Ch.8 Advanced Theories of Covalent Bonding Exam Questions - Chemistry 2e Complete Test Bank by Paul Flowers. DOCX document preview.
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Chapter 08: Advanced Theories of Covalent Bonding
- Based on valence bond theory, which statement best describes the electron geometry, bonding and hybridization of the central atom in carbon tetrachloride? (Outcome # 12) (DOK 3)
- The electron geometry of carbon in carbon tetrachloride is tetrahedral with a sp3 hybridization. The C-Cl bond is of σ-character.
- The electron geometry of carbon in carbon tetrachloride is tetrahedral with a sp2 hybridization. The C-Cl bond is of σ-character.
- The electron geometry of carbon in carbon tetrachloride is tetrahedral with a sp3 hybridization. The C-Cl bond is of π-character.
- Based on valence bond theory, which statement best describes the electron geometry and hybridization of the central atom(s) in acetylene? (Outcome # 12) (DOK 2)
- The electron geometry of the 2 carbons in acetylene is tetrahedral with a sp3 hybridization.
- The electron geometry of the 2 carbons in acetylene is trigonal planar with a sp2 hybridization.
- The electron geometry of the 2 carbons in acetylene is linear with a sp hybridization.
- Which statement best describe the structure of a carbonate anion? (Outcome # 12) (DOK 3)
- The electron geometry of carbon in a carbonate anion is trigonal planar with a sp2 hybridization and bond angles are 120°. There is a π-bond formed between a non-hybridized “C” p-orbital overlapping with an “O” p-orbital.
- The electron geometry of carbon in a carbonate anion is trigonal planar with a sp2 hybridization and bond angles are <120°. There is a π-bond formed between a non-hybridized “C” p-orbital overlapping with an “O” p-orbital.
- The electron geometry of carbon in a carbonate anion is trigonal planar with a sp2 hybridization and bond angles are <120°. There is a π-bond formed between a hybridized “C” p-orbital overlapping with an “O” p-orbital.
- Based on valence bond theory, what is the hybridization of the central atom(s) in C2F4? (Outcome # 12) (DOK 1)
- both carbons are sp2
- both carbons are sp3
- one carbon is sp3 and the other carbon is sp2
- Which element contains triple covalent bonds? (Outcome # 9) (DOK 1)
- oxygen
- nitrogen
- iodine
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