Probability And The Normal Curve Ch.4 Exam Questions - Statistics for Criminology 1e | Test Bank Cooper by Jonathon A. Cooper. DOCX document preview.

Probability And The Normal Curve Ch.4 Exam Questions

Chapter 4: Probability and the Normal Curve

  1. The city of Portland is interested to find what impact different levels of treatment (intensive treatment, conventional treatment, or no treatment) during jail time have on low-level drug offenders. The jail administration received 300 sealed and mixed-up envelopes containing one of the three treatment options. During each offender’s intake, a corrections officer opens one envelope to reveal the treatment level that offender will receive, as indicated on the card, and then the card is taken out of the selection pool.

Indicate whether the case allows for classical probability or empirical probability. Calculate the probabilities of the following (A, extensive treatment; B, conventional treatment; C, no treatment) at the beginning of the study.

      1. What is the chance that an individual inmate will receive intensive treatment?
      2. What is the chance of an individual inmate to receive some form of treatment (intensive treatment or conventional treatment)?
      3. What is the chance that the first five inmates receive no treatment?
      4. What will happen to your initial figures once selection has begun?
  1. Over the following three months, 300 convicted low-level drug offenders were assigned to different levels of treatment utilizing the methodology described above.

Extensive treatment

Conventional treatment

No treatment

Total

Female

41

33

51

125

Male

59

67

49

175

Total

100

100

100

300

As the table indicates, we have a total of 300 inmates who were assigned to extensive treatment, conventional treatment, or no treatment according to the methodology presented in question 1. Of the 125 females, 51 have been assigned to no treatment, 33 to conventional treatment, and 41 to extensive treatment. The remaining 175 offenders were male, 49 who were assigned to no treatment, 67 to conventional treatment, and 59 to extensive treatment.

  1. If we selected one individual at random from the sample, what is the probability that a person is a female assigned to extensive treatment?
  2. What is the probability of being male or being assigned to no treatment?
  3. What is the probability of being assigned to conventional treatment?
  4. You gather a random sample of six inmates who are eligible for a parole hearing. The parole hearing has two possible outcomes (i.e., released on parole and not released on parole). You want to construct a binomial probability distribution to be able to later on (after you learn how many of the six inmates were actually released on parole) find whether the actual outcome could have been expected.
  5. Create a binomial probability distribution.
  6. What is the (theoretical) probability that four of six inmates get released on parole?
  7. The normal curve is a probability distribution for ____________ random variables. Two parameters are essential for its specification, that is, ____________ and ___________. The normal curve is purely hypothetical and has the following characteristics:
    1. ______________________
    2. ______________________
  8. ______________________
  9. Under the normal curve, about what is the probability that a random case will fall within 1 standard deviation from the mean (±)?
    1. 0.34.
    2. 0.50.
    3. 0.68.
    4. 0.135.
  10. Under the normal curve, how many cases, of a sample of 500, would we expect to find
  11. Within 2 standard deviations from the mean (±)? 
  12. More than 3 standard deviations away from the mean (±)?
  13. To address the concern regarding use of force by police officers, the local police department decided to offer (mandatory) “use of force training” to officers who fall into the upper 30% of the frequency of overall force used by individual officers (in 2015).
  14. Compute the mean.
  15. Compute the standard deviation.
  16. Compute the z score.
  17. Indicate the area under the normal curve (AUC) listed in the z-score table.
  18. Indicate the percent ranking for each police officer.
  19. List the officer IDs of the individuals who will be required to attend the “use of force training.”

Officer ID

No. of incidences/use of force/2015

5556

26

5557

36

5558

15

5559

58

5560

12

5561

29

5562

17

5562

41

5562

9

5563

47

5564

12

5565

25

5566

51

5567

43

5568

22

  1. The same police department decided to reward officers for low rates of citizen complaints. Officers falling in the lower 20% (for the year 2015) will receive two additional paid days off for the year 2016.
  2. Compute the mean.
  3. Compute the standard deviation.
  4. Compute the z scores for every individual officer.
  5. Indicate the area under the normal curve (AUC) listed in the z-score table.
  6. Indicate the percent ranking for each police officer.
  7. List the officer IDs of the individuals who will receive two additional paid days for the year 2016.

Officer ID

No. of citizen complaints/2015

5556

1

5557

9

5558

3

5559

20

5560

14

5561

8

5562

5

5562

21

5562

0

5563

11

5564

0

5565

6

5566

15

5567

9

5568

4

r

nCr

(pr)(qn – r)

p

0 parole

1

(1/2)0(1/2)6 = 1/64

1/64 = 0.015625

1

6

(1/2)1(1/2)5 = 1/64

6/64 = 0.9375

2

15

(1/2)2(1/2)4 = 1/64

15/64 = 0.234375

3

20

(1/2)3(1/2)3 = 1/64

20/64 = 0.3125

4

15

(1/2)4(1/2)2 = 1/64

15/64 = 0.234375

5

6

(1/2)5(1/2)1 = 1/64

6/64 = 0.9375

6

1

(1/2)6(1/2)0 = 1/64

1/64 = 0.015625

Officer ID

No. of incidences/use of force/2013

x – mean

z score

AUC

(area under the curve)

% Ranking

5556

26

–3.53

–0.23

0.0910

40.9

5557

36

6.47

0.41

0.1591

79.55

5558

15

–14.53

–0.93

0.3238

17.62

5559

58

28.47

1.82

0.4656

96.56

5560

12

–17.53

–1.12

0.3686

13.14

5561

29

–0.53

–0.03

0.0120

48.8

5562

17

–12.53

–0.80

0.2881

21.19

5562

41

11.47

0.73

0.2673

76.73

5562

9

–20.53

–1.31

0.4049

9.51

5563

47

17.47

1.12

0.3686

86.86

5564

12

–17.53

–1.12

0.3686

13.14

5565

25

–4.53

–0.29

0.1141

38.59

5566

51

21.47

1.37

0.4147

91.47

5567

43

13.47

0.86

0.3051

80.51

5568

22

–7.53

–0.48

0.1844

31.56

Officer ID

No. of citizen complaints/2013

xX

z score

AUC

% Ranking

5556

1

–7.4

–1.10

0.3643

13.57

5557

9

0.6

0.09

0.0359

53.59

5558

3

–5.4

–0.80

0.2881

21.19

5559

20

11.6

1.72

0.4564

95.64

5560

14

5.6

0.83

0.2967

20.33

5561

8

–0.4

–0.06

0.0239

47.61

5562

5

–3.4

–0.50

0.1915

30.85

5562

21

12.6

1.87

0.4693

96.93

5562

0

–8.4

–1.24

0.3925

10.75

5563

11

2.6

0.39

0.1517

65.17

5564

0

–8.4

–1.24

0.3925

10.75

5565

6

–2.4

–0.36

0.1406

35.94

5566

15

6.6

0.98

0.3106

81.06

5567

9

0.6

0.09

0.0359

53.59

5568

4

–4.4

–0.65

0.2422

25.78

Document Information

Document Type:
DOCX
Chapter Number:
4
Created Date:
Aug 21, 2025
Chapter Name:
Chapter 4 Probability And The Normal Curve
Author:
Jonathon A. Cooper

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