Ch.19 Ionic Equilibria In Aqueous Systems Test Bank Docx - Chemistry Molecular Nature 8e Complete Test Bank by Martin Silberberg. DOCX document preview.
Chapter 19 Test Bank
Ionic Equilibria in Aqueous Systems
1. Which of the following aqueous mixtures would be a buffer system?
A. HCl, NaCl
B. HNO3, NaNO3
C. H3PO4, H2PO4–
D. H2SO4, CH3COOH
E. NH3, NaOH
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Easy
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
2. Which, if any, of the following aqueous mixtures would be a buffer system?
A. CH3COOH, NaH2PO4
B. H2CO3, HCO3–
C. H2PO4–, HCO3–
D. HSO4–, HSO3–
E. None of these choices are correct.
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Easy
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
3. Equal volumes of the following pairs of solutions are mixed. Which pair will produce a buffer solution?
A. 0.10 mol L–1 HCl and 0.05 mol L–1 NaOH
B. 0.10 mol L–1 HCl and 0.15 mol L–1 NH3
C. 0.10 mol L–1 HCl and 0.05 mol L–1 NH3
D. 0.10 mol L–1 HCl and 0.20 mol L–1 CH3COOH
E. 0.10 mol L–1 HCl and 0.20 mol L–1 NaCl
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
4. Which one of the following aqueous solutions, when mixed with an equal volume of 0.10 mol L–1 aqueous NH3, will produce a buffer solution?
A. 0.10 mol L–1 HCl
B. 0.20 mol L–1 HCl
C. 0.10 mol L–1 CH3COOH
D. 0.050 mol L–1 NaOH
E. 0.20 mol L–1 NH4Cl
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Easy
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
5. Which one of the following pairs of 0.100 mol L–1 solutions, when mixed, will produce a buffer solution?
A. 50. mL of aqueous CH3COOH and 25. mL of aqueous HCl
B. 50. mL of aqueous CH3COOH and 100. mL of aqueous NaOH
C. 50. mL of aqueous NaOH and 25. mL of aqueous HCl
D. 50. mL of aqueous CH3COONa and 25. mL of aqueous NaOH
E. 50. mL of aqueous CH3COOH and 25. mL of aqueous CH3COONa
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
6. Which of the following has the highest buffer capacity?
A. 0.10 M H2PO4–/0.10 M HPO42–
B. 0.50 M H2PO4–/0.10 M HPO42–
C. 0.10 M H2PO4–/0.50 M HPO42–
D. 0.50 M H2PO4–/0.50 M HPO42–
E. They all have the same buffer capacity.
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Easy
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
7. A popular buffer solution consists of carbonate (CO32–) and hydrogen carbonate (HCO3–) conjugate acid-base pair. Which, if any, of the following such buffers has the highest buffer capacity?
A. 0.9 M CO32– and 0.1 M HCO3–
B. 0.1 M CO32– and 0.9 M HCO3–
C. 0.5 M CO32– and 0.5 M HCO3–
D. 0.1 M CO32– and 0.1 M HCO3–
E. They all have the same buffer capacity.
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Easy
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
8. A popular buffer solution consists of carbonate (CO32–) and hydrogen carbonate (HCO3–) conjugate acid-base pair. Which, if any, of the following such buffers can neutralize the greatest amount of added hydrochloric acid, while remaining within its buffer range?
A. 1 L of 0.9 M CO32– and 0.1 M HCO3–
B. 1 L of 0.1 M CO32– and 0.9 M HCO3–
C. 1 L of 0.5 M CO32– and 0.5 M HCO3–
D. 1 L of 0.1 M CO32– and 0.1 M HCO3–
E. They can all neutralize the same amount of hydrochloric acid.
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
9. Which of the following acids should be used to prepare a buffer with a pH of 4.5?
A. HOC6H4OCOOH, Ka = 1.0 × 10–3
B. C6H4(COOH)2, Ka = 2.9 × 10–4
C. CH3COOH, Ka = 1.8 × 10–5
D. C5H5O5COOH, Ka = 4.0 × 10–6
E. HBrO, Ka = 2.3 × 10–9
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
10. Citric acid has an acid dissociation constant of 8.4 × 10–4. It would be most effective for preparation of a buffer with a pH of
A. 2.
B. 3.
C. 4.
D. 5.
E. 6.
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Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
11. A buffer is to be prepared by adding solid sodium acetate to 0.10 M CH3COOH. Which of the following concentrations of sodium acetate will produce the most effective buffer?
A. 3.0 M CH3COONa
B. 2.5 M CH3COONa
C. 2.0 M CH3COONa
D. 1.5 M CH3COONa
E. 0.30 M CH3COONa
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
12. An acetate buffer has a pH of 4.40. Which of the following changes will cause the pH to decrease?
A. dissolving a small amount of solid sodium acetate
B. adding a small amount of dilute hydrochloric acid
C. adding a small amount of dilute sodium hydroxide
D. dissolving a small amount of solid sodium chloride
E. diluting the buffer solution with water
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Easy
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
13. A phosphate buffer (H2PO4–/HPO42-) has a pH of 8.3. Which of the following changes will cause the pH to increase?
A. dissolving a small amount of Na2HPO4
B. dissolving a small amount of NaH2PO4
C. adding a small amount of dilute hydrochloric acid
D. adding a small amount of dilute phosphoric acid
E. making the buffer more concentrated by removing some water
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Easy
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
14. What will be the effect of adding 0.5 mL of 0.1 M NaOH to 100 mL of an acetate buffer in which [CH3COOH] = [CH3COO–] = 0.5 M?
A. The pH will increase slightly.
B. The pH will increase significantly.
C. The pH will decrease slightly.
D. The pH will decrease significantly.
E. Since it is a buffer solution, the pH will not be affected.
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Easy
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
15. What will be the effect of adding 0.5 mL of 0.1 M HCl to 100 mL of a phosphate buffer in which [H2PO4–] = [HPO42–] = 0.35 M?
A. The pH will increase slightly.
B. The pH will increase significantly.
C. The pH will decrease slightly.
D. The pH will decrease significantly.
E. Since it is a buffer solution, the pH will not be affected.
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Easy
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
16. Buffer solutions with the component concentrations shown below were prepared. Which of them should have the lowest pH?
A. [CH3COOH] = 0.25 M, [CH3COO–] = 0.25 M
B. [CH3COOH] = 0.75 M, [CH3COO–] = 0.75 M
C. [CH3COOH] = 0.75 M, [CH3COO–] = 0.25 M
D. [CH3COOH] = 0.25 M, [CH3COO–] = 0.75 M
E. [CH3COOH] = 1.00 M, [CH3COO–] = 1.00 M
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
17. Buffer solutions with the component concentrations shown below were prepared. Which of them should have the highest pH?
A. [H2PO4–] = 0.50 M, [HPO42–] = 0.50 M
B. [H2PO4–] = 1.0 M, [HPO42–] = 1.0 M
C. [H2PO4–] = 1.0 M, [HPO42–] = 0.50 M
D. [H2PO4–] = 0.50 M, [HPO42–] = 1.0 M
E. [H2PO4–] = 0.75 M, [HPO42–] = 1.0 M
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
18. A buffer is prepared by adding 0.5 mol of solid sodium hydroxide to 1.0 L of 1.0 M acetic acid (CH3COOH). What is the pH of the buffer?
A. The pH will be pKa – 0.30, where pKa is that of acetic acid.
B. The pH will be greater than the pKa for acetic acid.
C. The pH will be less than the value in answer a.
D. The pH will be equal to the pKa for acetic acid.
E. More information is needed to solve the problem.
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
19. A solution is prepared by adding 100 mL of 0.2 M hydrochloric acid to 100 mL of 0.4 M sodium formate. Is this a buffer solution, and if so, what is its pH?
A. It is a buffer, pH > pKa of formic acid.
B. It is a buffer, pH < pKa of formic acid.
C. It is a buffer, pH = pKa of formic acid.
D. It is a buffer, pH = pKb of sodium formate.
E. Since hydrochloric acid is a strong acid, this is not a buffer.
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
20. A buffer is prepared by adding 100 mL of 0.50 M sodium hydroxide to 100 mL of 0.75 M propanoic acid. Is this a buffer solution, and if so, what is its pH?
A. It is a buffer, pH > pKa of propanoic acid.
B. It is a buffer, pH < pKa of propanoic acid.
C. It is a buffer, pH = pKa of propanoic acid.
D. It is a buffer, pH = pKb of sodium propanoate.
E. Since sodium hydroxide is a strong base, this is not a buffer.
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
21. A solution is prepared by adding 500 mL of 0.3 M NaClO to 500 mL of 0.4 M HClO. What is the pH of this solution?
A. The pH will be greater than the pKa of hypochlorous acid.
B. The pH will be less than the pKa of hypochlorous acid.
C. The pH will be equal to the pKa of hypochlorous acid.
D. The pH will equal the pKb of sodium hypochlorite.
E. None of these choices are correct.
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
22. What is the pH of a buffer that consists of 0.45 M CH3COOH and 0.35 M CH3COONa?
Ka = 1.8 × 10–5
A. 4.49
B. 4.64
C. 4.85
D. 5.00
E. 5.52
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
23. What is the pH of a solution that consists of 0.50 M H2C6H6O6 (ascorbic acid) and 0.75 M NaHC6H6O6 (sodium ascorbate)? For ascorbic acid, Ka = 6.8 × 10–5
A. 3.76
B. 3.99
C. 4.34
D. 4.57
E. 5.66
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
24. What is the pH of a buffer that consists of 0.20 M NaH2PO4 and 0.40 M Na2HPO4?
For NaH2PO4, Ka = 6.2 × 10–8
A. 6.51
B. 6.91
C. 7.51
D. 7.90
E. 8.13
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
25. What is the [H3O+] in a buffer that consists of 0.30 M HCOOH and 0.20 M HCOONa?
For HCOOH, Ka = 1.7 × 10–4
A. 1.1 × 10–4 M
B. 2.6 × 10–4 M
C. 4.3 × 10–4 M
D. 6.7 × 10–5 M
E. None of these choices are correct.
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
26. What is the [H3O+] in a solution that consists of 1.2 M HClO and 2.3 M NaClO?
Ka = 3.5 × 10–8
A. 7.8 × 10–9 M
B. 1.8 × 10–8 M
C. 6.7 × 10–8 M
D. 1.6 × 10–7 M
E. None of these choices are correct.
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
27. What is the [H3O+] in a solution that consists of 0.15 M C2N2H8 (ethylene diamine) and 0.35 C2N2H9Cl? Kb = 4.7 × 10–4
A. 2.0 × 10–3 M
B. 1.1 × 10–3 M
C. 6.3 × 10–9 M
D. 2.1 × 10–10 M
E. 5.0 × 10–11 M
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
28. What is the [H3O+] in a solution that consists of 1.5 M NH3 and 2.5 NH4Cl? Kb = 1.8 × 10–5
A. 1.1 × 10–5 M
B. 3.0 × 10–6 M
C. 3.3 × 10–9 M
D. 9.3 × 10–10 M
E. None of these choices are correct.
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
29. What is the pKa for the acid HA if a solution of 0.65 M HA and 0.85 M NaA has a pH of 4.75?
A. < 4.00
B. 4.63
C. 4.87
D. 5.02
E. > 5.50
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
30. A formic acid buffer containing 0.50 M HCOOH and 0.50 M HCOONa has a pH of 3.77. What will the pH be after 0.010 mol of NaOH has been added to 100.0 mL of the buffer?
A. 3.67
B. 3.78
C. 3.81
D. 3.85
E. 3.95
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Hard
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
31. An acetic acid buffer containing 0.50 M CH3COOH and 0.50 M CH3COONa has a pH of 4.74. What will the pH be after 0.0020 mol of HCl has been added to 100.0 mL of the buffer?
A. 4.77
B. 4.71
C. 4.68
D. 4.62
E. None of these choices are correct.
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Hard
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
32. A buffer is prepared by adding 300.0 mL of 2.0 M NaOH to 500.0 mL of 2.0 M CH3COOH. What is the pH of this buffer? Ka = 1.8 × 10–5
A. 4.57
B. 4.52
C. 4.87
D. 4.92
E. 4.97
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
33. A buffer is prepared by adding 1.00 L of 1.0 M HCl to 750 mL of 1.5 M NaHCOO. What is the pH of this buffer? Ka = 1.7 × 10–4
A. 2.87
B. 3.72
C. 3.82
D. 3.95
E. 4.66
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
34. If 10.0 g of NaF and 20.0 g of HF are dissolved in water to make one liter of solution, what will the pH be? For HF, Ka = 6.8 × 10–4.
A. 7.13
B. 2.54
C. 1.57
D. 3.17
E. 4.86
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
35. A solution is prepared by dissolving 20.0 g of K2HPO4 and 25.0 g of KH2PO4 in enough water to produce 1.0 L of solution. What is the pH of this buffer? For phosphoric acid (H3PO4), Ka2 = 6.2 × 10–8.
A. 7.70
B. 7.42
C. 7.21
D. 7.00
E. 6.72
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
36. You need to use KH2PO4 and K2HPO4 to prepare a buffer with a pH of 7.45. Which of the following ratios of [base]/[acid] is required? For phosphoric acid, (H3PO4), Ka2 = 6.2 × 10–8.
A. [base]/[acid] = 1.75
B. [base]/[acid] = 1.27
C. [base]/[acid] = 1.24
D. [base]/[acid] = 0.79
E. [base]/[acid] = 0.57
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Easy
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
37. You need to prepare a buffer solution with a pH of 4.00, using NaF and HF. What ratio of the ratio of [base]/[acid] should be used in making the buffer? For HF, Ka = 7.2 × 10–4.
A. [base]/[acid] = 0.14
B. [base]/[acid] = 0.42
C. [base]/[acid] = 2.36
D. [base]/[acid] = 7.20
E. None of these choices are correct.
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Easy
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
38. The pH of blood is 7.35. It is maintained in part by the buffer system composed of carbonic acid (H2CO3) and the bicarbonate (hydrogen carbonate, HCO3–) ion. What is the ratio of [bicarbonate]/[carbonic acid] at this pH? For carbonic acid, Ka1 = 4.2 × 10–7.
A. [bicarbonate]/[carbonic acid] = 0.11
B. [bicarbonate]/[carbonic acid] = 0.38
C. [bicarbonate]/[carbonic acid] = 2.65
D. [bicarbonate]/[carbonic acid] = 9.4
E. None of these choices are correct.
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Easy
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
39. What mass of NaF must be added to 50.0 mL of a 0.500 M HF solution to achieve a pH of 3.25?
For HF, Ka = 7.2 × 10–4.
A. 1.3 g
B. 0.69 g
C. 6.9 g
D. 23 g
E. 1.5 g
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
40. Two buffer solutions are prepared using acetic acid and sodium acetate. Solution A contains 20.0 g of acetic acid (CH3COOH) and 5.0 g of sodium acetate CH3COONa). Solution B contains 10.0 g of acetic acid and 25.0 g of sodium acetate. What is the difference between the pH values of these two solutions? For acetic acid, Ka = 1.8 × 10–5.
A. 0.0
B. 1.0
C. 2.0
D. 2.3
E. 4.6
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Hard
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
41. A buffer is prepared by adding 150 mL of 1.0 M NaOH to 250 mL of 1.0 M NaH2PO4. How many moles of HCl must be added to this buffer solution to change the pH by 0.18 units? If necessary, assume the total volume remains unchanged at 400 mL.
A. 0.025 mol HCl
B. 0.063 mol HCl
C. 0.082 mol HCl
D. 0.50 mol HCl
E. 1.0 mol HCl
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Hard
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
42. At the equivalence point in an acid-base titration
A. the [H3O+] equals the Ka of the acid.
B. the [H3O+] equals the Ka of the indicator.
C. the amounts of acid and base which have been combined are in their stoichiometric ratio.
D. the pH is 7.0.
E. the pH has reached a maximum.
Accessibility: Keyboard Navigation
Bloom's: 1. Remember
Difficulty: Easy
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
43. When a strong acid is titrated with a strong base, the pH at the equivalence point
A. is greater than 7.0.
B. is equal to 7.0.
C. is less than 7.0, but is not 3.5.
D. is equal to the pKa of the acid.
E. is equal to 3.5.
Accessibility: Keyboard Navigation
Bloom's: 1. Remember
Difficulty: Easy
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
44. When a weak acid is titrated with a strong base, the pH at the equivalence point
A. is greater than 7.0.
B. is equal to 7.0.
C. is less than 7.0.
D. is equal to the pKa of the acid.
E. is equal to 14.0 – pKb, where pKb is that of the base.
Accessibility: Keyboard Navigation
Bloom's: 1. Remember
Difficulty: Easy
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
45. When a strong acid is titrated with a weak base, the pH at the equivalence point
A. is greater than 7.0.
B. is equal to 7.0.
C. is less than 7.0.
D. is equal to the pKa of the acid.
E. is equal to the pKb of the base.
Accessibility: Keyboard Navigation
Bloom's: 1. Remember
Difficulty: Easy
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
46. When a weak acid is titrated with a weak base, the pH at the equivalence point
A. is greater than 7.0.
B. is equal to 7.0.
C. is less than 7.0.
D. is determined by the sizes of Ka and Kb.
E. is no longer affected by addition of base.
Accessibility: Keyboard Navigation
Bloom's: 1. Remember
Difficulty: Easy
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
47. Which one of the following is the best representation of the titration curve that will be obtained in the titration of a weak acid (0.10 mol L–1) with a strong base of the same concentration?
A. A
B. B
C. C
D. D
E. E
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
48. Which one of the following is the best representation of the titration curve that will be obtained in the titration of a weak base (0.10 mol L–1) with HCl of the same concentration?
A. A
B. B
C. C
D. D
E. E
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
49. The indicator propyl red has Ka = 3.3 × 10–6. What would be the approximate pH range over which it would change color?
A. 3.5–5.5
B. 4.5–6.5
C. 5.5–7.5
D. 6.5–8.5
E. None of these choices are correct.
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
50. Which of the following indicators would be the best to use when 0.050 M benzoic acid (Ka = 6.6 × 10–5) is titrated with 0.05 M NaOH?
A. bromphenol blue, pH range: 3.0–4.5
B. bromcresol green, pH range: 3.8–5.4
C. alizarin, pH range: 5.7–7.2
D. phenol red, pH range: 6.9–8.2
E. phenolphthalein, pH range: 8.0–10.1
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
51. A 50.0-mL sample of 0.50 M HCl is titrated with 0.50 M NaOH. What is the pH of the solution after 28.0 mL of NaOH have been added to the acid?
A. 0.85
B. 0.75
C. 0.66
D. 0.49
E. 3.8
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
52. A 20.0-mL sample of 0.25 M HNO3 is titrated with 0.15 M NaOH. What is the pH of the solution after 30.0 mL of NaOH have been added to the acid?
A. 2.00
B. 1.60
C. 1.05
D. 1.00
E. None of these choices are correct.
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
53. A 20.0-mL sample of 0.30 M HBr is titrated with 0.15 M NaOH. What is the pH of the solution after 40.3 mL of NaOH have been added to the acid?
A. 2.95
B. 3.13
C. 10.87
D. 11.05
E. 13.14
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
54. A 35.0-mL sample of 0.20 M LiOH is titrated with 0.25 M HCl. What is the pH of the solution after 23.0 mL of HCl have been added to the base?
A. 1.26
B. 1.67
C. 12.33
D. 12.74
E. 13.03
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
55. When 20.0 mL of 0.15 M hydrochloric acid is mixed with 20.0 mL of 0.10 M sodium hydroxide, the pH of the resulting solution is
A. 0.00.
B. 12.40.
C. 1.60.
D. 0.82.
E. 7.00.
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
56. A 25.0-mL sample of 0.35 M HCOOH is titrated with 0.20 M KOH. What is the pH of the solution after 25.0 mL of KOH has been added to the acid? Ka = 1.77 × 10–4
A. 4.00
B. 3.88
C. 3.63
D. 3.51
E. 3.47
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Hard
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
57. A 10.0-mL sample of 0.75 M CH3CH2COOH is titrated with 0.30 M NaOH. What is the pH of the solution after 22.0 mL of NaOH have been added to the acid? Ka = 1.3 × 10–5
A. 5.75
B. 4.94
C. 4.83
D. 4.02
E. 3.95
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Hard
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
58. A 25.0-mL sample of 0.10 M C2H3NH2 (ethylamine) is titrated with 0.15 M HCl. What is the Ph of the solution after 9.00 mL of acid have been added to the amine? Kb = 6.5 × 10–4
A. 11.08
B. 10.88
C. 10.74
D. 10.55
E. 10.49
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Hard
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
59. A 25.0-mL sample of 1.00 M NH3 is titrated with 0.15 M HCl. What is the pH of the solution after 15.00 mL of acid have been added to the ammonia solution? Kb = 1.8 × 10–5
A. 10.26
B. 9.30
C. 9.21
D. 8.30
E. 8.21
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Hard
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
60. A 20.0-mL sample of 0.30 M HClO was titrated with 0.30 M NaOH. The following data were collected during the titration.
mL NaOH added 5.00 10.00 1.00 2.00
pH 6.98 7.46 7.93 10.31
What is the Ka for HClO?
A. 1.1 × 10–7
B. 3.5 × 10–8
C. 1.2 × 10–8
D. 4.9 × 10–11
E. None of these choices are correct.
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
61. Which one of the following is the best representation of the titration curve that will be obtained in the titration of a weak diprotic acid H2A (0.10 mol L–1) with a strong base of the same concentration?
A. A
B. B
C. C
D. D
E. E
Bloom's: 2. Understand
Difficulty: Hard
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
62. A diprotic acid H2A has Ka1 = 1 × 10–4 and Ka2 = 1 × 10–8. The corresponding base A2– is titrated with aqueous HCl, both solutions being 0.1 mol L–1. Which one of the following diagrams best represents the titration curve which will be seen?
A. A
B. B
C. C
D. D
E. E
Bloom's: 2. Understand
Difficulty: Hard
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
63. A 20.0-mL sample of 0.50 M H2C6H6O6 (ascorbic acid, a diprotic acid) was titrated with 0.50 M NaOH. The following data were gathered during the titration.
mL NaOH added 10.00 20.00 30.00 40.00
pH 4.17 5.21 11.55 12.89
What is Ka2 for ascorbic acid?
A. 6.8 × 10–5
B. 6.2 × 10–6
C. 6.2 × 10–7
D. 6.2 × 10–8
E. 2.8 × 10–12
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
64. What volume of 0.200 M KOH must be added to 17.5 mL of 0.135 M H3PO4 to reach the third equivalence point?
A. 3.94 mL
B. 11.8 mL
C. 17.5 mL
D. 23.6 mL
E. 35.4 mL
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Easy
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
65. A sample of a monoprotic acid (HA) weighing 0.384 g is dissolved in water and the solution is titrated with aqueous NaOH. If 30.0 mL of 0.100 M NaOH is required to reach the equivalence point, what is the molar mass of HA?
A. 37.0 g/mol
B. 81.0 g/mol
C. 128 g/mol
D. 20.3 g/mol
E. 211 g/mol
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
66. When 0.300 g of a diprotic acid was titrated with 0.100 M LiOH, 40.0 mL of the LiOH solution was needed to reach the second equivalence point. Identify the formula of the diprotic acid.
A. H2S
B. H2C2O4
C. H2C4H4O6
D. H2Se
E. H2Te
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
67. What volume of 0.500 M H2SO4 is needed to react completely with 20.0 mL of 0.400 M LiOH?
A. 4.00 mL
B. 8.00 mL
C. 12.5 mL
D. 16.0 mL
E. 32.0 mL
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Easy
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
68. A change in pH will significantly affect the solubility of which, if any, of the following compounds?
A. BaF2
B. CuCl
C. CuBr
D. AgI
E. None of these choices are correct.
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Solubility and pH
Topic: Solubility
69. The solubility of aluminum hydroxide in water ______________ when dilute nitric acid is added to it.
A. increases
B. decreases
C. does not change
D. first increases, then decreases
E. first decreases, then increases
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Solubility and pH
Topic: Solubility
70. A saturated solution of calcium hydroxide, Ca(OH)2, is in contact with excess solid Ca(OH)2. Which of the following statements correctly describes what will happen when aqueous HCl (a strong acid) is added to this mixture, and system returns to equilibrium? (For Ca(OH)2, Ksp = 6.5 × 10–6)
A. The solubility of Ca(OH)2 will be unchanged.
B. The OH– concentration will decrease and the Ca2+ concentration will increase.
C. The OH– concentration will increase and the Ca2+ concentration will decrease.
D. The concentrations of both Ca2+ and OH– will increase.
E. The solubility of Ca(OH)2 will decrease.
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Solubility and pH
Topic: Solubility
71. The solubility of silver chloride _______________ when dilute nitric acid is added to it.
A. increases
B. decreases
C. does not change
D. first increases, then decreases
E. first decreases, then increases
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Solubility and pH
Topic: Solubility
72. Write the ion product expression for magnesium fluoride, MgF2.
A.
B.
C.
D.
E.
Bloom's: 3. Apply
Difficulty: Easy
Gradable: automatic
Subtopic: Solubility Product (Ksp)
Topic: Solubility
73. Write the ion product expression for silver sulfide, Ag2S.
A.
B.
C.
D.
E.
Bloom's: 3. Apply
Difficulty: Easy
Gradable: automatic
Subtopic: Solubility Product (Ksp)
Topic: Solubility
74. Write the ion product expression for calcium phosphate, Ca3(PO4)2.
A.
B.
C.
D.
E. None of these choices are correct.
Bloom's: 3. Apply
Difficulty: Easy
Gradable: automatic
Subtopic: Solubility Product (Ksp)
Topic: Solubility
75. The solubility of lead(II) chloride is 0.45 g/100 mL of solution. What is the Ksp of PbCl2?
A. 4.9 × 10–2
B. 1.7 × 10–5
C. 8.5 × 10–6
D. 4.2 × 10–6
E. < 1.0 × 10–6
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Solubility Product (Ksp)
Topic: Solubility
76. The solubility of calcium chromate is 1.56 × 10–3 g/100 mL of solution. What is the Ksp for CaCrO4?
A. 2.4 × 10–4
B. 1.5 × 10–5
C. 7.6 × 10–6
D. 1.0 × 10–8
E. < 1.0 × 10–8
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Solubility Product (Ksp)
Topic: Solubility
77. The solubility of silver chromate is 0.0287 g/1.0 L of solution. What is the Ksp for Ag2CrO4?
A. 9.5 × 10–5
B. 2.4 × 10–5
C. 2.6 × 10–12
D. 6.5 × 10–13
E. < 1.0 × 10–13
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Solubility Product (Ksp)
Topic: Solubility
78. The solubility of magnesium phosphate is 2.27 × 10–3 g/1.0 L of solution. What is the Ksp for Mg3(PO4)2?
A. 6.5 × 10–12
B. 6.0 × 10–14
C. 5.2 × 10–24
D. 4.8 × 10–26
E. 1.0 × 10–26
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Hard
Gradable: automatic
Subtopic: Solubility Product (Ksp)
Topic: Solubility
79. Calculate the solubility of barium carbonate, BaCO3, in pure water. Ksp = 2.0 × 10–9
A. 1.3 × 10–3 M
B. 3.2 × 10–5 M
C. 2.2 × 10–5 M
D. 4.5 × 10–5 M
E. 4.0 × 10–18 M
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Solubility Product (Ksp)
Topic: Solubility
80. Calculate the solubility of silver oxalate, Ag2C2O4, in pure water. Ksp = 1.0 × 10–11
A. 1.4 × 10–4 M
B. 8.2 × 10–5 M
C. 5.4 × 10–5 M
D. 3.2 × 10–6 M
E. 2.5 × 10–12 M
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Solubility Product (Ksp)
Topic: Solubility
81. Calculate the solubility of strontium fluoride, SrF2, in pure water. Ksp = 2.6 × 10–9
A. 1.4 × 10–3 M
B. 3.4 × 10–4 M
C. 8.7 × 10–4 M
D. 5.1 × 10–5 M
E. < 1.0 × 10–5 M
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Solubility Product (Ksp)
Topic: Solubility
82. Calculate the solubility of silver phosphate, Ag3PO4, in pure water. Ksp = 2.6 × 10–18
A. 4.0 × 10–5 M
B. 1.8 × 10–5 M
C. 4.0 × 10–6 M
D. 1.5 × 10–5 M
E. < 1.0 × 10–5 M
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Solubility Product (Ksp)
Topic: Solubility
83. Which of the following substances has the greatest solubility in water?
A. MgCO3, Ksp = 3.5 × 10–8
B. NiCO3, Ksp = 1.3 × 10–7
C. AgIO3, Ksp = 3.1 × 10–8
D. CuBr, Ksp = 5.0 × 10–9
E. AgCN, Ksp = 2.2 × 10–16
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Easy
Gradable: automatic
Subtopic: Solubility Product (Ksp)
Topic: Solubility
84. Which of the following substances has the greatest solubility in water?
A. PbI2, Ksp = 7.9 × 10–9
B. BaF2, Ksp = 1.5 × 10–6
C. Ca(OH)2, Ksp = 6.5 × 10–6
D. Zn(IO3)2, Ksp = 3.9 × 10–6
E. Ag2SO4, Ksp = 1.5 × 10–5
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Easy
Gradable: automatic
Subtopic: Solubility Product (Ksp)
Topic: Solubility
85. Which of the following substances has the greatest solubility in water?
A. Ba(IO3)2, Ksp = 1.5 × 10–9
B. PbF2, Ksp = 3.6 × 10–8
C. SrSO4, Ksp = 3.2 × 10–7
D. CuCl, Ksp = 1.9 × 10–7
E. CdS, Ksp = 1.0 × 10–24
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Hard
Gradable: automatic
Subtopic: Solubility Product (Ksp)
Topic: Solubility
86. Barium sulfate (BaSO4) is a slightly soluble salt, with Ksp = 1.1 × 10–10. What mass of Ba2+ ions will be present in 1.0 L of a saturated solution of barium sulfate?
A. < 10–7 g
B. 1.0 × 10–5 g
C. 0.0014 g
D. 0.0024 g
E. > 0.05 g
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Solubility Product (Ksp)
Topic: Solubility
87. Use the following information to calculate the solubility product constant, Ksp, for PbCl2. A saturated solution of PbCl2 in water was prepared and filtered. From the filtrate, 1.0 L was measured out into a beaker and evaporated to dryness. The solid PbCl2 residue recovered in the beaker amounted to 0.0162 moles.
A. Ksp = 6.9 × 10–8
B. Ksp = 4.3 × 10–6
C. Ksp = 1.7 × 10–5
D. Ksp = 2.6 × 10–4
E. Ksp = 3.2 × 10–2
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Hard
Gradable: automatic
Subtopic: Solubility Product (Ksp)
Topic: Solubility
88. Use the following information to calculate the solubility product constant, Ksp, for CuCl. A saturated solution of CuCl in water was prepared and filtered. From the filtrate, 1.0 L was measured out into a beaker and evaporated to dryness. The solid CuCl residue recovered in the beaker was found to weigh 0.041g.
A. Ksp = 1.7 × 10y9
B. Ksp = 1.7 × 10y7
C. Ksp = 1.7 × 10–5
D. Ksp = 4.3 × 10–4
E. Ksp = 2.1 × 10–2
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Hard
Gradable: automatic
Subtopic: Solubility Product (Ksp)
Topic: Solubility
89. Assuming that the total volume does not change after 0.200 g of KCl is added to 1.0 L of a saturated aqueous solution of AgCl, calculate the number of moles of Ag+ ion in the solution after equilibrium has been reestablished. For AgCl, Ksp = 1.8 × 10–10.
A. 1.8 × 10–10 mol Ag+
B. 9.0 × 10–10 mol Ag+
C. 9.0 × 10–9 mol Ag+
D. 6.7 × 10–8 mol Ag+
E. 1.3 × 10–5 mol Ag+
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Solubility and Common Ion Effect
Topic: Solubility
90. What is the maximum mass of KCl that can be added to1.0 L of a 0.010 M lead(II) chloride solution without causing any precipitation of lead(II) chloride? Assume that addition of KCl does not affect the solution volume. For lead(II) chloride, Ksp = 1.6 × 10–5.
A. 3.0 g
B. 1.5 g
C. 0.8 g
D. 1.0 g
E. 0.2 g
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Solubility and Common Ion Effect
Topic: Solubility
91. Calculate the solubility of magnesium sulfate, MgSO4, when placed into a 0.10 M MgCl2 solution. Ksp = 5.9 × 10–3
A. 4.2 × 10–2 M
B. 5.9 × 10–2 M
C. 7.7 × 10–2 M
D. 3.5 × 10–5 M
E. 3.5 × 10–6 M
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Solubility and Common Ion Effect
Topic: Solubility
92. Calculate the solubility of silver chromate, Ag2CrO4, in 0.005 M Na2CrO4. Ksp = 2.6 × 10–12
A. 1.4 × 10–4 M
B. 3.4 × 10–5 M
C. 1.1 × 10–5 M
D. 1.6 × 10–6 M
E. < 1.0 × 10–6 M
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Solubility and Common Ion Effect
Topic: Solubility
93. Calculate the solubility of lead(II) iodide, PbI2, in 0.025 M KI. Ksp = 7.9 × 10–9
A. 4.5 × 10–2 M
B. 2.8 × 10–2 M
C. 8.9 × 10–5 M
D. 5.0 × 10–5 M
E. 1.3 × 10–5 M
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Solubility and Common Ion Effect
Topic: Solubility
94. A lab technician adds 0.015 mol of KOH to 1.00 L of 0.0010 M Ca(NO3)2. Ksp = 6.5 × 10–6 for Ca(OH)2). Which of the following statements is correct?
A. Calcium hydroxide precipitates until the solution is saturated.
B. The solution is unsaturated and no precipitate forms.
C. The concentration of calcium ions is reduced by the addition of the hydroxide ions.
D. One must know Ksp for calcium nitrate to make meaningful predictions on this system.
E. The presence of KOH will raise the solubility of Ca(NO3)2.
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Predicting Precipitation Reactions (Q vs. Ksp)
Topic: Solubility
95. A lab technician adds 0.20 mol of NaF to 1.00 L of 0.35 M cadmium nitrate, Cd(NO3)2. Which of the following statements is correct? Ksp = 6.44 × 10–3 for CdF2.
A. Cadmium fluoride precipitates until the solution is saturated.
B. The solution is unsaturated and no precipitate forms.
C. The solubility of cadmium fluoride is increased by the presence of additional fluoride ions.
D. One must know Ksp for cadmium nitrate to make meaningful predictions on this system.
E. The presence of NaF will raise the solubility of Cd(NO3)2.
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Predicting Precipitation Reactions (Q vs. Ksp)
Topic: Solubility
96. What is the maximum amount of sodium sulfate that can be added to 1.00 L of 0.0020 M Ca(NO3)2 before precipitation of calcium sulfate begins? Ksp = 2.4 × 10–5 for calcium sulfate.
A. 1.2 × 10–2 mol
B. 4.9 × 10–3 mol
C. 3.5 × 10–3 mol
D. 1.2 × 10–5 mol
E. 4.8 × 10–8 mol
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Predicting Precipitation Reactions (Q vs. Ksp)
Topic: Solubility
97. Consider the dissolution of MnS in water (Ksp = 3.0 × 10–14).
MnS(s) + H2O(l) Mn2+(aq) + HS–(aq) + OH–(aq)
How is the solubility of manganese(II) sulfide affected by the addition of aqueous potassium hydroxide to the system?
A. The solubility will be unchanged.
B. The solubility will decrease.
C. The solubility will increase.
D. The amount of KOH added must be known before its effect can be predicted.
E. The pKa of H2S is needed before a reliable prediction can be made.
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Solubility and pH
Topic: Solubility
98. The lab technician Anna Lytic adds 2.20 mol KOH to 1.00 L of 0.5 M Al(NO3)3. What is the concentration of aluminum ions after the aluminum nitrate has reacted with the potassium hydroxide? Kf = 3.0 × 1033 for Al(OH)4–
A. 1.8 × 10–7 M
B. 9.1 × 10–18 M
C. 1.0 × 10–31 M
D. 3.3 × 10–34 M
E. 7.1 × 10–36 M
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Hard
Gradable: automatic
Subtopic: Predicting Precipitation Reactions (Q vs. Ksp)
Topic: Solubility
99. A solution is prepared by adding 4.50 mol of sodium hydroxide to 1.00 L of 1.00 M Co(NO3)2. What is the equilibrium concentration of cobalt ions? Kf = 5.0 × 109 for Co(OH)42–
A. 1.1 × 10–2 M
B. 1.4 × 10–5 M
C. 3.2 × 10–9 M
D. 2.0 × 10–10 M
E. 4.9 × 10–13 M
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Hard
Gradable: automatic
Subtopic: Predicting Precipitation Reactions (Q vs. Ksp)
Topic: Solubility
100. The concentration of the complex ion in each of following solutions is 1.00 M. In which of the solutions will the concentration of the uncomplexed metal ion be the greatest?
Hg(CN)42– Kf = 9.3 × 1038
Be(OH) 42– Kf = 4.0 × 1018
Zn(OH) 42– Kf = 3.0 × 1015
Cu(NH3)42+ Kf = 5.6 × 1011
CdI42– Kf = 1.0 × 106
A. Hg2+
B. Be2+
C. Zn2+
D. Cu2+
E. Cd2+
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Complex Ion Equilibrium
Topic: Solubility
101. Calculate the solubility of zinc hydroxide, Zn(OH)2, in 1.00 M NaOH.
Ksp = 3.0 × 10–16 for Zn(OH)2, Kf = 3.0 × 1015 for Zn(OH)42–
A. 0.60 M
B. 0.52 M
C. 0.37 M
D. 0.32 M
E. 0.24 M
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Hard
Gradable: automatic
Subtopic: Complex Ion Equilibrium
Topic: Solubility
102. A solution is prepared by mixing 50.0 mL of 0.50 M Cu(NO3)2 with 50.0 mL of 0.50 M Co(NO3)2. Sodium hydroxide is added to the mixture. Which hydroxide precipitates first and what concentration of hydroxide ions present in solution will accomplish the separation?
Ksp = 2.2 × 10–20 for Cu(OH)2, Ksp = 1.3 × 10–15 for Co(OH)2
A. Co(OH)2; [OH–] = 6.9 × 10–6 M
B. Co(OH) 2; [OH–] = 2.6 × 10–7 M
C. Cu(OH) 2; [OH–] = 1.8 × 10–7 M
D. Cu(OH) 2; [OH–] = 1.1 × 10–9 M
E. Cu(OH) 2; [OH–] = 1.0 × 10–17 M
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Fractional Precipitation
Topic: Solubility
103. The salts X(NO3)2 and Y(NO3)2 (where X+ and Y+ are metal ions) are dissolved in water to give a solution which is 0.1 M in each of them. Using the Ksp values listed below, decide which aqueous reagent, if any, will definitely precipitate X+ before precipitating Y+ from solution.
Given Ksp values:
XCl2, 1 × 10–5 YCl2, 1 × 10–10 X(OH)2, 1 × 10–10 Y(OH)2, 1 × 10–5
A. 1 M NaCl
B. 1 M HCl
C. 1 M HNO3
D. 1 M NaOH
E. None of these choices are correct.
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Fractional Precipitation
Topic: Solubility
104. The salts X(NO3)2 and Y(NO3)2 (where X+ and Y+ are metal ions) are dissolved in water to give a solution which is 0.1 M in each of them. Using the Ksp values listed below, decide which aqueous reagent, if any, will definitely precipitate X+ before precipitating Y+ from solution.
Given Ksp values:
XCl2, 1 × 10–5 YCl2, 1 × 10–10 X(OH)2, 1 × 10–10 Y(OH)2, 1 × 10–5
A. 1 M NH3
B. 1 M HCl
C. 1 M HNO3
D. 1 M NaCl
E. None of these choices are correct.
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Fractional Precipitation
Topic: Solubility
105. The salts X(NO3)2 and Y(NO3)2 (where X+ and Y+ are metal ions) are dissolved in water to give a solution which is 0.1 M in each of them. Using the Ksp values listed below, decide which aqueous reagent, if any, will definitely precipitate X+ before precipitating Y+ from solution.
Given Ksp values:
XCl2, 1 × 10–5 YCl2, 1 × 10–10 X(OH)2, 1 × 10–10 Y(OH)2, 1 × 10–5
A. 1 M NaNO3
B. 1 M HCl
C. 1 M HNO3
D. 1 M NaCl
E. None of these choices are correct.
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Fractional Precipitation
Topic: Solubility
106. The salts X(NO3)2 and Y(NO3)2 (where X+ and Y+ are metal ions) are dissolved in water to give a solution which is 0.1 M in each of them. Which of the answers gives the concentration of chloride ions will precipitate the most YCl2 without precipitating any XCl2?
Given Ksp values: XCl2, 2 × 10–5 YCl2, 1 × 10–10
A. 1 M Cl–
B. 0.1 M Cl–
C. 0.01 M Cl–
D. 0.001 M Cl–
E. 0.0001 M Cl–
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Fractional Precipitation
Topic: Solubility
107. A CH3COOH/CH3COO– buffer can be produced by adding a strong acid to a solution of CH3COO– ions.
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
108. Increasing the concentrations of the components of a buffer solution will increase the buffer range.
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Easy
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
109. Increasing the concentrations of the components of a buffer solution will increase the buffer capacity.
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Easy
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
110. If the pH of a buffer solution is greater than the pKa value of the buffer acid, the buffer will have more capacity to neutralize added base than added acid.
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Medium
Gradable: automatic
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation)
Topic: Acids and Bases
111. The end point in a titration is defined as the point when the indicator changes color.
Accessibility: Keyboard Navigation
Bloom's: 1. Remember
Difficulty: Easy
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
112. The equivalence point in a titration is defined as the point when the indicator changes color.
Accessibility: Keyboard Navigation
Bloom's: 1. Remember
Difficulty: Easy
Gradable: automatic
Subtopic: Acid-Base Titrations and Indicators
Topic: Acids and Bases
113. For a diprotic acid H2A, the relationship Ka1 > Ka2 is always true.
Accessibility: Keyboard Navigation
Bloom's: 1. Remember
Difficulty: Medium
Gradable: automatic
Subtopic: Polyprotic Acids
Topic: Acids and Bases
114. The solubility of salt MX (solubility product constant Ksp) in water will always be greater than that of salt MX3 (solubility product constant K'sp) provided that Ksp > K'sp.
Accessibility: Keyboard Navigation
Bloom's: 2. Understand
Difficulty: Hard
Gradable: automatic
Subtopic: Solubility Product (Ksp)
Topic: Solubility
115.Calculate the molar solubility of silver carbonate in 1.0 M sodium carbonate solution. (Ksp for Ag2CO3 = 8.1 x 10-12)
A. 8.1 x 10-12 M
B. 2.8 x 10-6 M
C. 1.4 x 10-6 M
D. 1.4 x 10-8 M
E. 2.0 x 10-4 M
Accessibility: Keyboard Navigation
Bloom's: 3. Apply
Difficulty: Medium
Gradable: automatic
Subtopic: Solubility Product (Ksp)
Topic: Solubility
Category # of Questions
Accessibility: Keyboard Navigation 107
Bloom's: 1. Remember 8
Bloom's: 2. Understand 43
Bloom's: 3. Apply 64
Difficulty: Easy 28
Difficulty: Hard 18
Difficulty: Medium 69
Gradable: automatic 115
Subtopic: Acid-Base Titrations and Indicators 28
Subtopic: Buffer Solutions (Common Ion Effect and the Henderson-Hasselbalch Equation) 45
Subtopic: Complex Ion Equilibrium 2
Subtopic: Fractional Precipitation 5
Subtopic: Polyprotic Acids 1
Subtopic: Predicting Precipitation Reactions (Q vs. Ksp) 5
Subtopic: Solubility and Common Ion Effect 5
Subtopic: Solubility and pH 5
Subtopic: Solubility Product (Ksp) 19
Topic: Acids and Bases 74
Topic: Solubility 41
Document Information
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Chemistry Molecular Nature 8e Complete Test Bank
By Martin Silberberg
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