Ch8 | Verified Test Bank – Conics And Systems Of Nonlinear - Test Bank | College Algebra 5e by Young by Cynthia Y. Young. DOCX document preview.
College Algebra, 5e (Young)
Chapter 8 Conics and Systems of Nonlinear Equations and Inequalities
8.5 Systems of Nonlinear Equations
1) Solve the system of equations by applying the elimination method.
6 + 10y = 136
-6 - 10y = 136
A) (4, 4)
B) (-4, -4)
C) infinite number of solutions
D) no solution
Diff: 1 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Solve a system of nonlinear equations using elimination.
2) Solve the system of equations by applying the elimination method.
- 12y = -20
2x - 6y = -8
A) (2, 0)
B) (2, 2)
C) (0, 2)
D) no solution
Diff: 3 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Solve a system of nonlinear equations using elimination.
3) Solve the system of equations by applying the substitution method.
-
= 15
xy = 56
A) (8, 7), (-8, -7)
B) (8, 7)
C) (56, 1)
D) no solution
Diff: 3 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Solve a system of nonlinear equations using substitution.
4) Solve the system of equations by applying the substitution method.
+
= 74
xy = 35
A) (5, 7)
B) (5, 7), (-5, -7)
C) (-7, -5)
D) no solution
Diff: 3 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Solve a system of nonlinear equations using substitution.
5) Solve the system of equations by applying the substitution method.
-
= -40
xy = -21
A) (3, 7), (-3, -7)
B) (3, -7)
C) (-3, 7)
D) (-3, 7), (3, -7)
Diff: 3 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Solve a system of nonlinear equations using substitution.
6) Solve the system of equations by applying the substitution method.
+
= 25
x - y = -7
A) (5, 0)
B) (-4, -3)
C) (-3, 4), (-4, 3)
D) no solution
Diff: 3 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Solve a system of nonlinear equations using substitution.
7) Solve the system of equations by applying the substitution method.
y = - 7
y = 9x - 7
A) (9, 74)
B) (0, -7), (9, 74)
C) (0, 7), (9, 0)
D) no solution
Diff: 2 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Solve a system of nonlinear equations using substitution.
8) Solve the system of equations by applying the substitution method.
y = - 7
y = x - 8
A) (8, 0), (, 0)
B) (8, 0)
C) (, 0)
D) no solution
Diff: 2 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Solve a system of nonlinear equations using substitution.
9) Solve the system of equations by applying the substitution method.
+ 7x +
- 21y = -98
x - y = 0
A) (7, 7)
B) (-7, -7)
C) (2, 2), (-7, -7)
D) no solution
Diff: 3 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Solve a system of nonlinear equations using substitution.
10) Graph each equation and find the point(s) of intersection.
+
= 64
x - y = -8
A) (8, 0), (0, -8)
B) (0, 8), (-8, 0)
C) (0, 8)
D) no solution
Diff: 3 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Interpret the algebraic solution graphically.
11) Graph each equation and find the point(s) of intersection.
+
= 49
- y = -7
A) (0, 7)
B) (-7, 0)
C) (-7, 38)
D) no solution
Diff: 2 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Interpret the algebraic solution graphically.
12) Graph each equation and find the point(s) of intersection.
+ y = 7
- y = -7
A) (0, -7)
B) (0, 7)
C) (7, -7)
D) no solution
Diff: 1 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Interpret the algebraic solution graphically.
13) Graph each equation and find the point(s) of intersection.
+
= 80
y = -8
A) (4, -8)
B) (0, -8)
C) (4, -8), (-4, -8)
D) no solution
Diff: 1 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Interpret the algebraic solution graphically.
14) Graph each equation and find the point(s) of intersection.
+
= 1
-x + y = 4
A) (-4, 0)
B) (0, 4)
C) (0, 1)
D) no solution
Diff: 2 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Interpret the algebraic solution graphically.
15) Solve the system of equations by apply any method.
+
= 18
-x + y = 0
A) (3, 3), (-3, -3)
B) (3, 3)
C) (3, 0)
D) no solution
Diff: 2 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Solve a system of nonlinear equations using elimination.
16) Solve the system of equations by applying the elimination method.
+ y = -24
-13x - y = -6
Diff: 2 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Solve a system of nonlinear equations using elimination.
17) Solve the system of equations by applying the substitution method.
y = + 8
y = x + 2
Diff: 2 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Solve a system of nonlinear equations using substitution.
18) Graph each equation and find the point(s) of intersection.
+ y = 20
- y = -20
Diff: 1 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Interpret the algebraic solution graphically.
19) The difference of two numbers is 77 and the difference of their squares is 5,159. Find the numbers.
Diff: 3 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Eliminate extraneous solutions.
20) A family moves into a new home and decides to fence in the yard to give its dog room to roam. If the area that will be fenced in is rectangular and has an area of 30,000 square feet, and the length is three times as much as the width, how many linear feet of fence should they buy?
A) 693 feet
B) 800 feet
C) 500 feet
D) 700 feet
Diff: 3 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Solve a system of nonlinear equations using elimination.; Solve a system of nonlinear equations using substitution.
21) Solve the system of equations by applying the elimination method.
+ 5y = -30
10x - 5y = 5
Diff: 2 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Solve a system of nonlinear equations using elimination.
22) Solve the system of equations by applying the elimination method.
+ 3y = 31
3x - 3y = -21
Diff: 2 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Solve a system of nonlinear equations using elimination.
23) Solve the system of equations by applying the elimination method.
-3 +
= -9
- 5y = -2
Diff: 2 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Solve a system of nonlinear equations using elimination.
24) Solve the system of equations by applying the elimination method.
( y) = 2
(4y) = 3
Diff: 3 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Solve a system of nonlinear equations using elimination.
25) Solve the system of equations by applying the elimination method.
2 - 4
= 10
3 + 4
= 35
Diff: 2 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Solve a system of nonlinear equations using elimination.
26) Solve the system of equations by applying the elimination method.
+
= 19
-
= -11
Diff: 2 Var: 1
Chapter/Section: Ch 08, Sec 05
Learning Objective: Eliminate extraneous solutions.; Solve a system of nonlinear equations using elimination.
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