Chi-Square Tests Chapter 11 Test Bank Docx

Introductory Statistics, 10e (Mann)

Chapter 11 Chi-Square Tests

11.1 The Chi-Square Distribution

1) The parameter(s) of the chi-square distribution is/are:

A) the sample size

B) degrees of freedom

C) n and x

D) n, x, and p

Diff: 1

LO: 11.1.0 Demonstrate an understanding of the chi-square distribution.

Section: 11.1 The Chi-Square Distribution

Question Title: Chapter 11, Testbank Question 001

2) For a chi-square distribution curve with 3 or more degrees of freedom, the peak occurs at the point:

A) x = 10

B) x = degrees of freedom minus 1

C) x = degrees of freedom minus 2

D) n - x

Diff: 1

LO: 11.1.0 Demonstrate an understanding of the chi-square distribution.

Section: 11.1 The Chi-Square Distribution

Question Title: Chapter 11, Testbank Question 002

3) A chi-square distribution assumes:

A) negative values only

B) positive values only

C) nonnegative values only

D) all values

Diff: 1

LO: 11.1.0 Demonstrate an understanding of the chi-square distribution.

Section: 11.1 The Chi-Square Distribution

Question Title: Chapter 11, Testbank Question 003

4) For small degrees of freedom, the chi-square distribution is:

A) symmetric

B) skewed to the right

C) skewed to the left

D) rectangular

Diff: 1

LO: 11.1.0 Demonstrate an understanding of the chi-square distribution.

Section: 11.1 The Chi-Square Distribution

Question Title: Chapter 11, Testbank Question 004

5) For very large degrees of freedom, the chi-square distribution becomes:

A) symmetric

B) skewed to the right

C) skewed to the left

D) rectangular

Diff: 1

LO: 11.1.0 Demonstrate an understanding of the chi-square distribution.

Section: 11.1 The Chi-Square Distribution

Question Title: Chapter 11, Testbank Question 005

6) What is the chi-square value for 14 degrees of freedom and a .05 area in the right tail?

A) 21.604

B) 26.119

C) 23.685

D) 29.141

Diff: 1

LO: 11.1.0 Demonstrate an understanding of the chi-square distribution.

Section: 11.1 The Chi-Square Distribution

Question Title: Chapter 11, Testbank Question 006

7) What is the chi-square value for 9 degrees of freedom and a .01 area in the left tail?

A) 21.666

B) -21.666

C) 2.088

D) -2.088

Diff: 1

LO: 11.1.0 Demonstrate an understanding of the chi-square distribution.

Section: 11.1 The Chi-Square Distribution

Question Title: Chapter 11, Testbank Question 007

8) What is the chi-square value for 19 degrees of freedom and a 0.025 area in the right tail?

A) 30.144

B) 32.852

C) 8.907

D) 10.117

Diff: 1

LO: 11.1.0 Demonstrate an understanding of the chi-square distribution.

Section: 11.1 The Chi-Square Distribution

Question Title: Chapter 11, Testbank Question 008

9) What is the chi-square value for 12 degrees of freedom and a 0.10 area in the left tail?

A) 6.304

B) -6.304

C) 18.549

D) -18.549

Diff: 1

LO: 11.1.0 Demonstrate an understanding of the chi-square distribution.

Section: 11.1 The Chi-Square Distribution

Question Title: Chapter 11, Testbank Question 009

10) Using the table for the chi-square distributions, find the lower 10% point when d.f. = 4.

Diff: 1

LO: 11.1.0 Demonstrate an understanding of the chi-square distribution.

Section: 11.1 The Chi-Square Distribution

Question Title: Chapter 11, Testbank Question 010

11) Find the probability of > 35.72 when d.f. = 17.

Diff: 1

LO: 11.1.0 Demonstrate an understanding of the chi-square distribution.

Section: 11.1 The Chi-Square Distribution

Question Title: Chapter 11, Testbank Question 011

12) Find the probability of < 6.26 when d.f. = 15.

A) 0.025

B) 0.05

C) 0.1

D) 0.005

Diff: 1

LO: 11.1.0 Demonstrate an understanding of the chi-square distribution.

Section: 11.1 The Chi-Square Distribution

Question Title: Chapter 11, Testbank Question 012

13) Find the probability of 9.89 < < 33.2 when d.f. = 24.

Diff: 3

LO: 11.1.0 Demonstrate an understanding of the chi-square distribution.

Section: 11.1 The Chi-Square Distribution

Question Title: Chapter 11, Testbank Question 013

14) If a test of hypothesis involves a multinomial experiment, which test is used?

A) Test of hypothesis about the variance

B) Goodness-of-fit test

C) χ2 distribution test

D) Independence test or homogeneity test

Diff: 1

LO: 11.1.0 Demonstrate an understanding of the chi-square distribution.

Section: 11.1 The Chi-Square Distribution

Question Title: Chapter 11, Testbank Question 014

11.2 A Goodness-of-Fit Test

1) Which of the following is not a characteristic of a multinomial experiment?

A) It consists of two identical trials.

B) Each trial results in one of k possible outcomes, where k is a number greater than 2.

C) The trials are independent.

D) The probabilities of various outcomes remain constant for each trial.

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 015

2) Which of the following is not a characteristic of a multinomial experiment?

A) It consists of n identical trials.

B) Each trial results in one of two possible outcomes.

C) The trials are independent.

D) The probabilities of various outcomes remain constant for each trial.

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 016

3) Which of the following is not a characteristic of a multinomial experiment?

A) It consists of n identical trials.

B) Each trial results in one of k possible outcomes, where k is a number greater than 2.

C) The trials are dependent.

D) The probabilities of various outcomes remain constant for each trial.

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 017

4) Which of the following is not a characteristic of a multinomial experiment?

A) It consists of n identical trials.

B) Each trial results in one of k possible outcomes, where k is a number greater than 2.

C) The trials are independent.

D) The probabilities of various outcomes are different for each trial.

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 018

5) For a goodness-of-fit test, the frequencies obtained from the performance of an experiment are the:

A) expected frequencies

B) subjective frequencies

C) objective frequencies

D) observed frequencies

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 019

6) For a goodness-of-fit test, the frequencies that we would obtain if the null hypothesis is true are the:

A) expected frequencies

B) subjective frequencies

C) objective frequencies

D) observed frequencies

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 020

7) For a goodness-of-fit test with the number of categories equal to k and sample size equal to n, the degrees of freedom are:

A) k - 2

B) n - k

C) k - n

D) k - 1

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 021

8) For a goodness-of-fit test, when n is the sample size and p is the probability of a category occurring, we calculate the expected frequency for a category by:

A) E = np

B) E = xp

C) E = nx

D) E = nkp

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 022

9) For a goodness-of-fit test, the sample size should be large enough so that the:

A) observed frequency for each category is at least 10

B) expected frequency for each category is at least 10

C) observed frequency for each category is at least 5

D) expected frequency for each category is at least 5

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 023

10) A goodness-of-fit test:

A) is always a right-tailed test

B) is always a left-tailed test

C) is always a two-tailed test

D) can be a right-tailed, left-tailed, or a two-tailed test

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 024

11) The table below lists the observed frequencies for all four categories for an experiment.

The null hypothesis for the goodness-of-fit test is that the proportion of all elements of the population that belong to each of the four categories is the same. What is the expected frequency for the second category?

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 025

12) The null hypothesis for the goodness-of-fit test is that the proportion of all elements of the population that belong to each of the four categories is the same. The expected frequencies for the four categories are:

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 026

13) The table below lists the observed frequencies for all four categories for an experiment.

The null hypothesis for the goodness-of-fit test is that the proportion of all elements of the population that belong to each of the four categories is the same. What are the degrees of freedom for this test?

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 027

14) The table below lists the observed frequencies for all four categories for an experiment.

The null hypothesis for the goodness-of-fit test is that the proportion of all elements of the population that belong to each of the four categories is the same. The significance level is 1%. What is the critical value of chi-square?

A) 13.277

B) 11.345

C) 12.838

D) 14.860

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 028

15) The table below lists the observed frequencies for all four categories for an experiment.

The null hypothesis for the goodness-of-fit test is that the proportion of all elements of the population that belong to each of the four categories is the same. What is the value of the test statistic, rounded to three decimal places?

Diff: 2

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 029

16) The table below lists the observed frequencies for all four categories for an experiment.

The null hypothesis for the goodness-of-fit test is that the proportion of all elements of the population that belong to each of the four categories is the same. Do you reject or fail to reject the null hypothesis at the 1% significance level? (State your answer as "reject" or "fail to reject", but don't include the quotation marks.)

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 030

17) The table below lists the observed frequencies for all four categories for an experiment.

The null hypothesis for the goodness-of-fit test is that 40% of all elements of the population belong to the first category, 30% belong to the second category, 20% belong to the third category, and 10% belong to the fourth category. What is the expected frequency for the fourth category?

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 031

18) The null hypothesis for the goodness-of-fit test is that 40% of all elements of the population belong to the first category, 30% belong to the second category, 20% belong to the third category, and 10% belong to the fourth category. The expected frequencies for the four categories are:

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 032

19) The table below lists the observed frequencies for all four categories for an experiment.

The null hypothesis for the goodness-of-fit test is that 40% of all elements of the population belong to the first category, 30% belong to the second category, 20% belong to the third category, and 10% belong to the fourth category. What are the degrees of freedom for this test?

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 033

20) The table below lists the observed frequencies for all four categories for an experiment.

The null hypothesis for the goodness-of-fit test is that 40% of all elements of the population belong to the first category, 30% belong to the second category, 20% belong to the third category, and 10% belong to the fourth category. The significance level is 10%. What is the critical value of chi-square?

A) 9.488

B) 7.815

C) 7.779

D) 6.251

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 034

21) The table below lists the observed frequencies for all four categories for an experiment.

The null hypothesis for the goodness-of-fit test is that the proportion of all elements of the population that belong to each of the four categories is equal. What is the value of the test statistic, rounded to three decimal places?

Diff: 2

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 035

22) The table below lists the observed frequencies for all four categories for an experiment.

The null hypothesis for the goodness-of-fit test is that 40% of all elements of the population belong to the first category, 30% belong to the second category, 20% belong to the third category, and 10% belong to the fourth category. Do you reject or fail to reject the null hypothesis at the 10% significance level? (State your answer as "reject" or "fail to reject", but don't include the quotation marks.)

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 036

23) The table below lists the observed frequencies for all four categories for an experiment.

The null hypothesis for the goodness-of-fit test is that the proportion of all elements of the population that belong to each of the five categories is the same. What is the expected frequency for the fourth category?

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 037

24) The null hypothesis for the goodness-of-fit test is that the proportion of all elements of the population that belong to each of the five categories is the same. The expected frequencies for the five categories are:

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 038

25) The table below lists the observed frequencies for all four categories for an experiment.

The null hypothesis for the goodness-of-fit test is that the proportion of all elements of the population that belong to each of the five categories is the same. What are the degrees of freedom for this test?

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 039

26) The table below lists the observed frequencies for all four categories for an experiment.

The null hypothesis for the goodness-of-fit test is that the proportion of all elements of the population that belong to each of the five categories is the same. The significance level is 5%. What is the critical value of chi-square?

A) 11.070

B) 12.833

C) 11.143

D) 9.488

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 040

27) The table below lists the observed frequencies for all four categories for an experiment.

The null hypothesis for the goodness-of-fit test is that the proportion of all elements of the population that belong to each of the five categories is the same. What is the value of the test statistic, rounded to three decimal places?

Diff: 2

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 041

28) The table below lists the observed frequencies for all four categories for an experiment.

The null hypothesis for the goodness-of-fit test is that the proportion of all elements of the population that belong to each of the five categories is the same. Do you reject or fail to reject the null hypothesis at the 5% significance level? (State your answer as "reject" or "fail to reject", but don't include the quotation marks.)

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 042

29) You ask 100 persons what color of car they like the most. The table below lists the observed frequencies for such a survey.

The null hypothesis for the goodness-of-fit test is that 10% of all persons like black cars, 25% like blue cars, 20% like red cars, 10% like white cars, and 35% like other colors. What is the expected frequency for red cars?

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 043

30) The null hypothesis for the goodness-of-fit test is that 10% of all persons like black cars, 25% like blue cars, 20% like red cars, 10% like white cars, and 35% like other colors. The expected frequencies for the various colors are:

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 044

31) You ask 100 persons what color of car they like the most. The table below lists the observed frequencies for such a survey.

The null hypothesis for the goodness-of-fit test is that 10% of all persons like black cars, 25% like blue cars, 20% like red cars, 10% like white cars, and 35% like other colors. What are the degrees of freedom for this test?

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 045

32) You ask 100 persons what color of car they like the most. The table below lists the observed frequencies for such a survey.

The null hypothesis for the goodness-of-fit test is that 10% of all persons like black cars, 25% like blue cars, 20% like red cars, 10% like white cars, and 35% like other colors. The significance level is 2.5%. What is the critical value of chi-square?

A) 9.488

B) 11.143

C) 12.833

D) 11.070

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 046

33) You ask 100 persons what color of car they like the most. The table below lists the observed frequencies for such a survey.

The null hypothesis for the goodness-of-fit test is that 10% of all persons like black cars, 25% like blue cars, 20% like red cars, 10% like white cars, and 35% like other colors. What is the value of the test statistic, rounded to three decimal places?

Diff: 2

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 047

34) You ask 100 persons what color of car they like the most. The table below lists the observed frequencies for such a survey.

The null hypothesis for the goodness-of-fit test is that 10% of all persons like black cars, 25% like blue cars, 20% like red cars, 10% like white cars, and 35% like other colors. Do you reject or fail to reject the null hypothesis at the 2.5% significance level? (State your answer as "reject" or "fail to reject", but don't include the quotation marks.)

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 048

35) The table below lists the number of crimes reported at a police station on each day of the week for the past three months.

The null hypothesis for the goodness-of-fit test is that the number of crimes reported at this police station is the same for each day of the week. What is the expected number of crimes reported on a Thursday?

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 049

36) The null hypothesis for the goodness-of-fit test is that the number of crimes reported at this police station is the same for each day of the week. The expected frequencies for each of the seven days are:

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 050

37) The table below lists the number of crimes reported at a police station on each day of the week for the past three months.

The null hypothesis for the goodness-of-fit test is that the number of crimes reported at this police station is the same for each day of the week. What are the degrees of freedom for this test?

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 051

38) The table below lists the number of crimes reported at a police station on each day of the week for the past three months.

The null hypothesis for the goodness-of-fit test is that the number of crimes reported at this police station is the same for each day of the week. The significance level is 10%. What is the critical value of chi-square?

A) 12.017

B) 14.067

C) 10.645

D) 12.592

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 052

39) The table below lists the number of crimes reported at a police station on each day of the week for the past three months.

The null hypothesis for the goodness-of-fit test is that the number of crimes reported at this police station is the same for each day of the week. What is the value of the test statistic?

Diff: 2

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 053

40) The table below lists the number of crimes reported at a police station on each day of the week for the past three months.

The null hypothesis for the goodness-of-fit test is that the number of crimes reported at this police station is the same for each day of the week. Do you reject or fail to reject the null hypothesis at the 10% significance level? (State your answer as "reject" or "fail to reject", but don't include the quotation marks.)

Diff: 1

LO: 11.2.0 Demonstrate an understanding of how to perform a goodness-of-fit test using the chi-square distribution.

Section: 11.2 A Goodness-of-Fit Test

Question Title: Chapter 11, Testbank Question 054

11.3 A Test of Independence or Homogeneity

1) If a test of hypothesis involves a contingency table, which test is used?

A) Test of hypothesis about the variance

B) Goodness-of-fit test

C) χ2 distribution test

D) Independence test or homogeneity test

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 055

2) For a chi-square test of independence, what are the degrees of freedom?

A) n - 1

B) n - 2

C) (R-1)(C-1) where R is the number of rows and C is the number of columns in the contingency table

D) (n-1)(k-1) where n is the sample size and k is the number of categories

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 056

3) For a chi-square test of homogeneity, what are the degrees of freedom?

A) sample size minus one

B) sample size minus two

C) (R-1)(C-1) where R is the number of rows and C is the number of columns in the contingency table

D) (n-1)(k-1) where n is the sample size and k is the number of categories

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 057

4) A chi-square test of independence:

A) is always a right-tailed test

B) is always a left-tailed test

C) is always a two-tailed test

D) can be a right-tailed, a left-tailed, or a two-tailed test

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 058

5) A chi-square test of homogeneity:

A) is always a right-tailed test

B) is always a left-tailed test

C) is always a two-tailed test

D) can be a right-tailed, a left-tailed, or a two-tailed test

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 059

6) A chi-square test of independence is about the independence of:

A) two means

B) two proportions

C) two characteristics presented in a contingency table

D) means of several populations

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 060

7) A chi-square test of homogeneity is about:

A) testing the null hypothesis that two samples are homogeneous

B) testing the null hypothesis that two proportions are homogeneous

C) the independence of two characteristics presented in a contingency table

D) testing the null hypothesis that the proportions of elements with certain characteristics in two or more different populations are the same

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 061

8) For a chi-square test of independence, a contingency table with 3 rows and 6 columns has how many degrees of freedom?

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 062

9) For a chi-square test of independence, a contingency table with 6 rows and 12 columns has how many degrees of freedom?

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 063

10) For a chi-square test of homogeneity, a contingency table with 5 rows and 7 columns has how many degrees of freedom?

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 064

11) For a chi-square test of homogeneity, a contingency table with 4 rows and 9 columns has how many degrees of freedom?

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 065

12) You observe 100 randomly selected college students to find out whether they arrive on time or late for their classes. The table below gives a two-way classification for these students.

For a chi-square test of independence for this contingency table, what is the number of degrees of freedom?

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 066

13) You observe 100 randomly selected college students to find out whether they arrive on time or late for their classes. The table below gives a two-way classification for these students.

For a chi-square test of independence for this contingency table, what are the observed frequencies for the first row?

A) 33 and 7

B) 50 and 10

C) 33 and 50

D) 7 and 10

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 067

14) You observe 100 randomly selected college students to find out whether they arrive on time or late for their classes. The table below gives a two-way classification for these students.

For a chi-square test of independence for this contingency table, what are the expected frequencies for the first row, rounded to two decimal places?

A) 34.40 and 8.60

B) 35.78 and 8.26

C) 37.50 and 7.83

D) 31.99 and 9.20

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 068

15) You observe 100 randomly selected college students to find out whether they arrive on time or late for their classes. The table below gives a two-way classification for these students.

For a chi-square test of independence for this contingency table, what are the observed frequencies for the second column?

A) 8 and 15

B) 34 and 43

C) 34 and 8

D) 43 and 15

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 069

16) You observe 100 randomly selected college students to find out whether they arrive on time or late for their classes. The table below gives a two-way classification for these students.

For a chi-square test of independence for this contingency table, what are the expected frequencies for the second column, rounded to two decimal places?

A) 7.02 and 10.98

B) 7.37 and 10.43

C) 7.58 and 10.10

D) 6.46 and 11.86

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 070

17) You observe 100 randomly selected college students to find out whether they arrive on time or late for their classes. The table below gives a two-way classification for these students.

To perform a chi-square test of independence for this contingency table at the 1% significance level, what is the critical value of chi-square?

A) 7.879

B) 6.635

C) 10.597

D) 9.210

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 071

18) You observe 100 randomly selected college students to find out whether they arrive on time or late for their classes. The table below gives a two-way classification for these students.

To perform a chi-square test of independence for this contingency table, what is the value of the chi-square test statistic (rounded to three decimal places)?

Diff: 2

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 072

19) You observe 100 randomly selected college students to find out whether they arrive on time or late for their classes. The table below gives a two-way classification for these students.

Do you reject or fail to reject the null hypothesis that the two characteristics are independent at the 1% significance level? (State your answer as "reject" or "fail to reject", but don't include the quotation marks.)

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 073

20) Jean, an expert on dental hygiene, hypothesizes that the dental hygiene of students at the Westwood Elementary School is similar to that of students at Easton Elementary. In order to test her hypothesis, she collects information about children at each school from dentists in the area, recording the number of cavities that each child has had in the past year. Her findings appear in the following table.

The null hypothesis is that the proportions of students with no cavities, one cavity, two cavities, and three or more cavities are relatively the same between schools. What is the value of the test statistic, rounded to three decimal places, that Jean will use?

Diff: 2

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 074

21) You ask 600 randomly selected working adults whether or not they are satisfied with their jobs. The table below gives a two-way classification for these adults.

For a chi-square test of independence for this contingency table, what is the number of degrees of freedom?

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 075

22) You ask 600 randomly selected working adults whether or not they are satisfied with their jobs. The table below gives a two-way classification for these adults.

For a chi-square test of independence for this contingency table, what are the observed frequencies for the second row?

A) 246 and 62

B) 192 and 100

C) 192 and 246

D) 100 and 62

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 076

23) You ask 600 randomly selected working adults whether or not they are satisfied with their jobs. The table below gives a two-way classification for these adults.

For a chi-square test of independence for this contingency table, what are the expected frequencies for the second row, rounded to two decimal places?

A) 226.08 and 87.92

B) 218.62 and 80.36

C) 207.23 and 84.22

D) 239.12 and 73.41

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 077

24) You ask 600 randomly selected working adults whether or not they are satisfied with their jobs. The table below gives a two-way classification for these adults.

For a chi-square test of independence for this contingency table, what are the observed frequencies for the first column?

A) 242 and 67

B) 199 and 92

C) 199 and 242

D) 92 and 67

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 078

25) You ask 600 randomly selected working adults whether or not they are satisfied with their jobs. The table below gives a two-way classification for these adults.

For a chi-square test of independence for this contingency table, what are the expected frequencies for the first column, rounded to two decimal places?

A) 226.08 and 87.92

B) 218.25 and 231.75

C) 207.00 and 243.00

D) 213.75 and 236.25

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 079

26) You ask 600 randomly selected working adults whether or not they are satisfied with their jobs. The table below gives a two-way classification for these adults.

To perform a chi-square test of independence for this contingency table at the 5% significance level, what is the critical value of chi-square?

A) 5.991

B) 7.378

C) 3.841

D) 5.024

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 080

27) You ask 600 randomly selected working adults whether or not they are satisfied with their jobs. The table below gives a two-way classification for these adults.

To perform a chi-square test of independence for this contingency table, what is the value of the chi-square test statistic (rounded to three decimal places)?

Diff: 2

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 081

28) You ask 600 randomly selected working adults whether or not they are satisfied with their jobs. The table below gives a two-way classification for these adults.

For a test of independence, do you reject or fail to reject the null hypothesis at the 5% significance level? (State your answer as "reject" or "fail to reject", but don't include the quotation marks.)

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 082

29) A clinic administers two drugs to two groups of randomly assigned patients to cure the same disease: 70 patients received Drug I and 80 patients received Drug II. The following table gives the information about the numbers of patients cured and those not cured by each of these two drugs.

For a chi-square test of homogeneity for this contingency table, what is the number of degrees of freedom?

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 083

30) A clinic administers two drugs to two groups of randomly assigned patients to cure the same disease: 70 patients received Drug I and 80 patients received Drug II. The following table gives the information about the numbers of patients cured and those not cured by each of these two drugs.

For a chi-square test of homogeneity for this contingency table, what are the observed frequencies for the first row?

A) 59 and 11

B) 59 and 65

C) 65 and 15

D) 11 and 15

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 084

31) A clinic administers two drugs to two groups of randomly assigned patients to cure the same disease: 70 patients received Drug I and 80 patients received Drug II. The following table gives the information about the numbers of patients cured and those not cured by each of these two drugs.

For a chi-square test of homogeneity for this contingency table, what are the expected frequencies for the first row, rounded to two decimal places?

A) 59.73 and 10.27

B) 68.27 and 10.27

C) 68.27 and 11.73

D) 59.73 and 11.73

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 085

32) A clinic administers two drugs to two groups of randomly assigned patients to cure the same disease: 70 patients received Drug I and 80 patients received Drug II. The following table gives the information about the numbers of patients cured and those not cured by each of these two drugs.

For a chi-square test of homogeneity for this contingency table, what are the observed frequencies for the second column?

A) 11 and 20

B) 59 and 60

C) 59 and 11

D) 60 and 20

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 086

33) A clinic administers two drugs to two groups of randomly assigned patients to cure the same disease: 70 patients received Drug I and 80 patients received Drug II. The following table gives the information about the numbers of patients cured and those not cured by each of these two drugs.

For a chi-square test of homogeneity for this contingency table, what are the expected frequencies for the second column, rounded to two decimal places?

A) 15.40 and 17.60

B) 13.20 and 17.60

C) 13.20 and 19.80

D) 15.40 and 19.80

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 087

34) A clinic administers two drugs to two groups of randomly assigned patients to cure the same disease: 70 patients received Drug I and 80 patients received Drug II. The following table gives the information about the numbers of patients cured and those not cured by each of these two drugs.

To perform a chi-square test of homogeneity for this contingency table at the 10% significance level, what is the critical value of chi-square?

A) 5.991

B) 4.605

C) 3.841

D) 2.706

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 088

35) A clinic administers two drugs to two groups of randomly assigned patients to cure the same disease: 70 patients received Drug I and 80 patients received Drug II. The following table gives the information about the numbers of patients cured and those not cured by each of these two drugs.

To perform a chi-square test of homogeneity for this contingency table, what is the value of the chi-square test statistic (rounded to three decimal places)?

Diff: 2

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 089

36) A clinic administers two drugs to two groups of randomly assigned patients to cure the same disease: 70 patients received Drug I and 80 patients received Drug II. The following table gives the information about the numbers of patients cured and those not cured by each of these two drugs.

For a test of homogeneity, will you reject or fail to reject the null hypothesis at the 10% significance level? (State your answer as "reject" or "fail to reject", but don't include the quotation marks.)

Diff: 1

LO: 11.3.0 Demonstrate an understanding of how to perform a test of independence or homogeneity using contingency tables and the chi-square distribution.

Section: 11.3 A Test of Independence or Homogeneity

Question Title: Chapter 11, Testbank Question 090

11.4 Inferences About the Population Variance

1) If a test of hypothesis involves the standard deviation of a single population, which test is used?

A) Test of hypothesis about the variance

B) Goodness-of-fit test

C) χ2 distribution test

D) Independence test or homogeneity test

Diff: 1

LO: 11.4.0 Demonstrate an understanding of how to estimate and test a hypothesis about a population variance.

Section: 11.4 Inferences About the Population Variance

Question Title: Chapter 11, Testbank Question 091

2) A random sample of 25 elements selected from a population produced a variance equal to 3.328. Assume that the population is normally distributed. Based on this sample, the 95% confidence interval for the population variance, rounded to three decimal places, is:

A) 2.029 and 6.441

B) 2.029 and 6.223

C) 1.965 and 6.441

D) 1.965 and 6.223

Diff: 2

LO: 11.4.0 Demonstrate an understanding of how to estimate and test a hypothesis about a population variance.

Section: 11.4 Inferences About the Population Variance

Question Title: Chapter 11, Testbank Question 092

3) A random sample of 25 elements selected from a population produced a variance equal to 14.880. Assume that the population is normally distributed. Based on this sample, the 95% confidence interval for the population standard deviation, rounded to three decimal places, is:

A) 3.012 and 5.366

B) 3.012 and 28.242

C) 8.810 and 5.366

D) 8.810 and 28.242

Diff: 2

LO: 11.4.0 Demonstrate an understanding of how to estimate and test a hypothesis about a population variance.

Section: 11.4 Inferences About the Population Variance

Question Title: Chapter 11, Testbank Question 093

4) A random sample of 16 elements selected from a population produced a variance equal to 13.307. Assume that the population is normally distributed. Based on this sample, the 99% confidence interval for the population variance, rounded to three decimal places, is:

A) 6.085 and 43.383

B) 6.085 and 43.860

C) 6.102 and 43.383

D) 6.102 and 43.860

Diff: 2

LO: 11.4.0 Demonstrate an understanding of how to estimate and test a hypothesis about a population variance.

Section: 11.4 Inferences About the Population Variance

Question Title: Chapter 11, Testbank Question 094

5) A random sample of 16 elements selected from a population produced a variance equal to 3.233. Assume that the population is normally distributed. Based on this sample, the 99% confidence interval for the population standard deviation, rounded to three decimal places, is:

A) 1.216 and 3.247

B) 1.216 and 3.339

C) 1.223 and 3.247

D) 1.223 and 3.339

Diff: 2

LO: 11.4.0 Demonstrate an understanding of how to estimate and test a hypothesis about a population variance.

Section: 11.4 Inferences About the Population Variance

Question Title: Chapter 11, Testbank Question 095

6) A random sample of 20 elements selected from a population produced a variance equal to 12.040. Assume that the population is normally distributed. Based on this sample, the 90% confidence interval for the population variance, rounded to three decimal places, is:

A) 7.589 and 22.611

B) 7.589 and 21.946

C) 7.496 and 22.611

D) 7.496 and 21.946

Diff: 2

LO: 11.4.0 Demonstrate an understanding of how to estimate and test a hypothesis about a population variance.

Section: 11.4 Inferences About the Population Variance

Question Title: Chapter 11, Testbank Question 096

7) A random sample of 20 elements selected from a population produced a variance equal to 7.752. Assume that the population is normally distributed. Based on this sample, the 90% confidence interval for the population standard deviation, rounded to three decimal places, is:

A) 2.210 and 3.816

B) 2.210 and 3.759

C) 2.197 and 3.816

D) 2.197 and 3.759

Diff: 2

LO: 11.4.0 Demonstrate an understanding of how to estimate and test a hypothesis about a population variance.

Section: 11.4 Inferences About the Population Variance

Question Title: Chapter 11, Testbank Question 097

8) A random sample of 29 workers selected from a large company produced a variance of their weekly earnings equal to 5878. Assume that the population is normally distributed. Based on this sample, the 95% confidence interval for the variance of the weekly earnings of all of this company's employees, rounded to three decimal places, is:

A) 3701.761 and 10,751.502

B) 3701.761 and 10,924.200

C) 3723.030 and 10,751.502

D) 3723.030 and 10,924.200

Diff: 2

LO: 11.4.0 Demonstrate an understanding of how to estimate and test a hypothesis about a population variance.

Section: 11.4 Inferences About the Population Variance

Question Title: Chapter 11, Testbank Question 098

9) A random sample of 29 workers selected from a large company produced a variance of their weekly earnings equal to 6859. Assume that the population is normally distributed. Based on this sample, the 95% confidence interval for the standard deviation of the weekly earnings of all of this company's employees, rounded to the nearest cent, is:

A) 65.72 and 112.01

B) 65.72 and 112.904

C) 65.912 and 112.01

D) 65.912 and 112.904

Diff: 2

LO: 11.4.0 Demonstrate an understanding of how to estimate and test a hypothesis about a population variance.

Section: 11.4 Inferences About the Population Variance

Question Title: Chapter 11, Testbank Question 099

10) A random sample of 25 elements selected from a population produced a variance equal to 8.195. The null hypothesis is that the population variance is less than or equal to4.50 and the alternative hypothesis is that the population variance is greater than 4.50. Assume that the population is normally distributed. The significance level is 1%. The critical value of chi-square is:

A) 42.980

B) 45.559

C) 41.638

D) 44.181

Diff: 1

LO: 11.4.0 Demonstrate an understanding of how to estimate and test a hypothesis about a population variance.

Section: 11.4 Inferences About the Population Variance

Question Title: Chapter 11, Testbank Question 100

11) A random sample of 25 elements selected from a population produced a variance equal to 7.588. The null hypothesis is that the population variance is less than or equal to4.30 and the alternative hypothesis is that the population variance is greater than 4.30. Assume that the population is normally distributed. The significance level is 1%. The value of the chi-square test statistic is, rounded to three decimal places:

Diff: 2

LO: 11.4.0 Demonstrate an understanding of how to estimate and test a hypothesis about a population variance.

Section: 11.4 Inferences About the Population Variance

Question Title: Chapter 11, Testbank Question 101

12) A random sample of 25 elements selected from a population produced a variance equal to 5.742. The null hypothesis is that the population variance is less than or equal to3.75 and the alternative hypothesis is that the population variance is greater than 3.75. Assume that the population is normally distributed. Do you reject or fail to reject the null hypothesis at the 1% significance level? (State your answer as "reject" or "fail to reject", but don't include the quotation marks.)

Diff: 1

LO: 11.4.0 Demonstrate an understanding of how to estimate and test a hypothesis about a population variance.

Section: 11.4 Inferences About the Population Variance

Question Title: Chapter 11, Testbank Question 102

13) A random sample of 20 elements selected from a population produced a variance equal to 3.824. The null hypothesis is that the population variance is equal to 9.70 and the alternative hypothesis is that the population variance is not equal to 9.70. Assume that the population is normally distributed. The significance level is 5%. The critical values of chi-square are:

A) 10.117 and 30.144

B) 8.231 and 31.526

C) 7.633 and 36.191

D) 8.907 and 32.852

Diff: 1

LO: 11.4.0 Demonstrate an understanding of how to estimate and test a hypothesis about a population variance.

Section: 11.4 Inferences About the Population Variance

Question Title: Chapter 11, Testbank Question 103

14) A random sample of 20 elements selected from a population produced a variance equal to 13.753. The null hypothesis is that the population variance is equal to 18.00 and the alternative hypothesis is that the population variance is not equal to 18.00. Assume that the population is normally distributed. The significance level is 5%. The value of the chi-square test statistic is, rounded to three decimal places:

Diff: 2

LO: 11.4.0 Demonstrate an understanding of how to estimate and test a hypothesis about a population variance.

Section: 11.4 Inferences About the Population Variance

Question Title: Chapter 11, Testbank Question 104

15) A random sample of 20 elements selected from a population produced a variance equal to 11.522. The null hypothesis is that the population variance is equal to 19.35 and the alternative hypothesis is that the population variance is not equal to 19.35. Assume that the population is normally distributed. Do you reject or fail to reject the null hypothesis at the 5% significance level? (State your answer as "reject" or "fail to reject", but don't include the quotation marks.)

Diff: 1

LO: 11.4.0 Demonstrate an understanding of how to estimate and test a hypothesis about a population variance.

Section: 11.4 Inferences About the Population Variance

Question Title: Chapter 11, Testbank Question 105

16) A random sample of 28 elements selected from a population produced a variance equal to 8.871. The null hypothesis is that the population variance is greater than or equal to 19.05 and the alternative hypothesis is that the population variance is less than 19.05. Assume that the population is normally distributed. The significance level is 2.5%. The critical value of chi-square is:

A) 14.573

B) 43.195

C) 41.923

D) 13.844

Diff: 1

LO: 11.4.0 Demonstrate an understanding of how to estimate and test a hypothesis about a population variance.

Section: 11.4 Inferences About the Population Variance

Question Title: Chapter 11, Testbank Question 106

17) A random sample of 28 elements selected from a population produced a variance equal to 9.870. The null hypothesis is that the population variance is greater than or equal to 18.10 and the alternative hypothesis is that the population variance is less than 18.10. Assume that the population is normally distributed. The significance level is 2.5%. The value of the chi-square test statistic is, rounded to three decimal places:

Diff: 2

LO: 11.4.0 Demonstrate an understanding of how to estimate and test a hypothesis about a population variance.

Section: 11.4 Inferences About the Population Variance

Question Title: Chapter 11, Testbank Question 107

18) A random sample of 28 elements selected from a population produced a variance equal to 10.180. The null hypothesis is that the population variance is greater than or equal to 18.80 and the alternative hypothesis is that the population variance is less than 18.80. Assume that the population is normally distributed. Do you reject or fail to reject the null hypothesis at the 2.5% significance level? (State your answer as "reject" or "fail to reject", but don't include the quotation marks.)

Diff: 1

LO: 11.4.0 Demonstrate an understanding of how to estimate and test a hypothesis about a population variance.

Section: 11.4 Inferences About the Population Variance

Question Title: Chapter 11, Testbank Question 108

19) The variance of the prices of all college textbooks was 80.25 last year. A recent sample of 20 college textbooks produced a variance of their prices equal to 138.844. The null hypothesis is that the current variance of the prices of all college textbooks is equal to 80.25 and the alternative hypothesis is that the current variance of the prices of all college textbooks is greater than 80.25. Assume that the prices of college textbooks are normally distributed. The significance level is 1%. The critical value of chi-square is:

A) 36.191

B) 38.582

C) 39.997

D) 37.566

Diff: 1

LO: 11.4.0 Demonstrate an understanding of how to estimate and test a hypothesis about a population variance.

Section: 11.4 Inferences About the Population Variance

Question Title: Chapter 11, Testbank Question 109

20) The variance of the prices of all college textbooks was 82.00 last year. A recent sample of 20 college textbooks produced a variance of their prices equal to 93.306. The null hypothesis is that the current variance of the prices of all college textbooks is equal to 82.00 and the alternative hypothesis is that the current variance of the prices of all college textbooks is greater than 82.00. Assume that the prices of college textbooks are normally distributed. The significance level is 1%. The value of the chi-square test statistic is, rounded to three decimal places:

Diff: 2

LO: 11.4.0 Demonstrate an understanding of how to estimate and test a hypothesis about a population variance.

Section: 11.4 Inferences About the Population Variance

Question Title: Chapter 11, Testbank Question 110

21) The variance of the prices of all college textbooks was 81.30 last year. A recent sample of 20 college textbooks produced a variance of their prices equal to 87.972. The null hypothesis is that the current variance of the prices of all college textbooks is equal to 81.30 and the alternative hypothesis is that the current variance of the prices of all college textbooks is greater than 81.30. Assume that the prices of college textbooks are normally distributed. Do you reject or fail to reject the null hypothesis at the 1% significance level? (State your answer as "reject" or "fail to reject", but don't include the quotation marks.)

Diff: 1

LO: 11.4.0 Demonstrate an understanding of how to estimate and test a hypothesis about a population variance.

Section: 11.4 Inferences About the Population Variance

Question Title: Chapter 11, Testbank Question 111

22) A researcher claims that the variance of the heights of all female college basketball players is 4.55 square inches. A random sample of 28 female college basketball players produced a variance of their heights equal to 3.882 square inches. The null hypothesis is that the variance of the heights of all female college basketball players is equal to4.55 square inches and the alternative hypothesis is that the variance of the heights of all female college basketball players is not equal to 4.55. Assume that the population is normally distributed. The significance level is 5%. The critical values of chi-square are:

A) 13.844 and 41.923

B) 14.573 and 43.195

C) 15.308 and 44.461

D) 12.879 and 40.113

Diff: 1

LO: 11.4.0 Demonstrate an understanding of how to estimate and test a hypothesis about a population variance.

Section: 11.4 Inferences About the Population Variance

Question Title: Chapter 11, Testbank Question 112

23) A researcher claims that the variance of the heights of all female college basketball players is 4.60 square inches. A random sample of 28 female college basketball players produced a variance of their heights equal to 1.861 square inches. The null hypothesis is that the variance of the heights of all female college basketball players is equal to4.60 square inches and the alternative hypothesis is that the variance of the heights of all female college basketball players is not equal to 4.60. Assume that the population is normally distributed. The significance level is 5%. The value of the chi-square test statistic is, rounded to three decimal places:

Diff: 2

LO: 11.4.0 Demonstrate an understanding of how to estimate and test a hypothesis about a population variance.

Section: 11.4 Inferences About the Population Variance

Question Title: Chapter 11, Testbank Question 113

24) A researcher claims that the variance of the heights of all female college basketball players is 5.35 square inches. A random sample of 28 female college basketball players produced a variance of their heights equal to 6.678 square inches. The null hypothesis is that the variance of the heights of all female college basketball players is equal to5.35 square inches and the alternative hypothesis is that the variance of the heights of all female college basketball players is not equal to 5.35. Assume that the population is normally distributed. The significance level is 5%. Do you reject or fail to reject the null hypothesis at the 10% significance level? (State your answer as "reject" or "fail to reject", but don't include the quotation marks.)

Diff: 1

LO: 11.4.0 Demonstrate an understanding of how to estimate and test a hypothesis about a population variance.

Section: 11.4 Inferences About the Population Variance

Question Title: Chapter 11, Testbank Question 114

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