 + 2H2O

Difficulty: Easy

Learning Objective: Explain the concepts of a mechanism and a rate determining step in a chemical reaction.

Section Reference: 13.1 What Is a Reaction Mechanism?

Feedback: Elementary reactions are uni-, bi-, or occasionally trimolecular.

3. The formation of chlorocarbon solvents such as CH2Cl2 proceeds through the reaction of chlorine with methane. Which of the following is a unimolecular reaction in the mechanism?

a) CH4 + Cl• 🡪 CH3• + HCl

b) H2 🡪 2 H•

c) CH3• + Cl• 🡪 CH3Cl

d) Cl2 🡪 2 Cl•

e) CH2Cl• + Cl• 🡪 CH2Cl2

Difficulty: Hard

Learning Objective: Explain the concepts of a mechanism and a rate determining step in a chemical reaction.

Section Reference: 13.1 What Is a Reaction Mechanism?

4. It has been suggested that the decomposition of NO2 occurs via the following mechanism:

NO2 🡪 NO + O (Rxn I)

O + NO2 🡪 2NO + O2 (Rxn II)

Predict the rate determining step.

a) Rxn II; this reaction is bimolecular, bimolecular reactions are always slower than unimolecular reactions.

b) Rxn I; unimolecular reactions are always slower than bimolecular reactions.

c) Rxn I; O is highly reactive and thus Rxn II will be very fast.

d) Rxn II; NO2 is highly reactive and thus Rxn I will be very fast.

e) Rxn I and II are both elementary reactions and will proceed at equal rates.

Difficulty: Medium

Learning Objective: Explain the concepts of a mechanism and a rate determining step in a chemical reaction.

Section Reference: 13.1 What Is a Reaction Mechanism?

5. You are running late for a basketball game on your campus and you are thinking about what will be the rate determining step for attending the basketball game? Which of the following will be your rate determining step?

a) purchasing a ticket

b) locating a seat in the stands

c) walking/driving to the game

d) waiting for the players to arrive

e) giving your ticket to the doorman

Difficulty: Easy

Learning Objective: Explain the concepts of a mechanism and a rate determining step in a chemical reaction.

Section Reference: 13.1 What Is a Reaction Mechanism?

6. Which of the following sketches shows the proper orientation of molecules for CO2 reacting with NO to make NO2 and CO?

a)

b)

c)

d)

e)

Difficulty: Medium

Learning Objective: Explain the concepts of a mechanism and a rate determining step in a chemical reaction.

Section Reference: 13.1 What Is a Reaction Mechanism?

7. The synthesis of nitrogen monoxide proceeds by the reaction of ammonia with oxygen as shown in the following unbalanced reaction:

NH3(g) + O2(g) 🡪 NO(g) + H2O(g)

If O2 is being consumed at a rate of 32 mole/sec, what is the rate of NO production?

a) 38. mole/sec

b) 1.9 x 103 mole/minute

c) 15 x 103 mole/minute

d) 32 mole/minute

e) 1.4 x 105 mole/hour

Difficulty: Hard

Learning Objective: Determine the rate of a reaction based on the rate of change of concentration of a reactant or product.

Section Reference: 13.2 Rates of Chemical Reactions

8. Consider the aqueous phase reaction between the dichromate anion and iron (II) cations:

14 H3O+(aq) + Cr2O72- + 6Fe2+(aq) 🡪 2Cr3+(aq) + 21H2O

What is the reaction rate expressed in terms of changing H3O+ concentration?

a) Reaction rate =

b) Reaction rate = -

c) Reaction rate = -

d) Reaction rate =

Difficulty: Easy

Learning Objective: Determine the rate of a reaction based on the rate of change of concentration of a reactant or product.

Section Reference: 13.2 Rates of Chemical Reactions

Feedback: Concentration of H3O+ is decreasing, therefore reaction rate is negative.

9. Consider the aqueous phase reaction between hydrogen gas and liquid bromine:

H2(g) + Br2(g)🡪 2HBr(g)

Which of the following expressions accurately express the rate of the above reaction?

I. Reaction rate =

II. Reaction rate =

III. Reaction rate =

IV. Reaction rate =

a) I and III

b) I and II

c) II and IV

d) III and IV

e) I only

Difficulty: Easy

Learning Objective: Determine the rate of a reaction based on the rate of change of concentration of a reactant or product.

Section Reference: 13.2 Rates of Chemical Reactions

10. Consider the aqueous phase reaction between the dichromate anion and iron (II) cations:

14 H3O+(aq) + Cr2O72- + 6Fe2+(aq) 🡪 2Cr3+(aq) + 21H2O

What is the rate of increase of Cr3+ concentration expressed in terms of changing H3Oconcentration?

a)

b)

c)

d)

Difficulty: Medium

Learning Objective: Determine the rate of a reaction based on the rate of change of concentration of a reactant or product.

Section Reference: 13.2 Rates of Chemical Reactions

Feedback: Cr3+ concentration is increasing, but at 1/7th the rate that H3O+ concentration is decreasing.

11. Cyclohexane is manufactured from the reaction of benzene with hydrogen:

C6H6(g) + 3 H2(g) 🡪 C6H12(g)

If the initial concentration of hydrogen was 1.5 M and 5 minutes later the hydrogen concentration is 0.34 M, what is the average rate of disappearance of hydrogen?

a) 0.30 M/min

b) 0.20 M/min

c) 1.16 M/min

d) 0.23 M/min

e) 0.68 M/min

Difficulty: Easy

Learning Objective: Determine the rate of a reaction based on the rate of change of concentration of a reactant or product.

Section Reference: 13.2 Rates of Chemical Reactions

12. Cyclohexane is manufactured from the reaction of benzene with hydrogen:

C6H6(g) + 3 H2(g) 🡪 C6H12(g)

If the initial concentration of hydrogen was 1.5 M and 5 minutes later the hydrogen concentration is 0.34 M, what is the average rate of appearance of cyclohexane?

a) 0.39 M/min

b) 7.7 x 10-2 M/min

c) 4.6 M/s

d) 3.9 x 10- 2 M/hr

e) 2.3 M/min

Difficulty: Medium

Learning Objective: Determine the rate of a reaction based on the rate of change of concentration of a reactant or product.

Section Reference: 13.2 Rates of Chemical Reactions

13. NO2 decomposes to form NO and O2. The concentration of NO2 is monitored and found to be 2.1x10-2 M after 15 seconds and 1.8 x10-2 M after 20 seconds. What is the average rate of appearance of O2 over this time period?

a) 6.0x10-4 M/s

b) 1.2x10-3 M/s

c) 3.0x10-4 M/s

d) 3.0x10-3 M/s

e) 1.5x10-4 M/s

Difficulty: Medium

Learning Objective: Determine the rate of a reaction based on the rate of change of concentration of a reactant or product.

Section Reference: 13.2 Rates of Chemical Reactions

Feedback: Students must balance equation before determining average rate of O­2.

14. Why does the rate of a reaction generally slow with time?

a) The reaction mixture gets warmer.

b) The number of product molecules decreases.

c) The number of collisions of reactants decreases.

d) The number of product molecules increases.

e) The temperature of the reaction vessel decreases.

Difficulty: Easy

Learning Objective: Determine the rate of a reaction based on the rate of change of concentration of a reactant or product.

Section Reference: 13.2 Rates of Chemical Reactions

15. The rate of a reaction

a) increases with the concentration of reactants.

b) decreases with the concentration of reactants.

c) is independent of concentration.

d) is a function of reaction stoichiometry.

e) cannot be determined based on the balanced chemical reaction.

Difficulty: Easy

Learning Objective: Determine the rate law, given the mechanism and knowledge of the relative rates of steps of a reaction.

Section Reference: 13.3 Concentration and Reaction Rates

16. For the reaction I-(aq) + OCl-(aq) 🡪 IO-(aq) + Cl-(aq) in basic solution, it was found that

a) This reaction is first order overall.

b) This reaction is third order overall.

c) This reaction is second order overall.

d) This reaction is first order in [OH-] concentration.

e) The rate law is incorrect as OH- is neither a reactant nor a product.

Difficulty: Medium

Learning Objective: Determine the rate law, given the mechanism and knowledge of the relative rates of steps of a reaction.

Section Reference: 13.3 Concentration and Reaction Rates

17. A 1.66 x 10-4 mole sample of 239Pu undergoes 9 x 107 decays per second obeying first-order kinetics. How many decays per second would be expected from a 5.46 x 10-1 mole sample?

a) 9 x 108 decays/second

b) 3 x 109 decays/second

c) 9 x 1010 decays/second

d) 3 x 1011 decays/second

e) 9 x 1011 decays/second

Difficulty: Hard

Learning Objective: Determine the rate law, given the mechanism and knowledge of the relative rates of steps of a reaction.

Section Reference: 13.3 Concentration and Reaction Rates

18. The reaction A + 2B 🡪 products was found to have the rate law; rate = k[A] [B]2. While holding the concentration of A constant, the concentration of B was increased from 0.010M to 0.030M. Predict by what factor the rate of reaction will increase.

a) 3

b) 6

c) 9

d) 30

e) 27

Difficulty: Easy

Learning Objective: Determine the rate law, given the mechanism and knowledge of the relative rates of steps of a reaction.

Section Reference: 13.3 Concentration and Reaction Rates

19. The first-order rate constant for the decomposition of trioxane (C3H6O3) is known to be 3.05 x 10-4 s-1 at 519ºK. What is the half life of trioxane at 519ºK?

a) 3.28 x 103 s

b) 6.93 x103 s

c) 0.693 hour

d) 0.631 hour

e) 0.328 hour

Difficulty: Easy

Learning Objective: Determine rate laws from concentration versus time data.

Section Reference: 13.4 Experimental Kinetics

20. Butadiene reacts to form its dimmer according to the following reaction:

Concentration versus time data were collected for this reaction and a plot of 1/[C4H6] resulted in a straight line with slope 6.14 x10-2 M s-1. The integrated for of the rate law is

a)

b)

c)

d)

e)

Difficulty: Medium

Learning Objective: Determine rate laws from concentration versus time data.

Section Reference: 13.4 Experimental Kinetics

Feedback: a) based on 1st order reaction; b) 0th order reaction; c) correct answer; d) incorrect k; e) ½ life for 1st order reaction

21. It is determined that the charcoal in a fire pit used as an ancient hearth has lost about 42.3% of the initial 14C. How old was the fire pit if 14C has a half life of 5730 years?

a) 2210 years

b) 4430 years

c) 4550 years

d) 5250 years

e) 7750 years

Difficulty: Medium

Learning Objective: Determine rate laws from concentration versus time data.

Section Reference: 13.4 Experimental Kinetics

22. The following reaction takes place at 80.1°C:

Ru(NH3)5Cl2+ (aq) + H2O (l) 🡪 Ru(NH3)5(H2O)3+ (aq) + Cl- (aq)

The following time and concentration data are collected:

t (s)

[Ru(NH3)5Cl2+]

ln (Ru(NH3)5Cl2+)

1/(Ru(NH3)5Cl2+)

0

1.50 x 10-2

-4.20

66.7

1.00 x 10-3

1.08 x 10-2

-4.53

92.6

2.00.x 10-3

7.78 x 10-3

-4.86

128.5

3.00.x 10-3

5.61 x 10-3

-5.18

178.2

5.40.x 10-3

2.55 x 10-3

-5.97

392

1.01.x 10-2

5.46 x 10-4

-7.51

1830

4.00.x 10-2

3.01 x 10-8

-17.3

3.32 x107

Which of the following is the correct value of the rate constant?

a) 3.28 1/M•s

b) 4.19 1/s

c) 419 1/s

d) 328 1/M•s

e) 328 1/s

Difficulty: Hard

Learning Objective: Determine rate laws from concentration versus time data.

Section Reference: 13.4 Experimental Kinetics

23. Nitrous oxide, N2O, decomposes on metal surfaces readily at high temperatures following first-order kinetics for the equation:

2 N2O (g) 🡪 2 N2 (g) + O2 (g)

The following data are obtained for a reaction at 850°C:

t (min)

[N2O]

15

0.0835

30

0.068

80

0.035

120

0.022

What was the initial concentration of N2O (t = 0)?

a) 0.0885 M

b) 0.0940 M

c) 0.101 M

d) 0.112 M

e) 0.123 M

Difficulty: Medium

Learning Objective: Determine rate laws from concentration versus time data.

Section Reference: 13.4 Experimental Kinetics

24. The following are initial rate data for 2 NO + 2 H2 🡪 N2 + 2 H2O

Experiment

Initial [NO]

Initial [H2]

Initial Rate

1

0.20

0.12

0.066

2

0.20

0.24

0.13

3

0.20

0.36

0.20

4

0.40

0.12

0.26

5

0.60

0.12

0.59

What is the rate law?

a) Rate = k[NO]

b) Rate = k[H2]

c) Rate = k[NO][H2]

d) Rate = k[NO]2[H­2]

e) Rate = k[NO][H2]2

Difficulty: Hard

Learning Objective: Determine rate laws from concentration versus time data.

Section Reference: 13.4 Experimental Kinetics

25. The reaction of NO with O2 to give oxygen is known to follow a third order rate law

(rate = k[NO]2[O2]). Two possible mechanisms are shown below:

Mechanism 1

2 NO (g) + O2 (g) 🡪 2 NO2 (g) (slow)

Mechanism 2

2 NO (g) (NO)2 (g) (fast)

(NO)2 + O2 🡪 2 NO2 (slow)

Which of these two mechanisms is a more acceptable mechanism, based on the criteria given above?

a) Mechanism 1 because it is simpler

b) Mechanism 1 because its rate law is the same as the known rate law

c) Mechanism 2 because it only involves 2 steps

d) Mechanism 2 because only bimolecular processes are involved

e) Mechanism 1 because no unstable species are formed

Difficulty: Hard

Learning Objective: Show that the mechanism and rate law are closely related.

Section Reference: 13.5 Linking Mechanisms and Rate Laws

26. The following mechanism has been suggested for the decomposition of ozone, O3.

O3(g) O2(g) + O(g) (fast equilibrium)

O(g) + O3(g) 🡪 2 O2(g) (slow)

Consider the following statements in light of this mechanism:

I. The rate law is second order in O3.

II. The rate does not depend on the concentration of O2.

III. The reaction slows with increased O2 concentration.

IV. The rate law is second order.

V. Substances reacting with O atoms will speed up the reaction.

Which of the above statements are true?

a) II and V

b) II only

c) I and IV

d) I and III

e) II, IV and V

Difficulty: Medium

Learning Objective: Show that the mechanism and rate law are closely related.

Section Reference: 13.5 Linking Mechanisms and Rate Laws

27. What is the rate law associated with the following mechanism:

HCl + HCl H2Cl2

HCl + CH3CHCH2 CH3CHClCH3

H2Cl2 + CH3CHClCH3 🡪CH3CHClCH3 +2 HCl

Net: HCl(g) + CH3CHCH2(g) 🡪 CH3CHClCH3 (g)

a) rate = k[HCl]2[CH3CHCH2]

b) rate = k[HCl]3[CH3CHCH2]

c) rate = k[H2Cl2][CH3CHClCH3]

d) rate = k[HCl][CH3CHCH2]

e) rate = k[HCl]2

Difficulty: Hard

Learning Objective: Show that the mechanism and rate law are closely related.

Section Reference: 13.5 Linking Mechanisms and Rate Laws

Feedback a) incorrect power for HCl; b) correct answer; c) contains intermediates; d) based second reaction which is fast, equilibrium and not rate determining; e) based on first reaction which is fast, equilibrium and not rate determining

28. Hydrogen and iodine react to form HI. One possible mechanism is shown below:

I2(g) 2 I(g)

H2(g) + 2 I(g) 🡪2 HI(g)

Consider the following statements in light of this mechanism:

I. The rate law overall is second order.

II. The iodine atom is an intermediate.

III. The first step is the rate determining step.

IV. The second step is the fast step.

V. The second step is rate determining.

Which of the above statements are true?

a) II, III and IV

b) II and V

c) all except V

d) I and II only

e) I, II and V

Difficulty: Hard

Learning Objective: Show that the mechanism and rate law are closely related.

Section Reference: 13.5 Linking Mechanisms and Rate Laws

29. Heterogeneous catalysts are used in industrial processes because

I. they utilize more of the catalyst atoms.

II. it is easier to separate the products from the catalyst.

III. higher operating temperatures are readily obtained.

IV. they are more selective.

Which of the above statements are true?

a) I, II and III

b) II and III

c) III and IV

d) I and IV

e) II and IV

Difficulty: Medium

Learning Objective: Explain the mechanisms by which catalysts function.

Section Reference: 13.7 Catalysis

30. In which order do the following steps typically occur for reactions facilitated by heterogeneous catalysts:

I. Desorption of material

II. Adsorption on materials on catalyst surface

III. Reaction to form products

IV. Movement of bound species over catalyst surface

a) II, I, III, IV

b) II, IV, III, I

c) II, I, IV, III

d) II, III, IV, I

e) IV, II, III, I

Difficulty: Easy

Learning Objective: Explain the mechanisms by which catalysts function.

Section Reference: 13.7 Catalysis

31. Which of the following does NOT occur during a reaction facilitated by a heterogeneous catalyst?

a) rejuvenation of catalyst via desorption of products

b) migration of bound reactants over catalyst surface

c) bond reorganization at catalyst surface

d) absorption of reactants on catalyst surface

e) weakening of or breaking of bonds and formation of bonds/interactions with catalyst

Difficulty: Medium

Learning Objective: Explain the mechanisms by which catalysts function.

Section Reference: 13.7 Catalysis

Feedback: Heterogeneous catalysts adsorb reactants on the surface, rather than absorb reactants into the structure.

32. The saturation behaviour of enzyme systems (E + S) suggests that

a) reactions in the pocket/active site are not rate limiting.

b) binding to the active site will never be rate limiting.

c) release of product will never be rate limiting.

d) bimolecular reactions cannot happen.

e) different steps in a mechanism can be rate determining based on concentration.

Difficulty: Hard

Learning Objective: Explain the mechanisms by which catalysts function.

Section Reference: 13.7 Catalysis

ESSAY QUESTIONS

33. Write the overall equation of reaction for the following mechanism and identify the reaction intermediates:

Cl2 🡪 2 Cl•

Cl• + CO 🡪 COCl

COCl + Cl2 🡪 COCl2 + Cl•

2 Cl• 🡪 Cl2

Difficulty: Easy

Learning Objective: Explain the concepts of a mechanism and a rate determining step in a chemical reaction.

Section Reference: 13.1 What Is a Reaction Mechanism?

34. Write the overall equation of reaction for the following mechanism and identify the reaction intermediates:

2 NO2 🡪 NO3 + NO

NO3 + CO 🡪 CO2 + NO2

Difficulty: Medium

Learning Objective: Explain the concepts of a mechanism and a rate determining step in a chemical reaction.

Section Reference: 13.1 What Is a Reaction Mechanism?

35. The industrial production of 2-propanol involves the reaction of propene with sulphuric acid and then water. Write the second step of the mechanism if the following is the first step:

Difficulty: Hard

Learning Objective: Explain the concepts of a mechanism and a rate determining step in a chemical reaction.

Section Reference: 13.1 What Is a Reaction Mechanism?

36. Draw a molecular picture showing the termolecular process in which two NO molecules collide with an O2 molecule to give two molecules of NO2.

Difficulty: Medium

Learning Objective: Explain the concepts of a mechanism and a rate determining step in a chemical reaction.

Section Reference: 13.1 What Is a Reaction Mechanism?

37. Hydrogen peroxide decomposes according to the equation:

2 H2O2(aq) 🡪 2 H2O(l) + O2(g)

At 27˚C and 1 atm, a 50.0 ml sample of hydrogen peroxide decomposes at a rate that produces 10.0 ml/sec of O2(g). Assuming ideal behaviour

a) Determine the moles of oxygen produced per second.

b) Determine the change in molarity of H2O2 per second.

Difficulty: Hard

Learning Objective: Determine the rate of a reaction based on the rate of change of concentration of a reactant or product.

Section Reference: 13.2 Rates of Chemical Reactions

38. The following concentration vs. time data were collected for the reaction:

A + 2B 🡪C

time (s)

[A] (M)

[B] (M)

[C] ((M)

0.00

1.50 x 10-2

1.00 x 10-1

0.00

60.0

1.37 x 10-2

9.74 x 10-2

1.29 x 10-3

180.

1.15 x 10-2

9.29 x 10-2

3.55 x 10-3

420.

7.99 x 10-3

8.60 x 10-2

7.01 x 10-3

480.

7.30 x 10-3

8.46 x 10-2

7.70 x 10-3

600.

6.10 x 10-3

8.22 x 10-2

8.90 x 10-3

720.

5.09 x 10-3

8.02 x 10-2

9.91 x 10-3

900.

3.89 x 10-3

7.78 x 10-2

1.11 x 10-2

960.

3.55 x 10-3

7.71 x 10-2

1.14 x 10-2

Calculate for A, B and C for the following time differences:

(a) 0 and 60 s,

(b) 900 and 960 s,

(c) What is the rate of the reaction for part a)?

Difficulty: Hard

Learning Objective: Determine the rate of a reaction based on the rate of change of concentration of a reactant or product.

Section Reference: 13.2 Rates of Chemical Reactions

39. Consider the following three molecular pictures that represent the relative numbers of the two reactants involved in one step of the depletion of stratospheric ozone by chlorine atoms:

A

B

C

The equation for the elementary reaction and a molecular picture of the reaction process are shown below:

Cl• + O3🡪 ClO + O2

If the three samples represented by A, B and C are at the same temperature, what are the rates of reaction of B and C compared to that of A?

Difficulty: Medium

Learning Objective: Determine the rate law, given the mechanism and knowledge of the relative rates of steps of a reaction.

Section Reference: 13.3 Concentration and Reaction Rates

40. The reaction of NO2 with CO to give CO2 and NO can proceed through different mechanisms. What first step would be consistent with the following rate law?

Rate = k[NO2][CO]

Difficulty: Easy

Learning Objective: Determine the rate law, given the mechanism and knowledge of the relative rates of steps of a reaction.

Section Reference: 13.3 Concentration and Reaction Rates

41. What are the units of a rate constant for a reaction that has an overall order of 3?

Difficulty: Easy

Learning Objective: Determine the rate law, given the mechanism and knowledge of the relative rates of steps of a reaction.

Section Reference: 13.3 Concentration and Reaction Rates

42. The reaction of NO2 with CO to give CO2 and NO can proceed through different mechanisms. What rate law would be consistent for the following first step?

2 NO2 🡪 NO + NO3

Difficulty: Easy

Learning Objective: Determine the rate law, given the mechanism and knowledge of the relative rates of steps of a reaction.

Section Reference: 13.3 Concentration and Reaction Rates

43. The rate law for the reaction of NO with O2 to give NO2 is shown below:

rate = k [NO]2[O2]

a) If all other conditions are kept constant, what will be the effect on the rate if the concentration of NO is doubled?

b) If all other conditions are kept constant, what will be the effect on the rate if the concentration of O2 is doubled?

Difficulty: Easy

Learning Objective: Determine the rate law, given the mechanism and knowledge of the relative rates of steps of a reaction.

Section Reference: 13.3 Concentration and Reaction Rates

44. At moderate temperatures, the rate law for the reaction of NO2 and CO to give CO2 and NO follows the rate law shown below:

rate = k [NO2]2

Flask a

Flask b

In which flask will the reaction be faster and how much faster?

Difficulty: Easy

Learning Objective: Determine the rate law, given the mechanism and knowledge of the relative rates of steps of a reaction.

Section Reference: 13.3 Concentration and Reaction Rates

45. Radioactive decay follows first-order kinetics. Some smoke detectors use the isotope 241Am that has a half-life of 432.2 years. In how many years will 95% of the 241Am have decayed?

Difficulty: Medium

Learning Objective: Determine rate laws from concentration versus time data.

Section Reference: 13.4 Experimental Kinetics

46. Trioxane undergoes decomposition to formaldehyde at elevated temperatures.

C3H6O3 (g) 🡪 3 CH2O (g)

The following data was collected for the gas phase reaction at 519ºK:

t(s)

[C3H6O3] (M)

0

1.50

1200

1.04

2400

0.72

3600

0.50

4800

0.35

6000

0.24

7200

0.17

Determine the order of the decomposition in trioxane and the rate constant at 519ºK.

Difficulty: Hard

Learning Objective: Determine rate laws from concentration versus time data.

Section Reference: 13.4 Experimental Kinetics

47. Ammonium cyanate undergoes rearrangement to form urea in aqueous solution.

NH4NCO(aq) 🡪 CO(NH2)2 (aq)

The following data was collected:

T (min)

[NH4NCO]

0

0.46

44

0.38

110

0.289

232

0.21

597

0.117

Determine the order of the reaction and the rate constant.

Difficulty: Hard

Learning Objective: Determine rate laws from concentration versus time data.

Section Reference: 13.4 Experimental Kinetics

48. Sucrose, cane sugar, reacts with water in acid solution to give glucose and fructose, which have the same chemical formula.

C12H22O11 (aq) + H2O (l) 🡪2 C6H12O6 (aq)

The following data were obtained at room temperature for sucrose:

t (min)

(M)

0

0.316

-1.152

3.16

39

0.274

-1.293

3.65

80

0.238

-1.435

4.20

140

0.19

-1.661

5.26

210

0.146

-1.924

6.85

Use graphical means to determine the order of the reaction and write the rate law with the numerical value of the rate constant with time units of seconds.

Difficulty: Hard

Learning Objective: Determine rate laws from concentration versus time data.

Section Reference: 13.4 Experimental Kinetics

49. Rate data were collected for the following reaction at a constant temperature.

2ClO2(aq) + 2 OH-1(aq) 🡪 ClO3-1(aq) + ClO2-1(aq) + H2O(l)

Experiment

[ClO2] mol/L

[OH-1]mol/L

Initial Rate of rxn

1

0.012

0.012

2.07 x10-4 M/s

2

0.024

0.012

8.28 x10-4 M/s

3

0.012

0.024

4.14 x10-4 M/s

4

0.024

0.024

16.6 x10-4 M/s

a) Determine the rate law for this reaction.

b) Determine the rate constant with appropriate units.

Difficulty: Medium

Learning Objective: Determine rate laws from concentration versus time data.

Section Reference: 13.4 Experimental Kinetics

50. Nitrous oxide, N2O, decomposes on metal surfaces readily at high temperatures following first-order kinetics for the equation:

2 N2O (g) 🡪 2 N2 (g) + O2 (g)

The following data are obtained for a reaction at 850°C:

t (min)

[N2O]

0

0.200

15

0.163

30

0.1326

80

0.0668

120

0.0386

Determine the rate constant and half-life for the reaction.

Difficulty: Hard

Learning Objective: Determine rate laws from concentration versus time data.

Section Reference: 13.4 Experimental Kinetics

51. The following are initial rate data for 2 NO + 2 H2 🡪 N2 + 2 H2O

Experiment

Initial [NO]

Initial [H2]

Initial Rate

1

0.20

0.12

0.066 M/s

2

0.20

0.24

0.13

3

0.20

0.36

0.20

4

0.40

0.12

0.26

5

0.60

0.12

0.59

The rate law is determined to be: rate = k[NO]2[H­2]. With this information determine k using the data from experiment 2.

Difficulty: Easy

Learning Objective: Determine rate laws from concentration versus time data.

Section Reference: 13.4 Experimental Kinetics

52. Assume that the following first-order reaction has a rate constant k = 0.0137/min:

SO2Cl2 🡪 SO2 + Cl2

Given the initial [SO2Cl2] = 0.42 M, how many minutes will it take for [SO2Cl2] = 0.19 M?

Difficulty: Medium

Learning Objective: Determine rate laws from concentration versus time data.

Section Reference: 13.4 Experimental Kinetics

53. The three reactions below, with identical reaction stoichiometry, must all share the same third order rate law found for the reaction of NO and O2. True or False, and why?

2 NO(g) + O2(g) 🡪 2 NO2(g)

2 NO(g) + Cl2(g) 🡪 2 NOCl(g)

2 NO(g) + F2(g) 🡪 2 NOF(g)

Difficulty: Medium

Learning Objective: Show that the mechanism and rate law are closely related.

Section Reference: 13.5 Linking Mechanisms and Rate Laws

54. Nitrogen dioxide, NO2 will react with carbon monoxide, CO, to form nitric oxide, NO, and carbon dioxide, CO2. A proposed mechanism is:

2NO2 🡪 NO3 + NO

NO3 + CO 🡪 NO2 + CO2

Experiments indicate that the rate of the reaction is independent of the CO concentration. Identify the rate determining step and derive the rate law consistent with the mechanism and experimental observation.

Difficulty: Medium

Learning Objective: Show that the mechanism and rate law are closely related.

Section Reference: 13.5 Linking Mechanisms and Rate Laws

Feedback: Since rate is independent of CO concentration, the second step must be fast and the first slow; rate law is determined from the first step.

55. A proposed mechanism for the following reaction, A2 + B2 🡪 2AB, is

A2 2A

A + B2 🡪 AB + B slow

B +A2 🡪 AB + A

Determine the rate law.

Difficulty: Medium

Learning Objective: Show that the mechanism and rate law are closely related.

Section Reference: 13.5 Linking Mechanisms and Rate Laws

56. The reaction of nitrogen dioxide and fluorine is:

2 NO2 + F2 🡪 2 NO2F

One proposed mechanism has two steps; the first step is rate determining:

Step

Elementary Reaction

Relative Rate

1

NO2 + F2 🡪 NO2F + F •

slow

2

F• + NO2 🡪 NO2F

fast (very reactive fluorine atom)

What is the experimentally determined rate law?

Difficulty: Medium

Learning Objective: Show that the mechanism and rate law are closely related.

Section Reference: 13.5 Linking Mechanisms and Rate Laws

57. The rate law for the reaction

2 H2 (g) + 2 NO (g) 🡪 N2 (g) + 2 H2O (g)

is rate = k[H2 ][NO]2. Which of the following mechanisms can be ruled out because the derived rate law is NOT consistent with the observed rate law?

Mechanism 1

H2 + NO 🡪 N + H2O (slow)

N + NO 🡪 N2 + O (fast)

O + H2 🡪 H2O (fast)

Mechanism 2

H2 + 2 NO 🡪 N2O + H2O (slow)

N2O + H2 🡪 N2 + H2O (fast)

Mechanism 3

2 NO N2O2 (fast equilibrium)

N2O2 + H2 🡪 N2O + H2O (slow)

N2O + H2 🡪 N2 + H2O (fast)

Difficulty: Hard

Learning Objective: Show that the mechanism and rate law are closely related.

Section Reference: 13.5 Linking Mechanisms and Rate Laws

58. For the following reaction A + B 🡪 C + D, the rate law is determined to be Rate = k[A]2

a) Of the five proposed mechanisms shown below, which is consistent with the experimentally determined rate law?

1. 2 A 🡪 Z (slow)

2 B + Z 🡪 2 C + 2 D (fast)

2. A + B 🡪 C + D (slow)

3. 2 B 🡪 N (slow)

2 A + N 🡪 2 C + 2 D (fast)

4. A 🡪 X (slow)

B + X 🡪 C + D (fast)

5. B 🡪 M (slow)

A + M 🡪 C + D (fast)

b) Are there any intermediates in the mechanism you chose and if so what?

Difficulty: Medium

Learning Objective: Show that the mechanism and rate law are closely related.

Section Reference: 13.5 Linking Mechanisms and Rate Laws

59. In the formation of dinitrogentetroxide, two NO2 molecules react to make an N-N bond.

2 NO2 🡪 2 N2O4

Draw molecular pictures superimposed on a diagram of energy vs. reaction coordinate that illustrates this process.

Difficulty: Easy

Learning Objective: Explain and quantify the effects of temperature on a reaction rate.

Section Reference: 13.6 Reaction Rates and Temperature

60. The following rate constants were obtained at the stated temperatures for the first-order reaction:

A🡪 B

T(K)

300

310

320

330

340

k (1/s)

8.93 x 10-8

1.94x 10-7

4.01 x 10-7

7.95 x 10-7

1.51 x 10-6

Find the activation energy (in kJ/mole) for this reaction.

Difficulty: Medium

Learning Objective: Explain and quantify the effects of temperature on a reaction rate.

Section Reference: 13.6 Reaction Rates and Temperature

61. Nitrogen dioxide molecules undergo oxygen exchange with an activation energy of 100 kJ/mole. By how much will the reaction rate constant increase if temperature is increased from 25oC to 75oC?

Difficulty: Medium

Learning Objective: Explain and quantify the effects of temperature on a reaction rate.

Section Reference: 13.6 Reaction Rates and Temperature

62. A particular first-order reaction is characterized by activation energy of 50 kJ/mole. At what temperature would the rate of the reaction be 10 times that at 298oK?

Difficulty: Hard

Learning Objective: Explain and quantify the effects of temperature on a reaction rate.

Section Reference: 13.6 Reaction Rates and Temperature

Feedback: Need to recognize that for first-order reaction 10 fold increase in rate results from a 10 fold increase in rate constant.

63. The reaction of ozone with oxygen atoms to give oxygen has an activation energy of 17.1 kJ/mole with a rate constant at 298oK, k = 4.8 x 106 1/M•s. Calculate the rate constant for this reaction at 315oK.

Difficulty: Medium

Learning Objective: Explain and quantify the effects of temperature on a reaction rate.

Section Reference: 13.6 Reaction Rates and Temperature

64. The reaction of ozone with oxygen atoms to produce molecular oxygen has a rate constant of 4.8x106 1/M s at 25oC. A 20 degree increase in temperature results in a rate constant of 7.4x106 1/M s. What is the rate constant at 100oC?

Difficulty: Medium

Learning Objective: Explain and quantify the effects of temperature on a reaction rate.

Section Reference: 13.6 Reaction Rates and Temperature

Feedback: Two step problem: student must first determine the activation energy, then the rate constant at the new temperature.

65. The activation energy for the high temperature conversion cyclopropane to propene is 270 kJ mol-1. At what temperature would the rate constant for this reaction be ten times that of 500oC?

Difficulty: Medium

Learning Objective: Explain and quantify the effects of temperature on a reaction rate.

Section Reference: 13.6 Reaction Rates and Temperature

66. The rate constant of the reaction, O (g) + N2 (g) 🡪NO (g) + N (g), is 9.7 x 10101/M•s at 800oK and has an activation energy of 315 kJ/mole. What is the value of the rate constant at 700oK?

Difficulty: Medium

Learning Objective: Explain and quantify the effects of temperature on a reaction rate.

Section Reference: 13.6 Reaction Rates and Temperature

67. For a large number of reactions in organic chemistry, an increase in temperature 10°C over room temperature will double the rate. What activation energy does this correspond to?

Difficulty: Medium

Learning Objective: Explain and quantify the effects of temperature on a reaction rate.

Section Reference: 13.6 Reaction Rates and Temperature

68. For a hypothetical reaction, the activation energy is E­act = 50.2 kJ/mol and it has an Arrhenius constant of 22.3 M-1s-1. Determine what the rate constant would be if the temperature was 400°C.

Difficulty: Medium

Learning Objective: Explain and quantify the effects of temperature on a reaction rate.

Section Reference: 13.6 Reaction Rates and Temperature

69. Consider the following energy-reaction coordinate diagram.

Give the names for the quantities indicated by A, B and C.

Difficulty: Easy

Learning Objective: Explain the mechanisms by which catalysts function.

Section Reference: 13.7 Catalysis

70. Write the overall equation of reaction for the following mechanism and identify any reaction intermediates and any catalysts.

H2O2 + I-1 🡪 H2O + OI-1

2O2 + OI-1 🡪 H2O + O2 + I-1

Difficulty: Medium

Learning Objective: Explain the mechanisms by which catalysts function.

Section Reference: 13.7 Catalysis

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Document Information

Document Type:
DOCX
Chapter Number:
13
Created Date:
Aug 21, 2025
Chapter Name:
Chapter 13 Kinetics: Mechanisms And Rates Of Reactions 608
Author:
John A. Olmsted

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